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VCE Stuff => VCE Mathematics => VCE Mathematics/Science/Technology => VCE Subjects + Help => VCE Mathematical Methods CAS => Topic started by: naved_s9994 on June 16, 2009, 06:02:54 pm

Title: Diff problem
Post by: naved_s9994 on June 16, 2009, 06:02:54 pm: Attached.
Title: Re: Diff problem
Post by: Mao on June 16, 2009, 06:37:26 pm: $\frac{dy}{dx} | _{x=1} = -2(2x-1)^{-3}\cdot 2 = -4$

$y(1) = 1$

$\implies y_t - 1 = -4(x - 1) \implies y = -4x +5$
Title: Re: Diff problem
Post by: naved_s9994 on June 16, 2009, 07:08:05 pm: thx mao, karma donate :P
Title: Re: Diff problem
Post by: Davoo! on June 16, 2009, 11:09:10 pm: You can also use the quotient rule but the way Mao's done it is just a lot simpler.