ATAR Notes: Forum
Archived Discussion => Mathematics => 2011 => End-of-year exams => Exam Discussion => Victoria => Mathematical Methods CAS => Topic started by: adamclarke on November 08, 2011, 11:08:18 am
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How did you all find Methods Exam 1?
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shit
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destroyed it!
Answers i can remember:
P=3/4
Pr(X<3.5)= 5/8
Pr(X<2|X<3.5)= 3/5
4^x-15*2^x=16 solve for x, x=4
solve for m and a; m=4 and a=8
f(g(x))= square root of (x+8)(x+2)
domain (-infinity, -8] U [-2, infinity]
same anyone?
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http://www.itute.com/board/viewtopic.php?f=2&t=2447&sid=259dce1ff982b4d0016137a210b2bd07
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Yeah got the same, pretty sure i got everything right except
Last question man ....
got the right method but did 2a/a = a instead of 2.... so stupid of me, if my memory is correct the shorter side is meant to be 1 and the longer side is 2.
I got 1 and some root number because i stuffed up 2a/a...... No methods marks either -___-
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yeah last question i got that wrong as well, so silly
Hopefully the only mark we lost :)
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Got all of them (unless I did silly mistakes) except the last question which threw me off because it was only worth 1 mark.
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I am so so glad I decided to not do maths in Year 12 and pick it back up from the beginning at uni :P
My mates called me stupid... but I bet they're not laughing now!
On a more positive note, remember this exam was only worth 22%, so don't agonise too much about how you went. Instead utilise these last hours so you can redeem yourself in the truly important methods exam :)
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Awful.
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Is {x: x E (-infinity, -8] U [-2, infinity]} the same as {x: x E R\(-8.-2)}?
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Yeah that is the same ! ;D
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10d. max L = 9 +3root5 or 19 + 3root5 ?
and underneath a sqroot > 0 or >= 0. I put > does that mean 1 mark lost?
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how do you do the last Q10d?
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destroyed it!
Answers i can remember:
P=3/4
Pr(X<3.5)= 5/8
Pr(X<2|X<3.5)= 3/5
4^x-15*2^x=16 solve for x, x=4
solve for m and a; m=4 and a=8
f(g(x))= square root of (x+8)(x+2)
domain (-infinity, -8] U [-2, infinity]
same anyone?
yes i got that too, lets hope its right
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I am so so glad I decided to not do maths in Year 12 and pick it back up from the beginning at uni :P
My mates called me stupid... but I bet they're not laughing now!
On a more positive note, remember this exam was only worth 22%, so don't agonise too much about how you went. Instead utilise these last hours so you can redeem yourself in the truly important methods exam :)
Well all up it's worth more because it affects your sac marks.
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Didn't use my time efficiently. Spent too long on each question and didn't have enough time to check over and now realised that I made heaps of silly mistakes.
Hopefully scrape an A+ considering everyone else found it hard as well.
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Didn't use my time efficiently. Spent too long on each question and didn't have enough time to check over and now realised that I made heaps of silly mistakes.
Hopefully scrape an A+ considering everyone else found it hard as well.
dont worry I will help boost your score
from my performance today
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Hi everyone, for the question about domain f(g(x)), I got (- infinity, -8] and [3, + infinity)
My reason: I also got (- inf, -8] and [-2, inf). But the problem is Dom f(g(x)) = intersection of f(x) and g(x). Domain of f(x) is (-inf, -3] and [3, + inf). Therefore, dom f(g(x) should also be in that range.. Therefore, I got my above result.
Is that wrong?? I'm quite worried :<
ANd for question 2: find an antiderivative. I have "+c" after my antiderivative. Is it acceptable?
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destroyed it!
Answers i can remember:
P=3/4
P ALSO EQUALS 0!!!
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i rejected p=0 as a solution can't remember exactly why, does anyone have a copy of the exam i can't remember much so its difficult to say what i got, i think around 25-30 :(
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destroyed it!
Answers i can remember:
P=3/4
P ALSO EQUALS 0!!!
Are you sure? that would mean that Pr(Head) = 0 and Pr(Tail) = 1
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I said p=0 too, it did say it was a biased coin!
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destroyed it!
Answers i can remember:
P=3/4
P ALSO EQUALS 0!!!
Are you sure? that would mean that Pr(Head) = 0 and Pr(Tail) = 1
It was a biased coin
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destroyed it!
Answers i can remember:
P=3/4
P ALSO EQUALS 0!!!
Are you sure? that would mean that Pr(Head) = 0 and Pr(Tail) = 1
It was a biased coin
GG theres another mark
EDIT: How are we supposed to get 2 Heads and 1 Tail then?
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for 4^x- 15x2^x= 16 i wrote the answer as log2(16) which does = 4
do you reckon they would still mark that right?
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Yes, but logically, how can their be a coin with inifintite chance?
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destroyed it!
Answers i can remember:
P=3/4
P ALSO EQUALS 0!!!
p can't equal 0 ..... dickhead
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for 4^x- 15x2^x= 16 i wrote the answer as log2(16) which does = 4
do you reckon they would still mark that right?
yes you will get that mark :)
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If p=0, then it is not probability any more as it's outcome would be determined before you tried?