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HSC Stuff => HSC Science Stuff => HSC Subjects + Help => HSC Chemistry => Topic started by: hanyi on March 24, 2019, 07:39:10 pm

Title: stoichiometry
Post by: hanyi on March 24, 2019, 07:39:10 pm

calculate the mass of sodium carbonate (Na2CO3.10H2O) required to make 250mL of a 0.100 M solution.

thank you !!!

Title: Re: stoichiometry
Post by: fun_jirachi on March 24, 2019, 09:24:22 pm

Using c=n/V, we have that 250mL of a 0.1M solution has 0.0250 moles of Na₂CO₃. Finding that the molar mass of Na₂CO₃ is 105.988 g/mol, multiply the two together to get about 2.65g (3SF).

Hope this helps :)