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VCE Stuff => VCE Science => VCE Mathematics/Science/Technology => VCE Subjects + Help => VCE Chemistry => Topic started by: naved_s9994 on August 19, 2009, 08:19:43 pm

Title: Concentration - Volumetric Analysis
Post by: naved_s9994 on August 19, 2009, 08:19:43 pm: Hey guys,
Wondering if anyone can help?

Convert the molar concentration to units of g L ^-1 :

0.0024M NaCl solution

Can anyone work this out :'(
Thanks!
Title: Re: Concentration - Volumetric Analysis
Post by: monokekie on August 19, 2009, 08:28:07 pm: :'(
sry i suck at explaining.

but here's my working.
0.0024 x ( 23+35.5) = something g L^-1
Title: Re: Concentration - Volumetric Analysis
Post by: /0 on August 19, 2009, 08:40:31 pm: $0.0024M = 0.0024\left(\frac{mol}{L}\right)=0.0024\left(\frac{mol}{L}\right)\left(\frac{(23+35.5)g}{mol}\right) = 0.0024(23+35.5)gL^{-1}$

Whenever you're stuck with units you can resort to canceling out units like this
Title: Re: Concentration - Volumetric Analysis
Post by: lukeperry91 on August 19, 2009, 08:45:38 pm: Consider this solution to have a volume of one litre:
n=cv
n=0.0024
m=nM
m=0.0024*(23+35.5)
m=0.1404g (in one litre)
Therefore, the concentration equals 0.1404gL^-1
Title: Re: Concentration - Volumetric Analysis
Post by: naved_s9994 on August 19, 2009, 09:11:15 pm: ahh thanks everyone.
soo thankful !!