Post by: Aqualim on September 21, 2009, 09:50:15 am
I'm having a bit of trouble with the question attached below.
By the way the equation for the sine graph is; 2sin(3x)+2
I'm thinking that for question (f) that i would just type the equation into the CAS calc under the derivitive function and get an answer, i think i was 6cos(3x) or something.
OR
Do I draw the graph of the original function, then mark a tangent point at pi/3, and write down the equation of that point
Post by: cobby on September 21, 2009, 10:36:07 am
Hey,It says find the gradient at that point, so I assume you wouldn't have to show it on the graph itself. Just plug it into the calculator and state the answer.
I'm having a bit of trouble with the question attached below.
By the way the equation for the sine graph is; 2sin(3x)+2
I'm thinking that for question (f) that i would just type the equation into the CAS calc under the derivitive function and get an answer, i think i was 6cos(3x) or something.
OR
Do I draw the graph of the original function, then mark a tangent point at pi/3, and write down the equation of that point
Post by: Aqualim on September 21, 2009, 10:53:21 am
would it just be;
Post by: Flaming_Arrow on September 21, 2009, 10:54:20 am
alright cheers, also for question (g)
would it just be;
since the gradient is negative
180 - tan^-1(6)
Post by: Aqualim on September 21, 2009, 10:59:02 am
alright cheers, also for question (g)
would it just be;
since the gradient is negative
180 - tan^-1(6)
wouldn't it also be included in the 4th quadrant, instead of just the 2nd?
Post by: Flaming_Arrow on September 21, 2009, 11:36:34 am
alright cheers, also for question (g)
would it just be;
since the gradient is negative
180 - tan^-1(6)
wouldn't it also be included in the 4th quadrant, instead of just the 2nd?
na, in this case you want the angle that the line makes with the POSITIVE x axis