ATAR Notes: Forum
VCE Stuff => VCE Mathematics => VCE Mathematics/Science/Technology => VCE Subjects + Help => VCE General & Further Mathematics => Topic started by: Odette on November 02, 2007, 02:27:03 pm
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Hey everyone, I just wanted to let you all know that if any of you need help with further, just let me know, just post your question(s) here and I'll help you with it :)
:D
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ahhh i may take you up on that offer this weekend :D
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ahhh i may take you up on that offer this weekend :D
Sure thing :)
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could you plz explain Q9 2006 exam 1 Geo + Trig
only qn i got wrong in that exam :x
i initialy thought it would be an isoceles but realised it cant be...
edit: also do you have the answers for the 2006 sample? or can u post what u got so i can compare (aparently they dont make answers for VCAA sample exams)
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could you plz explain Q9 2006 exam 1 Geo + Trig
only qn i got wrong in that exam :x
i initialy thought it would be an isoceles but realised it cant be...
edit: also do you have the answers for the 2006 sample? or can u post what u got so i can compare (aparently they dont make answers for VCAA sample exams)
Um I don't do geo and trig sorry... i suck at bearings lol
As for the sample I havent done it just yet... I'll do it asap :)
http://itute.com/mathline/2006_vcaa_fm_exam1_sol.pdf
They show you how to work out Qn 9
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thanks... yeh im just about to start the 06 sample too, internet is too distracting lol
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thanks... yeh im just about to start the 06 sample too, internet is too distracting lol
Tell me about it lol... i'll probably work on exams later today, i think better at night :P lol
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k so i did them..
Core:
A, B, B, B, C
Geo:
D, C, C,
Bus Math:
D, C, B,
Networks:
B, A
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could you plz explain Q9 2006 exam 1 Geo + Trig
only qn i got wrong in that exam :x
i initialy thought it would be an isoceles but realised it cant be...
edit: also do you have the answers for the 2006 sample? or can u post what u got so i can compare (aparently they dont make answers for VCAA sample exams)
draw the diagram
its basicly like this
| ---------------M
|
|
|
O
|
|
|
| ----------P
therefore the bearing of P from M is between 180 to 270
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Okay Odette, here is your chance to help me out.
I just did the VCAA 2006 paper (part 1) and got 36/40.
The questions I got wrong were...
Core - Q10
Number Patterns - Q6, Q9
Matrices - Q7
No questions incorrect for graphs, which is comforting.
So... if you could guide me through those questions it would much appreciated, thanks!
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k so i did them..
Core:
A, B, B, B, C
Geo:
D, C, C,
Bus Math:
D, C, B,
Networks:
B, A
I did the core,geo, and bus man, i dont do networks ...
I got:
Core-
A,B,B,B,C
Geo-
A,C,C
Bus-
D,C,B
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joechan521 i think i got it,
becuase P is 152T its 62 past 90 where as M is 52 behind 90 (imagine 90 as being perpendicular with O) so that means P is closer to the vertical and M more 'further out' given there the same length..
i just had problem on which would be futher out the M or the P, geting the bearings from that is easy, thanks!
edit: oddete
i dont see how u got C for q4,core... did u do .5675 x (67.98/8.67) ??
and geo q1, x = 34.6/tan(23) ??
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Okay Odette, here is your chance to help me out.
I just did the VCAA 2006 paper (part 1) and got 36/40.
The questions I got wrong were...
Core - Q10
Number Patterns - Q6, Q9
Matrices - Q7
No questions incorrect for graphs, which is comforting.
So... if you could guide me through those questions it would much appreciated, thanks!
CORE 10
its asking for april
so therefore you get 3 data from march april and may which are 35,99,75
find the average [35+99+75]/3 about 70 therefore C
MATRIX 7
many ways to do it
graph the 2 equations
if they intersect = a unique solution
2 parallel lines = no unique solution
or other way to do it.
rearange the 2 equations in y=mx+c form
if same gradient = no unique solution
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Thanks joechan... added them in my 'notes' part of the textbook. Now for those number pattern ones Odette =]
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Okay Odette, here is your chance to help me out.
I just did the VCAA 2006 paper (part 1) and got 36/40.
The questions I got wrong were...
Core - Q10
Number Patterns - Q6, Q9
Matrices - Q7
No questions incorrect for graphs, which is comforting.
So... if you could guide me through those questions it would much appreciated, thanks!
Ok well I'm not too sure about the matrices question, but I can help you with the others...
CORE-
10. C
35+95+75=205
205/3=68.333
which is closest to 70
Number Patterns-
6. E
t15=12 x 1.03 ^14
t15=18.2
9.E
S∞ = a/1-r , a=0.4, r= 0.95
S∞ = 0.4/1-0.95
= 8
=> 73.4 + 8
= 81.4
Sorry about that...
Hope the others make sense, if they don't let me know
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joechan521 i think i got it,
becuase P is 152T its 62 past 90 where as M is 52 behind 90 (imagine 90 as being perpendicular with O) so that means P is closer to the vertical and M more 'further out' given there the same length..
i just had problem on which would be futher out the M or the P, geting the bearings from that is easy, thanks!
edit: oddete
i dont see how u got C for q4,core... did u do .5675 x (67.98/8.67) ??
and geo q1, x = 34.6/tan(23) ??
Sorry, made a mistake on Q4 of Core...
As for the Geo Q1=> I think it's tan 23=x/34.6 (depression not elevation) Could be wrong though :S lol
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yeah this is completely testing my brain capacity
i just spent an hour finding the residual button
i already knew where it was
but now i am stressing haha
i hate residual plots
i dislike calculators because they don't do what i try to get them to do
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yeah this is completely testing my brain capacity
i just spent an hour finding the residual button
i already knew where it was
but now i am stressing haha
i hate residual plots
i dislike calculators because they don't do what i try to get them to do
Lol...
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yeah really not looking forward to this
not to mention i have a nagging little brother pestering me every 5 minutes
not the best place to try and study, at home
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joechan521 i think i got it,
becuase P is 152T its 62 past 90 where as M is 52 behind 90 (imagine 90 as being perpendicular with O) so that means P is closer to the vertical and M more 'further out' given there the same length..
i just had problem on which would be futher out the M or the P, geting the bearings from that is easy, thanks!
edit: oddete
i dont see how u got C for q4,core... did u do .5675 x (67.98/8.67) ??
and geo q1, x = 34.6/tan(23) ??
Sorry, made a mistake on Q4 of Core...
As for the Geo Q1=> I think it's tan 23=x/34.6 (depression not elevation) Could be wrong though :S lol
hmm, did u measure from the horizontal, then using co interior angles, 23 will be bottom right angle (hard to explain w/o drawing) so opp=34.6 and adj=x
TOA => tan(23) = 34.6/x
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joechan521 i think i got it,
becuase P is 152T its 62 past 90 where as M is 52 behind 90 (imagine 90 as being perpendicular with O) so that means P is closer to the vertical and M more 'further out' given there the same length..
i just had problem on which would be futher out the M or the P, geting the bearings from that is easy, thanks!
edit: oddete
i dont see how u got C for q4,core... did u do .5675 x (67.98/8.67) ??
and geo q1, x = 34.6/tan(23) ??
Sorry, made a mistake on Q4 of Core...
As for the Geo Q1=> I think it's tan 23=x/34.6 (depression not elevation) Could be wrong though :S lol
hmm, did u measure from the horizontal, then using co interior angles, 23 will be bottom right angle (hard to explain w/o drawing) so opp=34.6 and adj=x
TOA => tan(23) = 34.6/x
No no um it was A=34.6 O=x lol ...
23 degrees (*)
*
|\
34.6 | \
|__\
x
If that makes sense lol ..
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(http://i71.photobucket.com/albums/i127/retroflector/aaaaaaaaaa.jpg)
edit: ur measuring the angle of depresion wrong, it has to be measured FROM THE HORIZONTAL :)
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(http://i71.photobucket.com/albums/i127/retroflector/aaaaaaaaaa.jpg)
edit: ur measuring the angle of depresion wrong, it has to be measured FROM THE HORIZONTAL :)
Oh i see ... lol
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Thanks for the help on the last questions... I just have 2 more questions.
Further maths exam (VCAA) '05
Core - Q10
Graphs - Q9
Thanks for any assistance!
Edit: I am doing the further vcaa exams '02 to '04 right now so if I come across anymore 'tricky' ones I'll post them up, begging for help. :P
Double Edit: Does anyone have any 'commercial' modules (other than neap and itute) for matrices? I feel like doing just 2 or 3 modules of that isn't enough. Ta!
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Thanks for the help on the last questions... I just have 2 more questions.
Further maths exam (VCAA) '05
Core - Q10
Graphs - Q9
Thanks for any assistance!
Edit: I am doing the further vcaa exams '02 to '04 right now so if I come across anymore 'tricky' ones I'll post them up, begging for help. :P
Double Edit: Does anyone have any 'commercial' modules (other than neap and itute) for matrices? I feel like doing just 2 or 3 modules of that isn't enough. Ta!
Can you like post the questions because vcaa site isnt working atm ... ?
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CORE-
Qn 10-
B. x-points : 1,2,3,4,5 => median is 3
y-points : 0,1,2,4,5 => median is 2
coordinates: (3,2)
GRAPHS-
Qn 9-
A. I= k/d^2
20 x 50^2 =k
50000 =k
(5,2000) => 2000=k/5^2
50000=k
Therefore the coordinates satisfy the equation (hope that makes sense)
Hope that helps sorry about the delay, I only got the VCAA 05 Exam :P
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Can we take in potractors?
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For the matrices question, we know that a unique solution is when the determinant does not equal to 0.
x=8,y=2 is a unique solution as they have already told us that x is 8 and y is 2 thus no need to apply the rule (det=ad-bc)
I think thats right?
i got question 9 wrong (2006 VCAA-matrices). if you put the values into the calc T^50, T^60 etc the figures keeps on increasing so shouldn't the answer be E-gradually increases?
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Is the trial exam (2007) from itute meant to be hard? vcaa exams will generally be of a lower standard (in terms of difficulty) than commercial papers?
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Is the trial exam (2007) from itute meant to be hard? vcaa exams will generally be of a lower standard (in terms of difficulty) than commercial papers?
VCAA exams are easier than most commercial papers :)
I think you can bring in a protractor, not sure though =]
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did they say last year's exam is easy? u reckon this yr's going to b pretty much the same or harder?
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did they say last year's exam is easy? u reckon this yr's going to b pretty much the same or harder?
Well I don't know how easy/hard it will be, but it cant be harder than the commercial ones
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hmm lets hope it'll b alright. best of luck to you and to all our fellow free study notes further peeps :)
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hmm lets hope it'll b alright. best of luck to you and to all our fellow free study notes further peeps :)
Thanks you too =]
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One last question guys.
Q7 Numbers and Patterns.
A shrub, 20 cm high, was planted in a pot. After it was planted in the pot its height increased by 8cm in the first month, by 4cm in the second month and by 2cm in the third momnth.' Assuming this pattern of growth continues... the max height the shrub will grow to is?
Correct answer: B) 36cm
I got 40, using the a/1-r, assuming r was 0.5 and a was 20?
Hopefully someone can clear this up before they go!
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One last question guys.
Q7 Numbers and Patterns.
A shrub, 20 cm high, was planted in a pot. After it was planted in the pot its height increased by 8cm in the first month, by 4cm in the second month and by 2cm in the third momnth.' Assuming this pattern of growth continues... the max height the shrub will grow to is?
Correct answer: B) 36cm
I got 40, using the a/1-r, assuming r was 0.5 and a was 20?
Hopefully someone can clear this up before they go!
A is actually 8, as its the "FIRST MONTH", so using that you would get 16. 16 +20 = 36
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A is actually 8, as its the "FIRST MONTH", so using that you would get 16. 16 +20 = 36
Cheers. I've now made that mistake a few times and I shouldn't now. GL!
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One last question guys.
Q7 Numbers and Patterns.
A shrub, 20 cm high, was planted in a pot. After it was planted in the pot its height increased by 8cm in the first month, by 4cm in the second month and by 2cm in the third momnth.' Assuming this pattern of growth continues... the max height the shrub will grow to is?
Correct answer: B) 36cm
I got 40, using the a/1-r, assuming r was 0.5 and a was 20?
Hopefully someone can clear this up before they go!
A is actually 8, as its the "FIRST MONTH", so using that you would get 16. 16 +20 = 36
Yeah that's right =] well done dxb =]
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GOOOOOOOOOOOOOOOOOOOOD LUUUUUUUUUUUUUUUUUUUUCK GUYS AND GIRLS !!
1hr and 40 mins til the exam!!!
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Half an hour!