ATAR Notes: Forum

VCE Stuff => VCE Mathematics => VCE Mathematics/Science/Technology => VCE Subjects + Help => VCE Specialist Mathematics => Topic started by: david10d on October 07, 2011, 11:54:16 pm

Title: QUESTION
Post by: david10d on October 07, 2011, 11:54:16 pm

just doing my first exam 2 to see where i'm at atm.


see VCAA 2006 exam 2

question 1e (find dA/dt). can someone explain this to me please? it seems so simple but i can't work it out =/ wtf


also what the fuck at these cunts not putting out solutions? lazy pricks



cheers

Title: Re: QUESTION
Post by: vea on October 07, 2011, 11:58:16 pm

A=piy^2
dA/dy=2pi y
use chain rule dA/dt=dA/dy x dy/dt
=24pix(6-3x^3)/91+x^3)^2

Title: Re: QUESTION
Post by: david10d on October 08, 2011, 12:03:35 am

Quote from: vea on October 07, 2011, 11:58:16 pm

A=piy^2
dA/dy=2pi y
use chain rule dA/dt=dA/dy x dy/dt
=24pix(6-3x^3)/91+x^3)^2

zzz

cheers dude