ATAR Notes: Forum
VCE Stuff => VCE Mathematics => VCE Mathematics/Science/Technology => VCE Subjects + Help => VCE Mathematical Methods CAS => Topic started by: TrueTears on February 28, 2009, 11:32:01 pm
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um just a small Q say you got a q saying "List the appropriate sequence of transformations that maps
to
"
so here obviously
is the image and u re-arrange that to make it similar to
, ie  = \sqrt{3x'+5})
then just equate
and
and etc etc
but say another q says "List the appropriate sequence of transformations that maps
to
" Do i do the same thing here? ie,
is now the image ? But how do u re-arrange the image to fit the given equation? Or do you re-arrange the given equation to fit the image?
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wat my teacher taught me is to "undo" the things. I always followed a certain sequence for transformations. so in this case, just do the opposite; reverse the translations, then undo the reflections then undo the dilations. so i think it's:
Shift of 1unit up
Shift of
units left
Dilate by a factor of
from the x-axis
Dilate by a factor of
from y-axis
The dilation parts is equivalent to
from the x-axis
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yeah, thanks
but how would you do this algebraically?
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hmmm did i get it right? algebraically eh?...give me a bit coz i don't like using mapping notation. can never seem to make it work.
haha i think i've got it:
let y=6...be the original. y=1/x^2 be the image --> y'=1/(x')^2
so y=(3/2)/(x-.5)^2 -1
(2/3)(y+1)=y'
so it's clear that there is:
a translation of 1 up, dilation of 2/3 from the x
the x part is similar. hope it makes sense.
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learning how to do it using mapping notation is pointless and wastes a lot of time too.
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well learning mapping notation is not all pointless because it develops the understanding necessary for using a "shortcut". but yes, it's a big waste of time. =]
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thanks i get it now.