ATAR Notes: Forum
VCE Stuff => VCE Mathematics => VCE Mathematics/Science/Technology => VCE Subjects + Help => VCE Mathematical Methods CAS => Topic started by: Fitness on November 07, 2007, 08:15:23 pm
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Ok there is this question in the itute 2006 trial exam 1. I can do part A and B ok. But I am stumped on why itute's answer is what it is for part C. It could be something obvious but I need to know what's going on with it.
(http://i180.photobucket.com/albums/x69/gourlaype/lolwtfidk.jpg)
Part A and B are easy. But for part C I put domain: R
Itute's answer is:
(http://i180.photobucket.com/albums/x69/gourlaype/lolwtfidkanswer.jpg)
Can anyone tell me why it's \{1}? I don't see why that isn't part of the domain... Why isn't x=1 differentiable? :?
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for that graph, y=|x^3-1|
theres a sharp turn, at where it meets the x-axis, the point(1,0)
its the pointy thing, you can see it from your graph.
at that point, you cannot find the gradient of it
hence dy/dx is not defined at x=1
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for that graph, y=|x^3-1|
theres a sharp turn, at where it meets the x-axis, the point(1,0)
its the pointy thing, you can see it from your graph.
at that point, you cannot find the gradient of it
hence dy/dx is not defined at x=1
Argh! I knew it was something simple!
Thanks heaps joechan521 :D
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ah yeh i did a question like this and i was totally like wtf why, but yeh tis cos of the pointy join. whatever they're called. cusp?
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ah yeh i did a question like this and i was totally like wtf why, but yeh tis cos of the pointy join. whatever they're called. cusp?
Yes a cusp. The funny thing is I leaned something about this and totally forgot! :wink: