Post by: Joseph41 on November 03, 2017, 01:56:10 pm
Congratulations - Further done!
What did you think? Register for a free account to share your thoughts below!
Ask your questions here!
Post by: brady_price on November 03, 2017, 03:48:52 pm
Suggested Answers
(anything starred is subject to change)
Core:
Spoiler
Q1. D
Q2. B
Q3. D
Q4. D
Q5. B
Q6. E
Q7. E
Q8. B
Q9. A
Q10. A
Q11. D
Q12. D
Q13. B
Q14. D
Q15. D
Q16. A
Q17. A
Q18. D
Q19. C
Q20. D
Q21. E
Q22. B
Q23. D
Q24. B
Q2. B
Q3. D
Q4. D
Q5. B
Q6. E
Q7. E
Q8. B
Q9. A
Q10. A
Q11. D
Q12. D
Q13. B
Q14. D
Q15. D
Q16. A
Q17. A
Q18. D
Q19. C
Q20. D
Q21. E
Q22. B
Q23. D
Q24. B
Matrices:
Spoiler
Q1. B
Q2. E
Q3. C
Q4. C
Q5. A
Q6. D
Q7. A
Q8. A
Q2. E
Q3. C
Q4. C
Q5. A
Q6. D
Q7. A
Q8. A
Networks:
Spoiler
Q1. B
Q2. C
Q3. A
Q4. D
Q5. C
Q6. E
Q7. D
Q8. B
Q2. C
Q3. A
Q4. D
Q5. C
Q6. E
Q7. D
Q8. B
Geometry and Measurement:
Spoiler
Q1. D
Q2. D
Q3. B
Q4. B
Q5. C
Q6. B
Q7. E*
Q8. A*
Q2. D
Q3. B
Q4. B
Q5. C
Q6. B
Q7. E*
Q8. A*
Graphs and Relations:
Spoiler
(Contributed by Deanator71)
Subject to change:
Q1. B
Q2. C
Q3. B
Q4. E
Q5. D
Q6. C
Q7. C
Q8. D
Subject to change:
Q1. B
Q2. C
Q3. B
Q4. E
Q5. D
Q6. C
Q7. C
Q8. D
Post by: Joseph41 on November 03, 2017, 03:55:27 pm
Post by: fish99 on November 03, 2017, 04:23:41 pm
Post by: ayri1234 on November 03, 2017, 04:33:42 pm
Post by: larz1203 on November 03, 2017, 04:34:51 pm
Could someone help me as to why Q14 answer is D?
Because it's a 7-median smoothed maximum wind speed, you take the data point for the 4th day and 3 days before and after that. That means that the one in the middle, vertically, is the data point for day 1 which is ~30
That being said, I have another question. In the last question for matrices, I got A as my answer. For my calculations, V=0.7; W=0.1; X=0.5;Y=0.6 and Z=0.2. Therefore W (0.1) isn't bigger than Z (0.2). Or did I make a mistake?😞
Post by: VIRTUP on November 03, 2017, 04:37:13 pm
Post by: fish99 on November 03, 2017, 04:40:06 pm
Because it's a 7-median smoothed maximum wind speed, you take the data point for the 4th day and 3 days before and after that. That means that the one in the middle, vertically, is the data point for day 1 which is ~30yep - i plused 3points before the 4th day (including the 4th day) and 3 points after that... and then divided by 7 = approx 32....... what did I do wrong?
Post by: bethany.north on November 03, 2017, 04:40:14 pm
Post by: iBennyz on November 03, 2017, 04:40:31 pm
X=0.5
Y=0.6
V=0.7
W=0.1
Z=0.2
Put the transformation matrix and multiply for S0, you'll get the S1 matrix given.
A. W>Z = 0.1 > 0.2 (Not true)
Post by: Khold on November 03, 2017, 04:41:53 pm
Could someone help me as to why Q14 answer is D?
Day 1's value (30) is the middle-most of the 6 other points surrounding and including Day 4, meaning that 3 of the other points are above it and the remaining 3 below it
Shouldn't question 8 be D? (Core)
Yeah that's what I got
Post by: Schmidt on November 03, 2017, 04:42:50 pm
calculations should show that V = 0.7, W = 0.1, X = 0.5, Z = 0.2 and Y = 0.6
Because 0.1 is not greater than 0.2, A is the answer.
Post by: sertani on November 03, 2017, 04:44:07 pm
Shouldn't question 8 be D? (Core)
look at the x axis. Its from point 21 not 0 so the y axis intercept cant be 17.4
Post by: brady_price on November 03, 2017, 04:44:23 pm
Shouldn't question 8 be D? (Core)
Y-intercept is where x = 0
Post by: Schmidt on November 03, 2017, 04:45:32 pm
Shouldn't question 8 be D? (Core)
The x-axis starts at 21 on the image of the graph, meaning the y-intercept cannot be 17.4 as it appears in the provided image. Answer is B
Post by: CarrymetoUni on November 03, 2017, 04:46:20 pm
Post by: ayri1234 on November 03, 2017, 04:48:24 pm
Y-intercept is where x = 0
I realised my mistake :(
Thanks
Post by: NoNeedToBeMad_ on November 03, 2017, 04:49:17 pm
Post by: larz1203 on November 03, 2017, 04:51:11 pm
yep - i plused 3points before the 4th day (including the 4th day) and 3 points after that... and then divided by 7 = approx 32....... what did I do wrong?
That's MEAN smoothing, not MEDIAN
Post by: SMOKIE on November 03, 2017, 04:51:39 pm
Shouldn't Q13 be E as the data value for day 21 is higher than the data value of day 1, so therefore it should have irregular fluctuations with an increasing trend.Yeah i put down E aswell
Post by: CarrymetoUni on November 03, 2017, 04:51:49 pm
Shouldn't Q13 be E as the data value for day 21 is higher than the data value of day 1, so therefore it should have irregular fluctuations with an increasing trend.I applied the same reasoning as you and got E as well.
Post by: fish99 on November 03, 2017, 04:56:03 pm
That's MEAN smoothing, not MEDIANohh ok (misread that) - thanks 🙂
Post by: Schmidt on November 03, 2017, 04:56:54 pm
Yeah i put down E aswell
Overall there is no increasing trend in the data. There would have been an increasing trend had the peaks become higher values each time as well as the minimum values increasing over time, however they stayed relatively level through the data indicating no increasing trend.
Post by: dec.hargreaves on November 03, 2017, 04:58:49 pm
Post by: sertani on November 03, 2017, 04:59:53 pm
how is the variable number of moths(less than 250, 250-500,more than 500) an ordinal value?
i thought they were both nominal variables
Post by: obrira on November 03, 2017, 05:00:26 pm
Post by: fish99 on November 03, 2017, 05:00:56 pm
Did anyone else get C for networks?what question for networks?
Post by: Sky_Emp on November 03, 2017, 05:02:01 pm
Post by: dec.hargreaves on November 03, 2017, 05:02:31 pm
Can someone explain Q7 CORE
how is the variable number of moths(less than 250, 250-500,more than 500) an ordinal value?
i thought they were both nominal variables
the variables have been put into an order (highest to lowest).
Post by: dec.hargreaves on November 03, 2017, 05:03:11 pm
what question for networks?
question 8
Post by: dec.hargreaves on November 03, 2017, 05:05:38 pm
How was question 16 (Core) A, doesn't make sense. I chose D btwthis involves correcting for seasonality:
1/1.6=0.625
so the actual sales should be reduced by 37.5%
Post by: ayri1234 on November 03, 2017, 05:05:59 pm
Spoiler
1. D
2. D
3. C*
4. B
5. C
6. B
7. E*
8. C*
2. D
3. C*
4. B
5. C
6. B
7. E*
8. C*
Post by: emilylaynek on November 03, 2017, 05:07:46 pm
Shouldn't question 8 be D? (Core)
No because if you look at the scale of the graph, the y-intercept wouldnt be 17.4
Post by: znjar on November 03, 2017, 05:07:48 pm
Post by: fish99 on November 03, 2017, 05:07:56 pm
Why is the answer question 23 D?Assuming the interest rate increases 0.51 each time - this means that #20 interest rate = 28.93...
Then, 7500 - 7233.83 = 266.17 (the total amount paid) minus the #20 interest rate of 28.93 (266.17 - 28.93) = 237.24
Hope it makes sense, someone else might be able to explain it better....
Post by: mammes on November 03, 2017, 05:09:22 pm
Hey everyone! I'm Brady, the Further Maths lecturer for ATAR Notes. I'll gradually be putting up my suggested solutions for the exam. Take them with a grain of salt (interpret that how you will), as they will be subject to a bit of editing! Hope you're all happy with the exam.
Suggested Answers
(anything starred is subject to change)
Core:SpoilerQ1. D
Q2. B
Q3. D
Q4. D
Q5. B
Q6. E
Q7. E
Q8. B
Q9. A
Q10. A
Q11. D
Q12. D*
Q13. B*
Q14. D
Q15. D
Q16. A
Q17. A
Q18. D
Q19. C
Q20. D
Q21. E
Q22. B
Q23. D
Q24. B
Matrices:SpoilerQ1. B
Q2. E
Q3. C
Q4. C
Q5. A
Q6. D
Q7. A
Q8. A*
Networks:SpoilerQ1. B
Q2. C
Q3. A
Q4. D
Q5. C
Q6. E
Q7. D
Q8. B
Modules will be here in a minute!
Got exactly the same.
Post by: tashlyc on November 03, 2017, 05:09:44 pm
Post by: CarrymetoUni on November 03, 2017, 05:10:35 pm
Post by: superficious on November 03, 2017, 05:11:48 pm
Post by: willmac2917 on November 03, 2017, 05:12:51 pm
Post by: deanator71 on November 03, 2017, 05:13:42 pm
Spoiler
- B
- C
- B
- E
- D
- C
- C
- D
Correct me if I am wrong.
Post by: stevieh on November 03, 2017, 05:14:48 pm
Post by: kirstfletch99 on November 03, 2017, 05:16:53 pm
Here's my answers for Graphs and Relations:Spoiler
- B
- C
- B
- E
- D
- C
- C
- D
Correct me if I am wrong.
I got the exact same :)
Post by: dec.hargreaves on November 03, 2017, 05:17:49 pm
Post by: ella.bazza on November 03, 2017, 05:18:42 pm
Why is Core question 2 B, I thought the whole point of upper and lower fencing was to modify the boxplot and the 5-point summary, so why wouldn't the answer be C?
Also, why is Core question 6 E?
And for networks for question 7, how is C a correct statement? Like why is the answer D?
Post by: tashlyc on November 03, 2017, 05:18:56 pm
Geometry and measurement:
1. D
2. D
3. C*
4. B
5. C
6. B
7. E*
8. C*
Why is 8 C? I got A, from making an equilateral triangle with sides of 100mm, then figured out the area of that, and minusing this by 3 times the area segment created (with radius of 50 and an angle of 60) to get 403 as the shaded region.
Post by: kirstfletch99 on November 03, 2017, 05:22:25 pm
Geometry and measurement:Spoiler1. D
2. D
3. C*
4. B
5. C
6. B
7. E*
8. C*
My answers were similar but I got B for Q3 and A for Q8, not sure how you got C's for them....?
Post by: fish99 on November 03, 2017, 05:23:51 pm
my answers are all the same except for networks Q8 which i got C for. anyone else??ahhh - nope I got D, could someone explain this Q8 (networks)?
Post by: fish99 on November 03, 2017, 05:25:06 pm
My answers were similar but I got B for Q3 and A for Q8, not sure how you got C's for them....?yeah I got B for Q3 and A for Q8 as well....
Post by: isobelj on November 03, 2017, 05:25:49 pm
Here's my answers for Graphs and Relations:Spoiler
- B
- C
- B
- E
- D
- C
- C
- D
Correct me if I am wrong.
Could you please explain why Q8 is D? I got C. Thanks
Post by: Landa on November 03, 2017, 05:28:21 pm
Here's my answers for Graphs and Relations:Spoiler
- B
- C
- B
- E
- D
- C
- C
- D
Correct me if I am wrong.
Got the exact same! 👌
Post by: kirstfletch99 on November 03, 2017, 05:29:39 pm
Just a few questions concerning the solutions here-
Why is Core question 2 B, I thought the whole point of upper and lower fencing was to modify the boxplot and the 5-point summary, so why wouldn't the answer be C?
Also, why is Core question 6 E?
And for networks for question 7, how is C a correct statement? Like why is the answer D?
For Q2 the upper and lower fencing helps you determine outliers but the 5 figure summary is determined from the set of data values and these values are still the same, just some of them are outliers. The minimum and maximum values of the data set CAN be outliers which is why it's B.
For Q6 it has to be E because it's the only option that compares the same number of moths (more than 500) and demonstrates how the percentage that contained this amount of moths varies depending on the trap, supporting the contention. To support the association you have to compare the same class of number of moths across 2 or more of the trap types.
Sorry cant help with the networks one! Didn't do that module
Post by: Finlayh on November 03, 2017, 05:30:45 pm
Assuming the interest rate increases 0.51 each time - this means that #20 interest rate = 28.93...
Then, 7500 - 7233.83 = 266.17 (the total amount paid) minus the #20 interest rate of 28.93 (266.17 - 28.93) = 237.24
Hope it makes sense, someone else might be able to explain it better....
0n question 23 i got B not D
I get how you got that answer but it asked for the payment which remains the same each time, so 100, as that is what the other ones are. Did anyone else think this?
Post by: akiophy on November 03, 2017, 05:31:41 pm
Post by: mtDNA on November 03, 2017, 05:33:20 pm
Post by: deanator71 on November 03, 2017, 05:34:38 pm
Could you please explain why Q8 is D? I got C. Thanks
My decimals may be imprecise, but to show that it is not C:
Pick point A: (1.1, 7.6)
m=2 and n=5 so
Z = 2 * 1.1 + 5 * 7.6 = ~40.2
Pick point C: (3.8, 4.4)
Z = 2 * 3.8 + 5 * 4.4 = ~29.6
Because Z for point A is higher than for point C, C is not the answer. (Was looking for the minimum value and nothing false was observed)
To show that D is the answer:
Point D: Z = 2*7.8 + 6*12.4 = ~90
Point B: Z = 2*4.4 + 6*15 = ~98.8
So the maximum value when m=2 and n=6 is not at point D because 98.8 > 90. (Looking for the maximum and it is not at point D)
So the answer is D.
Post by: fish99 on November 03, 2017, 05:36:34 pm
I get how you got that answer but it asked for the payment which remains the same each time, so 100, as that is what the other ones are. Did anyone else think this?At the top it says "The interest rate for this investment remains constant, but the payment may vary" - so on the 20th payment to reach the $7500, the payment was higher while the interest rate stayed the same......
Post by: ella.bazza on November 03, 2017, 05:36:52 pm
For Q2 the upper and lower fencing helps you determine outliers but the 5 figure summary is determined from the set of data values and these values are still the same, just some of them are outliers. The minimum and maximum values of the data set CAN be outliers which is why it's B.
For Q6 it has to be E because it's the only option that compares the same number of moths (more than 500) and demonstrates how the percentage that contained this amount of moths varies depending on the trap, supporting the contention. To support the association you have to compare the same class of number of moths across 2 or more of the trap types.
Sorry cant help with the networks one! Didn't do that module
Ahh thank you, I just realised I misread the statement C for question 6, that makes more sense haha
Post by: willmac2917 on November 03, 2017, 05:38:57 pm
My answers were similar but I got B for Q3 and A for Q8, not sure how you got C's for them....?
Yeah I got Q3. B and Q8. A.
How are they C and C??
Post by: dec.hargreaves on November 03, 2017, 05:39:01 pm
ahhh - nope I got D, could someone explain this Q8 (networks)?nevermind. just had a proper look at it and its B
Post by: Finlayh on November 03, 2017, 05:39:34 pm
At the top it says "The interest rate for this investment remains constant, but the payment may vary" - so on the 20th payment to reach the $7500, the payment was higher while the interest rate stayed the same......
Oh, thankyou! I can't believe i didn't see that!
Post by: xavosh on November 03, 2017, 05:39:51 pm
Question 7 (Geometry) is really confusing. Can someone actually show working out to why the answer is E.nah man says in the q that the payment can change i think. so find interest, add to total 19 and take from 7500 to get your payment
Post by: som0007 on November 03, 2017, 05:40:06 pm
1.D
2.D
3.B
4.A*** (i thought radius was 10)
5.C
6.C
7.C
8.A
Post by: dec.hargreaves on November 03, 2017, 05:41:43 pm
Just a few questions concerning the solutions here-C is correct because if there are 8 edges then there could definitely be and isolated vertex. Bipartite graphs are what you use when allocations need to be made. hope this helps
Why is Core question 2 B, I thought the whole point of upper and lower fencing was to modify the boxplot and the 5-point summary, so why wouldn't the answer be C?
Also, why is Core question 6 E?
And for networks for question 7, how is C a correct statement? Like why is the answer D?
Post by: ScreaMy on November 03, 2017, 05:41:58 pm
So far only lost 2 mark tho :(
Post by: teeeegs1 on November 03, 2017, 05:43:14 pm
Post by: ojwhop on November 03, 2017, 05:43:22 pm
Post by: willmac2917 on November 03, 2017, 05:45:12 pm
Geo and measurement
1.D
2.D
3.B
4.A*** (i thought radius was 10)
5.C
6.C
7.C
8.A
How’d you get A for Q4. Isn’t it B?
Post by: mtDNA on November 03, 2017, 05:45:41 pm
I got A for question 8 (geometry and measurement) through calculating the area of the triangle which connects the middle of the circles and calculating the area of each segment in this triangle (hard to explain) then got the area of the shaded region through subtracting both figures.
Yea it’s A, a similar question was in our year 11 spec exam :P
Post by: isobelj on November 03, 2017, 05:45:57 pm
My decimals may be imprecise, but to show that it is not C:
Pick point A: (1.1, 7.6)
m=2 and n=5 so
Z = 2 * 1.1 + 5 * 7.6 = ~40.2
Pick point C: (3.8, 4.4)
Z = 2 * 3.8 + 5 * 4.4 = ~29.6
Because Z for point A is higher than for point C, C is not the answer. (Was looking for the minimum value and nothing false was observed)
To show that D is the answer:
Point D: Z = 2*7.8 + 6*12.4 = ~90
Point B: Z = 2*4.4 + 6*15 = ~98.8
So the maximum value when m=2 and n=6 is not at point D because 98.8 > 90. (Looking for the maximum and it is not at point D)
So the answer is D.
Okay, thank you! That makes sense.
Post by: som0007 on November 03, 2017, 05:47:54 pm
How’d you get A for Q4. Isn’t it B?
I thought the radius is 10 LMFAO. i got it wrong.
But what is the answer for question 6 geo. i got C
Post by: akiophy on November 03, 2017, 05:49:02 pm
nah man says in the q that the payment can change i think. so find interest, add to total 19 and take from 7500 to get your paymentI think you misinterpret my question. I was referring to question 7 in geometry section, not financial maths.
Post by: ScreaMy on November 03, 2017, 05:51:34 pm
I thought the radius is 10 LMFAO. i got it wrong.
But what is the answer for question 6 geo. i got C
Question 6 is B
Post by: som0007 on November 03, 2017, 05:53:59 pm
Question 6 is B
Can you explain
Post by: willmac2917 on November 03, 2017, 05:55:02 pm
I thought the radius is 10 LMFAO. i got it wrong.
But what is the answer for question 6 geo. i got C
I got B.
Which is done by creating a triangle to the surface of the water with a hypotenuse of 10cm and a verticle length of 8cm. Using Pythagoras we can find the radius of the water by doing 10^2 - 8^2 = 36. Square root 36 giving 6.
Answer is B
Post by: crackleking on November 03, 2017, 05:56:39 pm
Post by: som0007 on November 03, 2017, 05:57:05 pm
I got B.
Which is done by creating a triangle to the surface of the water with a hypotenuse of 10cm and a verticle length of 8cm. Using Pythagoras we can find the radius of the water by doing 10^2 - 8^2 = 36. Square root 36 giving 6.
Answer is B
Lol i just realised FUCK.
Post by: girlonline on November 03, 2017, 05:59:35 pm
Post by: kirstfletch99 on November 03, 2017, 05:59:41 pm
Question 7 (Geometry) is really confusing. Can someone actually show working out to why the answer is E.
So I used the sine rule and managed to eliminate options A,B,C and D as these angles were all possible which left me with option E!
See my working out in the attachment :)
Post by: som0007 on November 03, 2017, 06:02:29 pm
I think I lost 7 marks, can I still get above 40? What would be the highest I could get assuming I get above 90% on the second exam? My average for sacs is 92%. I am freaking out 😭 Can someone please put me out of my misery and give an estimate?
I lost max 7 and min 6
same boat
Post by: girlonline on November 03, 2017, 06:04:13 pm
I lost max 7 and min 6I’m so upset. Further was like the subject I was counting on to pull me through to a decent atar 😭😭.
same boat
Post by: Mattjbr2 on November 03, 2017, 06:11:31 pm
Core:
Spoiler
Q1. D
Q2. B
Q3. D
Q4. D
Q5. B
Q6. E
Q7. B (wrong. correct answer is definitely: E)
Q8. D (wrong. correct answer is definitely: B)
Q9. A
Q10. A
Q11. D
Q12. D
Q13. C (controversial. correct answer may be: B. But I'm still confident it's C because I see seasonality and so do many others)
Q14. D
Q15. D
Q16. A
Q17. A
Q18. D
Q19. C
Q20. D
Q21. E
Q22. B
Q23. D
Q24. B
Q2. B
Q3. D
Q4. D
Q5. B
Q6. E
Q7. B (wrong. correct answer is definitely: E)
Q8. D (wrong. correct answer is definitely: B)
Q9. A
Q10. A
Q11. D
Q12. D
Q13. C (controversial. correct answer may be: B. But I'm still confident it's C because I see seasonality and so do many others)
Q14. D
Q15. D
Q16. A
Q17. A
Q18. D
Q19. C
Q20. D
Q21. E
Q22. B
Q23. D
Q24. B
Matrices:
Spoiler
Q1. B
Q2. E
Q3. C
Q4. C
Q5. A
Q6. D
Q7. A
Q8. A
Q2. E
Q3. C
Q4. C
Q5. A
Q6. D
Q7. A
Q8. A
Graphs and Relations:
Spoiler
Q1. B
Q2. C
Q3. B
Q4. E
Q5. D
Q6. C
Q7. C
Q8. D
Q2. C
Q3. B
Q4. E
Q5. D
Q6. C
Q7. C
Q8. D
Hopefully 13 is C. If so, then I get 38/40 :) if not, then 37/40 :(
Post by: ojwhop on November 03, 2017, 06:15:46 pm
I’m so upset. Further was like the subject I was counting on to pull me through to a decent atar 😭😭.
Hey, gauging everyone's thoughts, the exam this year was pretty damn tough. Your effort was amazing! and all you have to do is reflect on this exam and not fall for the same traps that will no doubt be present on Monday's exam. Keep up the work!
Post by: isobelj on November 03, 2017, 06:18:59 pm
I think I lost 7 marks, can I still get above 40? What would be the highest I could get assuming I get above 90% on the second exam? My average for sacs is 92%. I am freaking out 😭 Can someone please put me out of my misery and give an estimate?
I don't know a huge amount about study scores, but looking at the 2016 scaling report it seems that the cutoff to get an A in exam 1 was 33 marks out of 40. While it will most likely change this year, you'll probably get an A or a B for this exam, which is really great! As far as I know you can still get a pretty good study score for further, as long as you do well in the second exam.
I'd recommend looking over your mistakes from this exam and putting them in your bound reference. This weekend do lots of practice exams, checkpoints questions, or you could even look over previous practice exams you've done and work through your mistakes. Even if you feel like you didn't do that well in this exam there's still Monday. Work as hard as you can and do your best, it'll pay off!!! Good luck friend :)
Post by: Mattjbr2 on November 03, 2017, 06:23:38 pm
I think I lost 7 marks, can I still get above 40? What would be the highest I could get assuming I get above 90% on the second exam? My average for sacs is 92%. I am freaking out 😭 Can someone please put me out of my misery and give an estimate?
Losing 7 marks on exam 1 equates to a score of 66/80. That puts you in the top 18.4% of students for the 2016 exam 1.
Without knowing your rank, and assuming you get a very good score of 90% for exam 2 (only 8%of students got above 86% on exam 2 in 2016) I can estimate your SS in 2016 to be: Very Low A+ , Very Low A , Mid A+ = 38
Post by: abbie_roseee on November 03, 2017, 06:36:54 pm
Post by: jonwil on November 03, 2017, 06:37:03 pm
Based on various sources that confirm all of Brady's current answers for Core/Matrices/Networks
Im sitting on a 38/40 (Rip my networks understanding xD)
Is it still possible to get a 50?
Im rank 1, My teacher has told me that all the marks hes sent through to VCAA has been 100%
If I managed to get 59/60 or full marks is that enough for a 50?
Thanks! :D
Post by: elaine18 on November 03, 2017, 06:59:05 pm
Post by: Mattjbr2 on November 03, 2017, 06:59:21 pm
So my question is!
Based on various sources that confirm all of Brady's current answers for Core/Matrices/Networks
Im sitting on a 38/40 (Rip my networks understanding xD)
Is it still possible to get a 50?
Im rank 1, My teacher has told me that all the marks hes sent through to VCAA has been 100%
If I managed to get 59/60 or full marks is that enough for a 50?
Thanks! :D
Calculator says ~47
"it has been reported that you can only lose one mark over both exams if you want a 50. From there onwards, any mark lost is approximately a study score lost until about 45, where things become slightly more relaxed."
"from what I've heard, one mistake on the exam essentially means one mark off your study score."
"dropped 1 mark in exam + 94% SACS = Dropped 4 S.S"
More helpful info here
Post by: jonwil on November 03, 2017, 07:01:45 pm
Calculator says ~47
"it has been reported that you can only lose one mark over both exams if you want a 50. From there onwards, any mark lost is approximately a study score lost until about 45, where things become slightly more relaxed."
"from what I've heard, one mistake on the exam essentially means one mark off your study score."
"dropped 1 mark in exam + 94% SACS = Dropped 4 S.S"
More helpful anecdotes here
Calculator says ~47
"it has been reported that you can only lose one mark over both exams if you want a 50. From there onwards, any mark lost is approximately a study score lost until about 45, where things become slightly more relaxed."
"from what I've heard, one mistake on the exam essentially means one mark off your study score."
"dropped 1 mark in exam + 94% SACS = Dropped 4 S.S"
More helpful anecdotes here
Ah cheers
So the absolute maximum I can achieve would be a 48 given I don't drop another mark?
Given that, this years exam is much harder than last would bellcurve for 48-50 be maybe an extra mark down as opposed to previousyears?
Post by: masn123 on November 03, 2017, 07:03:15 pm
Post by: jonwil on November 03, 2017, 07:06:48 pm
How is the answer for Networks Q6 is E? Isn't the answer D? (4 ways to make an Eulerian trial possible?)You've got three in the middle from the middle vertex to each of the 3 odd degree vertexes
Then on the very bottom of the network you have 2 vertexes of degree 5
And in between those are another 2 edges
Therefore
3+2=5 =E
Post by: Mattjbr2 on November 03, 2017, 07:10:52 pm
Ah cheers
So the absolute maximum I can achieve would be a 48 given I don't drop another mark?
Given that, this years exam is much harder than last would bellcurve for 48-50 be maybe an extra mark down as opposed to previousyears?
Yeah this year's exam 1 is a hell of a lot more difficult than last year's (I dropped only 1 mark on both the sample and actual 2016 exams, as opposed to potentially 3 marks this year). So the A+ cutoff will likely be much less than 36/40, and so you'd be good with losing a mark or two for a 50 and many more for a 48+
Post by: jonwil on November 03, 2017, 07:19:07 pm
Yeah this year's exam 1 is a hell of a lot more difficult than last year's (I dropped only 1 mark on both the sample and actual 2016 exams, as opposed to potentially 3 marks this year). So the A+ cutoff will likely be much less than 36/40, and so you'd be good with losing a mark or two for a 50 and many more for a 48+
Feels good to hear that xD
Upon having this "1 marks a studyscore gone" mentality all year, pumping out practice exam after practice exam and seeing my potential loss of 2 marks I was so guttered
But its given me huge motivation to over perform on Monday, based on last yrs calculations its not possible but hopefully considering the difficulty of this year a 48/49/50 is still very possible :D
Post by: masn123 on November 03, 2017, 07:34:54 pm
Then on the very bottom of the network you have 2 vertexes of degree 5
And in between those are another 2 edges
Therefore
3+2=5 =E "
Thanks JonWil. I got it now. I missed the point that the multiple edges at the bottom can be removed in two ways. I counted them as one.
Post by: KidClutch on November 03, 2017, 07:38:01 pm
Thanks for posting the solutions!
Post by: malyy768 on November 03, 2017, 07:43:46 pm
I lost max 7 and min 6Yea I lost 7 marks too, is there anyway of getting a 40 raw ??
same boat
Post by: znjar on November 03, 2017, 08:01:11 pm
Post by: joojam on November 03, 2017, 08:01:47 pm
Post by: wri0061 on November 03, 2017, 08:05:47 pm
I got a 32/40 on that. If i've averaged B+ also in SACs, as well as a B+ in Mondays exam (hoping), what study score would I be looking at?
Post by: joojam on November 03, 2017, 08:10:44 pm
Post by: Joseph41 on November 03, 2017, 08:11:40 pm
Post by: superficious on November 03, 2017, 08:19:27 pm
yep - i plused 3points before the 4th day (including the 4th day) and 3 points after that... and then divided by 7 = approx 32....... what did I do wrong?
you calculated it as a 7-moving MEAN rather than a 7-moving median...
in a 7-moving median you dont find the average but rather find the middle number
Post by: mtDNA on November 03, 2017, 08:24:38 pm
Post by: AbanoubKT on November 03, 2017, 08:29:19 pm
Post by: girlonline on November 03, 2017, 08:30:18 pm
I don't know a huge amount about study scores, but looking at the 2016 scaling report it seems that the cutoff to get an A in exam 1 was 33 marks out of 40. While it will most likely change this year, you'll probably get an A or a B for this exam, which is really great! As far as I know you can still get a pretty good study score for further, as long as you do well in the second exam.Thank you :)
I'd recommend looking over your mistakes from this exam and putting them in your bound reference. This weekend do lots of practice exams, checkpoints questions, or you could even look over previous practice exams you've done and work through your mistakes. Even if you feel like you didn't do that well in this exam there's still Monday. Work as hard as you can and do your best, it'll pay off!!! Good luck friend :)
Post by: addictwithatextbook on November 03, 2017, 08:33:26 pm
So is it confirmed that 13 is B? If so, could someone explain why it can’t be C?
The peaks aren't really regular. There is one at 7 and 21, but not at 14, so it can't be seasonality based on every week. The peaks occur at day 4 (three days before day 7), day 12 (two days before day 14), and day 17 (four days before day 21), further reinforcing that the peaks don't occur regularly every seven days and hence, no seasonality. Therefore, the fluctuations are irregular (B).
Post by: girlonline on November 03, 2017, 08:36:04 pm
Losing 7 marks on exam 1 equates to a score of 66/80. That puts you in the top 18.4% of students for the 2016 exam 1.38. Oh my god noooo 😭😭 My whole atar is going down by so much more than I anticipated 😭 thanks anyway for calculating it. Let me just go dig myself a hole and bury myself in it now 😭
Without knowing your rank, and assuming you get a very good score of 90% for exam 2 (only 8%of students got above 86% on exam 2 in 2016) I can estimate your SS in 2016 to be: Very Low A+ , Very Low A , Mid A+ = 38
Post by: kit_kat15 on November 03, 2017, 08:43:22 pm
Hey everyone! I'm Brady, the Further Maths lecturer for ATAR Notes. I'll gradually be putting up my suggested solutions for the exam. Take them with a grain of salt (interpret that how you will), as they will be subject to a bit of editing! Hope you're all happy with the exam.Why's network Q8 B, how would you work it out?
Suggested Answers
(anything starred is subject to change)
Core:SpoilerQ1. D
Q2. B
Q3. D
Q4. D
Q5. B
Q6. E
Q7. E
Q8. B
Q9. A
Q10. A
Q11. D
Q12. D
Q13. B
Q14. D
Q15. D
Q16. A
Q17. A
Q18. D
Q19. C
Q20. D
Q21. E
Q22. B
Q23. D
Q24. B
Matrices:SpoilerQ1. B
Q2. E
Q3. C
Q4. C
Q5. A
Q6. D
Q7. A
Q8. A
Networks:SpoilerQ1. B
Q2. C
Q3. A
Q4. D
Q5. C
Q6. E
Q7. D
Q8. B
Geometry and Measurement:SpoilerQ1. D
Q2. D
Q3. B
Q4. B
Q5. C
Q6. B
Q7. E*
Q8. A*
Graphs and Relations:Spoiler(Contributed by Deanator71)
Subject to change:
Q1. B
Q2. C
Q3. B
Q4. E
Q5. D
Q6. C
Q7. C
Q8. D
Post by: Joseph41 on November 03, 2017, 08:43:28 pm
Post by: addictwithatextbook on November 03, 2017, 08:59:00 pm
Initially thinking it was option B, $100, because of regular payments as shown in the table, the question read "the payment value may vary," which means the payment may not be $100. This means methods should apply.
The interest and principal addition of payment number 20 must be known to work out the payment. They can be found in any order.
To find Principal addition:
Balance of investment of payment number 20 - balance of investment of payment number 19
7500.00-7233.83
=266.17
To find Interest:
First find the interest rate.
As per formula, interest of payment number 18 = balance of previous payment * interest rate per compunding period, I did (for TI-nspire CAS)
solve(6977.50*r/100=27.91,r)
in which r=0.4%
Use to same formula to find interest for payment number 20.
7233.83*0.4/100 = $28.93... (I never round until the final answer, chem habits)
Then to find payment:
payment + interest = principal addition, Rearrange to find:
payment = principal addition - interest
payment = 266.17 - 28.93... = $237.23...
which is approximately $237 (option D).
Post by: Angelx001 on November 03, 2017, 09:00:05 pm
Post by: omxrk on November 03, 2017, 09:03:43 pm
I've got a 94 SAC Average, got 38/40 for Exam 1 :( & assuming I get around 57/60 (95%) for Exam 2, what kind of study score am I looking at?
Thanks!
Post by: ooft on November 03, 2017, 09:06:28 pm
Post by: addictwithatextbook on November 03, 2017, 09:09:22 pm
Why's network Q8 B, how would you work it out?
Cut D and E are not affected by the changing values of pipelines x (as x does flow from source to sink along cut D), so their capacities are always 32 and 27 respectively.
When x=1, cut A has capacity 26, cut B has capacity 24 (note the 6 is omitted when calculating the capacity as that pipe does not flow from source to sink), and cut C has capacity 25 (remember capacity of cuts D and E). Since cut A does not have the minimum cut capacity, it's capacity does not give the maximum flow. Cut B has the minimum cut capacity, but the option for cut B does not show when x=1.
When x=2, the capacities of cuts A, B, and C, increase by 1, to 27, 25, and 26, respectively. Cut B still has the minimum cut capacity out of all cuts, thus cut B if x=2 (option B) is the correct answer.
If you want to consider when x=3, cut B still has the minimum cut capacity, thus cuts D and E do not give the maximum flow.
Post by: addictwithatextbook on November 03, 2017, 09:14:52 pm
What's the answer for Core question 7?!
The variable number of moths is ordinal as the categories can be ordered from least number of moths caught to the most number of moths caught. The variable trap type is nominal because the categories (sugar traps, scent traps, and light traps) cannot be ordered using a certain unit. Therefore, the answer is E (an ordinal variable and nominal variable respectively).
Post by: ilovethevce on November 03, 2017, 09:21:16 pm
Post by: Joel1999 on November 03, 2017, 09:41:07 pm
Post by: AbanoubKT on November 03, 2017, 10:38:36 pm
Hi, I’m hoping someone can help me. I did very well in my SACs throughout the year (98/100 total) and felt a lot of pressure about the exam today as this is my only good subject. I probably let the pressure get to me too much, I made some really, really, really dumb mistakes which I would normally never make and my total score was 36/40. Is my study score ruined? Is there absolutely any chance at all or still getting a 45? What would I need in E2? Thanks for your help :(
Yes for sure, aim for a perfect exam 2 and you will be fine, the multiple choice does not contribute as much, and this exam was considerably harder than last years, so give it your best shot! 👍
Post by: AbanoubKT on November 03, 2017, 10:53:11 pm
Question 13 of core, after placing the values of the time series into the calculator and producing the least squares regression line there is a positive gradient that suggests an increasing trend. It's not the largest gradient but the definition of an increasing trend is merely an increase over the long term which is clear here. Is this not true?Thought the same way. Shouldn't the answer be E then?
Post by: drepwns on November 03, 2017, 11:04:38 pm
Post by: Hamed Sarwari on November 04, 2017, 12:42:28 am
Post by: hmdeadas on November 04, 2017, 01:26:53 am
My SAC marks for math
CORE - 79%
FINANCE - 68%
MATRICES - 80%
NETWROKS - 62%
(ROUGH YEAR) - So for Exam one according to ATARNOTES i got 27/40...
Is their anyway for me to get a 32 or 33 STUDY SCORE???
My ranking is also not high, middle band
Post by: dec.hargreaves on November 04, 2017, 06:32:46 am
How is question 8 on matrices B? I got Ait is A
Post by: Joel1999 on November 04, 2017, 08:17:07 am
Thought the same way. Shouldn't the answer be E then?
Yeah that's what I would have thought....
Post by: Mattjbr2 on November 04, 2017, 08:21:25 am
So life is getting tough!
My SAC marks for math
CORE - 79%
FINANCE - 68%
MATRICES - 80%
NETWROKS - 62%
(ROUGH YEAR) - So for Exam one according to ATARNOTES i got 27/40...
Is their anyway for me to get a 32 or 33 STUDY SCORE???
My ranking is also not high, middle band
The mean score last year was 50.9/80. You got 54/80. Also, this year's mean is almost certainly much lower than last year's, which means you will get in the low to mid 30s if you do equally well in exam 2. But for now, do as many previous exam 2s as possible in preparation for monday! Its still possible for you to get high 30s if you do well enough in it
Post by: Nomi16 on November 04, 2017, 08:59:22 am
For Graph and relations question 7 is D as C gives the value of n as 200 which is outside the range of the full price.
Post by: RiceSenpai on November 04, 2017, 09:02:39 am
Post by: Sine on November 04, 2017, 10:32:57 am
Hi everyone!what do you mean by this?
For Graph and relations question 7 is D as C gives the value of n as 200 which is outside the range of the full price.
C is the total cost for n pies.
C = 0.8n + 250
C(200) = 0.8 * 200 + 250
C(200) = 410
He sells 150 at full price (x) and sells 50 at half price x/2 he wants to break even so cost of production = total cost sold for
410 = 150x + (50 *x)/2
410 = 150x + 25x
410 = 175x
x = 410/175
x = 2.34
so closest answer is $2.35 i.e. C
Post by: Sine on November 04, 2017, 10:34:26 am
What happens if you screw up in further exam 1 but do well in exam 2?Nothing inherently "happens" but you can definitely salvage/push your score up by doing very well on exam 2
Post by: fizza106 on November 04, 2017, 10:44:24 am
Post by: Sine on November 04, 2017, 10:50:00 am
For CORE question 19 and 20, are all interest only loans set out at perpetuities, so do their values always stay the same?The stem of the question says she pays the the intrest so what happens is the loan will increase via intrest in a month ($675) then she pays the amount that $675 hence going back to the original value of $225000 and this continually occurs.
Post by: Emwinkler on November 04, 2017, 11:23:56 am
Post by: reards on November 04, 2017, 11:55:41 am
Could someone explain the working for Q7 matrices
Use the recurrence relation given and times that by initial state of population and it gives a 4x1 matrix of 32500 at top, 20000 second row, 8650 third row and 5850 fourth row.
The information given said you had to sell or buy fish to get it back to initial state. So the only answer that worked was A, as 8650 adult fish after one month hence 1650 had to be sold to get it back to the constant state of 7000 adult fish
Post by: mtDNA on November 04, 2017, 11:56:29 am
Could someone explain the working for Q7 matrices
I think the best way for you to understand it is to look at the exam 2 questions from 2012-2016, I remember nearly the exact same question pop up in there, so take a look at the examiners report and it will explain the full working (sorry, I just can’t remember which exam it was since I saw it in checkpoints I think)
Post by: Something2016 on November 04, 2017, 12:21:19 pm
I am ranked 1st with a 100% SAC Average,
I scored 39/40 in Exam 1.
How many marks can I lose in Exam 2 and still pull off a 50?
Post by: mtDNA on November 04, 2017, 12:25:43 pm
Hey,
I am ranked 1st with a 100% SAC Average,
I scored 39/40 in Exam 1.
How many marks can I lose in Exam 2 and still pull off a 50?
Bump
Post by: Something2016 on November 04, 2017, 12:32:16 pm
Bump
??
Post by: Somedudelmaoy on November 04, 2017, 12:36:29 pm
Hey,
I am ranked 1st with a 100% SAC Average,
I scored 39/40 in Exam 1.
How many marks can I lose in Exam 2 and still pull off a 50?
none.
Post by: jonwil on November 04, 2017, 01:03:38 pm
none.Gotta take into account that this years exam was much harder than last years therein the cut offs will be less
Im rank 1, 100% sac average with 38/40
And people still reckon if I ace mondays exam or drop 1 mark a 50 is still possible
Post by: jimbo9 on November 04, 2017, 01:23:03 pm
Question 13 of core, after placing the values of the time series into the calculator and producing the least squares regression line there is a positive gradient that suggests an increasing trend. It's not the largest gradient but the definition of an increasing trend is merely an increase over the long term which is clear here. Is this not true?
Doing this also gives an r of less than 0.25 which means no relationship.
I think it would have to be quite a bit higher to be "best described" as E
Post by: Joel1999 on November 04, 2017, 02:41:35 pm
Doing this also gives an r of less than 0.25 which means no relationship.
I think it would have to be quite a bit higher to be "best described" as E
Yeah like I said, it is quite a small slope, but I think the term increasing trend is too subjective. As in what actually qualifies something to have an 'increasing trend' because my definition is what I stated earlier which is very vague....
Post by: helpmepls on November 04, 2017, 05:01:52 pm
Post by: Nomi16 on November 04, 2017, 05:36:04 pm
what do you mean by this?I meant that full price is only for the first 150 pieces thus the cost of the 150 pieces comes out to be 370.
C is the total cost for n pies.
C = 0.8n + 250
C(200) = 0.8 * 200 + 250
C(200) = 410
He sells 150 at full price (x) and sells 50 at half price x/2 he wants to break even so cost of production = total cost sold for
410 = 150x + (50 *x)/2
410 = 150x + 25x
410 = 175x
x = 410/175
x = 2.34
so closest answer is $2.35 i.e. C
so 370/150=2.466 which is the break even point of the 150 pieces. So the answer should be D.
Post by: KidClutch on November 04, 2017, 05:45:01 pm
Yeah like I said, it is quite a small slope, but I think the term increasing trend is too subjective. As in what actually qualifies something to have an 'increasing trend' because my definition is what I stated earlier which is very vague....He's not talking about the slope, but rather the correlation coefficient is 0.25, which considered no correlation
To find the underlying trend, you should use smoothing rather than a linear regression line
Post by: KidClutch on November 04, 2017, 05:48:10 pm
I meant that full price is only for the first 150 pieces thus the cost of the 150 pieces comes out to be 370.The half-price pies still have the same costs as the full price pies, which is 410, since she has already made 200 pies
so 370/150=2.466 which is the break even point of the 150 pieces. So the answer should be D.
Post by: elle6299 on November 04, 2017, 05:49:09 pm
Thanks in advance!
Post by: Joel1999 on November 04, 2017, 09:28:51 pm
He's not talking about the slope, but rather the correlation coefficient is 0.25, which considered no correlation
To find the underlying trend, you should use smoothing rather than a linear regression line
I know that, the slope is dependant on the correlation coefficient. But that is irrelevant, if you can tell me why precisely what qualifies a time series to have an increasing or decreasing trend. Because no where in the definition does it refer to the smoothed time series of any kind. Because to me if something is "increasing" over the period of time given it follows that it has an "increasing trend".
Post by: Spencer_Luscombe on November 04, 2017, 09:47:39 pm
Post by: KidClutch on November 04, 2017, 10:23:15 pm
The fluctuations are obscuring the underlying pattern in the time series, therefore smoothing is required
I know that, the slope is dependant on the correlation coefficient. But that is irrelevant, if you can tell me why precisely what qualifies a time series to have an increasing or decreasing trend. Because no where in the definition does it refer to the smoothed time series of any kind. Because to me if something is "increasing" over the period of time given it follows that it has an "increasing trend".
Post by: KidClutch on November 04, 2017, 10:24:12 pm
Are significant figures different to decimal places? eg. would the number 1.2345 to three significant figures be 1.235 or 1.23Yes. They are different. 3 sig figs is 1.23
Post by: hmdeadas on November 04, 2017, 11:09:50 pm
The mean score last year was 50.9/80. You got 54/80. Also, this year's mean is almost certainly much lower than last year's, which means you will get in the low to mid 30s if you do equally well in exam 2. But for now, do as many previous exam 2s as possible in preparation for monday! Its still possible for you to get high 30s if you do well enough in itThank You! Makes me feel a bit better haha. Only aiming for a 32/33 so hopefully it works out :-)
Post by: hmdeadas on November 04, 2017, 11:49:02 pm
Thanks
Post by: Educator on November 05, 2017, 01:44:14 am
regarding core question 11,
Could someone explain to me why a seasonal index can never be negative?
For instance
Q1: 20
Q2: -50
Q3: -75
Q4: 10
What are the seasonal indices.
TIA
Post by: addictwithatextbook on November 05, 2017, 09:42:17 am
Can someone explain question 5 on NETWROKS (maths exam), I got 4 but can't get question5. ALSO question6 netwroks please, i looked at the solutions but it still doesn't make sense, how do i handle these types of questions
Thanks
Questions 5 essentially asks the number of activities on the critical path(s). If you complete forward and backward scanning on the activity network for the question, you will find that activities C-F-H-M have the same EST and LST, and thus are on the only critical path. As any activity on the critical path cannot be delayed without increasing the project's minimum time, and that there are four activities on the critical path, the answer is 4 (C).
Question 6 made me muck up a few times. A good way to approach this question is to label the degree of each vertex, and it will result in the top, centre, and bottom two vertices being odd, making a total of four odd vertices. The question asks how many ways an edge can be removed to make an Eulerian trail. An Eulerian trail can only occur if there are two odd vertices. Removing any edge connecting two odd vertices will decrease their vertex to an even. (For example, removing the edge between the top vertex and centre vertex will decrease their vertex to 2 and 4 respectively). This will result in only two odd vertices left, allowing for an Eulerian trail to occur. In the graph, there are five edges connecting only the odd degree vertices, therefore there are 5 ways (E) to remove an edge for an Eulerian trail to be possible.
Post by: dec.hargreaves on November 05, 2017, 09:50:14 am
Questions 5 essentially asks the number of activities on the critical path(s). If you complete forward and backward scanning on the activity network for the question, you will find that activities C-F-H-M have the same EST and LST, and thus are on the only critical path. As any activity on the critical path cannot be delayed without increasing the project's minimum time, and that there are four activities on the critical path, the answer is 4 (C).i agree. question 6 was annoying at first but eventually got it
Question 6 made me muck up a few times. A good way to approach this question is to label the degree of each vertex, and it will result in the top, centre, and bottom two vertices being odd, making a total of four odd vertices. The question asks how many ways an edge can be removed to make an Eulerian trail. An Eulerian trail can only occur if there are two odd vertices. Removing any edge connecting two odd vertices will decrease their vertex to an even. (For example, removing the edge between the top vertex and centre vertex will decrease their vertex to 2 and 4 respectively). This will result in only two odd vertices left, allowing for an Eulerian trail to occur. In the graph, there are five edges connecting only the odd degree vertices, therefore there are 5 ways (E) to remove an edge for an Eulerian trail to be possible.
Post by: darcypeaceee on November 05, 2017, 10:33:24 am
Thank you in advance
Post by: Paolo Grande on November 05, 2017, 11:44:19 am
Post by: Educator on November 05, 2017, 01:11:13 pm
Regarding my earlier query, are we now all agreed that seasonal indices can be negative and therefore D cannot be a correct answer to Core question 11?
Post by: dec.hargreaves on November 05, 2017, 02:55:48 pm
Hi,This questions seems to have been argued a bit. Which answer would you have chosen? I chose D because I think the rest can definitely be negative
Regarding my earlier query, are we now all agreed that seasonal indices can be negative and therefore D cannot be a correct answer to Core question 11?
Post by: Educator on November 05, 2017, 03:05:26 pm
Post by: dec.hargreaves on November 05, 2017, 03:07:20 pm
Post by: Educator on November 05, 2017, 03:10:03 pm
Q1: 10
Q2: 30
Q3: -5
Q4: 20
Post by: dec.hargreaves on November 05, 2017, 03:25:22 pm
Seasonal Index = value for season/seasonal average
10+30+(-5)+20 = 55
55/4 = 13.75 (seasonal average)
10/13,75 = 0.7272727... SI-1
30/13.75 = 2.1818181... SI-2
-5/13.75 = -0.3636363... SI-3
20/13.75 = 1.4545454... SI-4
SI-1 + SI-2 + SI-3 + SI-4 = 4.000000001
seasonal indices can be negative.
thanks for opening this up to me. I thought that because they usually have to do with sales made in a season (year, quarter, month) they had to be positive because you can't have negative amount of sales
Post by: Educator on November 05, 2017, 03:31:10 pm
That's why I opened it up for discussion.
Post by: dec.hargreaves on November 05, 2017, 03:41:20 pm
Post by: Educator on November 05, 2017, 03:48:35 pm
Winter: -20 degrees
Spring: -5 degrees
Summer: 10 degrees
Autumn: 5 degrees
Post by: addictwithatextbook on November 05, 2017, 04:40:24 pm
Post by: Educator on November 05, 2017, 04:45:50 pm
The textbook method for calculating SI's can lead to negative SI's.
Post by: Paolo Grande on November 05, 2017, 06:07:47 pm
The other point is that when looking at amounts in relation to time, negative values do not make sense so consequently negative seasonal indices are not possible.
All the other options can definitely be negative so D is the correct answer. The VCAA would not be so sloppy in such a question to make an error.
Post by: Steve252 on November 05, 2017, 06:38:40 pm
If a seasonal index of 1.6 means 60% above the average, in the same way, a seasonal index of -0.5 would mean it is 150% below the average, as in 1.5 times below the average
Post by: Mattjbr2 on November 06, 2017, 08:10:15 am
Post by: jonwil on November 06, 2017, 12:04:55 pm
Can we please discuss why question 13 is not C? To me it looks like there's a pattern that repeats every ~7 days. Must seasonality have perfectly equal width between every single crest and trough? I thought it can be approximately the same each time give or take 1 day, hence why i assumed it's seasonal with some random fuzziness in places, i.e. random fluctuations. How can you confidently, with 100% certainty, say it's B? See the attached image for my thought process.
Cos your high points aren't consistent
They come at 7, 12, 20 which aren't consistent enough to argue for seasonality.
Even the low points bro
1,2 10, 15, 19
Whatever 3 points you decide to choose you can't really make a relation out of it.
So yeah
100% B
The only thing is a possible increase but nothing really shows it so B