ATAR Notes: Forum
HSC Stuff => HSC Maths Stuff => HSC Subjects + Help => HSC Mathematics Advanced => Topic started by: 88siege on February 22, 2018, 06:45:21 pm
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Im not sure if i'm overthinking for this question but i've been trying to solve simultaneously and idk where to go from there, do we just have to sub in x=-1 into both equations and prove they both give the same answer hence they intersect at x=-1?????
Show that the curves y=x^2 and y=e^(x+1) intersect at x=-1
Help is appreciated!!
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Yeah, at a time like that all you can do is sub in \(x=-1\) and verify you get the same \(y\) value both ways.
There is no way to solve \(x^2 = e^{x+1} \) using elementary methods
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Oh okay Thanks!!!