ATAR Notes: Forum
VCE Stuff => VCE Mathematics => VCE Mathematics/Science/Technology => VCE Subjects + Help => VCE Mathematical Methods CAS => Topic started by: mano91 on August 20, 2012, 06:48:42 pm
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Two letters are selected from the word BIRD.
What is the probability that the second letter is a vowel or that the first letter is a D?
Using a tree diagram, it is obvious to see that the answer is 4/12 = 1/3. (BI,RI, DI, DR.)
But how come applying the addition rule: Pr (D U Vowel) = pr(d) + pr(vowel) - pr( D and Vowel ) doesn't work?
unless i am applying it wrong... thanks!
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Hrm, shouldn't it be BI RI DI DB DR?
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no because DI is the intersection of the two events, we were asked for D or a vowel
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'Or' is inclusive.
EDIT: I mean wait what. Why don't you include DB?
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ahh, the solution to the question is wrong! which means that the addition rule can be applied correctly
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thanks buddy :)
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The reason you subtract the intersection is because you'd count it twice otherwise -- not because it shouldn't be included.