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VCE Stuff => VCE Mathematics => VCE Mathematics/Science/Technology => VCE Subjects + Help => VCE Specialist Mathematics => Topic started by: dodgedanpei on September 11, 2009, 10:04:55 pm

Title: A Kinematics Question
Post by: dodgedanpei on September 11, 2009, 10:04:55 pm

(http://img22.imageshack.us/img22/7255/fsadgfads.jpg)

Please post solution. Thanks in advance.

Title: Re: A Kinematics Question
Post by: mark_alec on September 11, 2009, 10:17:40 pm

A
0 = 20 - 4t. Solve for t.
distance = 1/2(20+0)*t (area under velocity time graph is a triangle)