ATAR Notes: Forum

VCE Stuff => VCE Mathematics => VCE Mathematics/Science/Technology => VCE Subjects + Help => VCE Specialist Mathematics => Topic started by: sophie.tran999 on August 01, 2011, 05:47:57 pm

Title: DIFFERENTIAL EQUATION
Post by: sophie.tran999 on August 01, 2011, 05:47:57 pm
Can anyone help me with this question, i get stuck with a)
Q: in a certain bacterial culture, the rate of increse is proportional to the number of bacteria present.
a) if the number doubles in 3 hours, find the hourly growth rate.
i can deal with b) and c).
Title: Re: DIFFERENTIAL EQUATION
Post by: b^3 on August 01, 2011, 06:21:45 pm
Let N represent the number of bacteria present
let t represent time
then
so at t=0 lets start of with n Bacteria
then at t=3, N=2n
solve the differential equation
flip it


solve for c, plug in t=0, and N=n
so
so the hourly growth rate will be k
so plug in t=3 and N=2n



So the hourly growth rate is

Wait I'm still wrong
Title: Re: DIFFERENTIAL EQUATION
Post by: sophie.tran999 on August 01, 2011, 06:24:11 pm
thx, thats wat i did afetr readin the question 1st time, but look, the question askes to find the GROWTH RATE, not find t in term of N :D
the anwser is : dN/dt = 0.23N
Title: Re: DIFFERENTIAL EQUATION
Post by: b^3 on August 01, 2011, 06:29:14 pm
1/3loge(2)=0.23 so that means that dN/dt=0.23N, I think that answers it right?
Title: Re: DIFFERENTIAL EQUATION
Post by: b^3 on August 01, 2011, 06:30:18 pm
since growth rate =dN/dt
Title: Re: DIFFERENTIAL EQUATION
Post by: sophie.tran999 on August 01, 2011, 06:32:31 pm
i think so. damn me lol
thx
Title: Re: DIFFERENTIAL EQUATION
Post by: b^3 on August 01, 2011, 06:33:14 pm
Yeh it's right and works, I had myself stuck in a loop for a min there.
Title: Re: DIFFERENTIAL EQUATION
Post by: sophie.tran999 on August 01, 2011, 06:34:09 pm
solve for c, plug in t=0, and N=n, this is important part. i missed this one
instead od plugging t=0 and N=o first, i just pluged t=3 and N=2N. :(