Login

Welcome, Guest. Please login or register.

April 19, 2024, 08:21:19 pm

Author Topic: vector proofs  (Read 3044 times)  Share 

0 Members and 1 Guest are viewing this topic.

annie

  • Victorian
  • Trailblazer
  • *
  • Posts: 25
  • Respect: 0
vector proofs
« on: November 02, 2008, 06:48:50 pm »
0
Hi guys i was just doing some trial exams for spesh paper 1, and i came across a vector proof question on my 9th paper  :o

it was something like prove that OACB is a Rhombus
given that AB is perpendicular to OC

and it stumped me because i don't know the prequisite conditions in order to prove that something is a shape

can someone tell me a general list of what 'shapes' i should know and their prequisites??

eg. rhombus - must have 4 equal sides etc??

thanks alot

Mao

  • CH41RMN
  • Honorary Moderator
  • Great Wonder of ATAR Notes
  • *******
  • Posts: 9181
  • Respect: +390
  • School: Kambrya College
  • School Grad Year: 2008
Re: vector proofs
« Reply #1 on: November 02, 2008, 07:30:34 pm »
0
parallelogram - one pair of opposite sides are parallel and same magnitude
rectangle - parallelogram + one right angle
rhombus - four equal sides
square - rhombus + one right angle

[the triangles are pretty self explanatory]
« Last Edit: November 07, 2008, 02:45:02 pm by Mao »
Editor for ATARNotes Chemistry study guides.

VCE 2008 | Monash BSc (Chem., Appl. Math.) 2009-2011 | UoM BScHon (Chem.) 2012 | UoM PhD (Chem.) 2013-2015

trinon

  • Victorian
  • Forum Obsessive
  • ***
  • Posts: 240
  • Respect: +5
Re: vector proofs
« Reply #2 on: November 02, 2008, 08:12:32 pm »
0
Refer to image attached.

Isn't it that if you can prove that OB.AC = 0, it's a rhombus?
Eli rocks at running.

ice_blockie

  • Victorian
  • Forum Obsessive
  • ***
  • Posts: 312
  • Respect: +6
Re: vector proofs
« Reply #3 on: November 02, 2008, 08:21:39 pm »
0
Refer to image attached.

Isn't it that if you can prove that OB.AC = 0, it's a rhombus?

In short no. Draw a kite and then you will see why...