ATAR Notes: Forum
Archived Discussion => 2009 => End-of-year exams => Exam Discussion => Victoria => Further Mathematics => Topic started by: jedda on November 02, 2009, 05:42:34 pm
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Everyone seemed to get E for this question, but I got C.
Could it be that because only one third of animals have a high exposure to danger, that u times one third by 86 to get 28?
I'm probably wrong but just want it to be cleared up.
Thanx :)
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I think they are only asking for the animals whose exposure to danger was high. Not as a total.
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Yeah probably it just seems a bit ambiguous
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whose exposure was high and whose chance of attack is below average.
I put C
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We don't know that the number of animals for each of low, medium and high exposure to danger is equal, so we can't compare them that way. There could be 100 for low, 100 for medium and 20000 for high, for all we know. :-\
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Yeah probably it just seems a bit ambiguous
...don't think too deep into a question. It's sort of good that you do but not in this case. It's immediately clear that the answer is E....doesn't make it ambigious, just common sense that a higher % of the bar is coloured as below average
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Yeah just read the graph and dont read too far into the question
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i put C. Trick questions are trick questions, thats why you have to read into them.
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I put C also, if that's wrong, I get 39/40 >_>
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Was C with 86% or some in it's graph sorry can't remember
may of put that one not sure can't remember
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Was C with 86% or some in it's graph sorry can't remember
may of put that one not sure can't remember
nope, the majority of ppz put 86%....some are debating that the answer is 28% =.=*
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Lets put an end to this controversy lol
Vote for C or E here: http://vcenotes.com/forum/index.php/topic,18902.0.html
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the percentage of animals whose exposure to danger is high AND (key word being "and") whose chance of attack is below average is closest to 28%. thus the answer being C. you must consider there are two other loads of information. the AND gives this away. I am fairly confident with this, but chances are they will just give both correct anyway. way tooooo ambiguous
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oh sorry i meant E
and yes i put that down hopefully it was right
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i dont understand how it could be C?
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the percentage of animals whose exposure to danger is high AND (key word being "and") whose chance of attack is below average is closest to 28%. thus the answer being C. you must consider there are two other loads of information. the AND gives this away. I am fairly confident with this, but chances are they will just give both correct anyway. way tooooo ambiguous
i'm sorry but if the "key word" was not AND but was OR, the question would not make sense! The word used has to be 'and'. But, I too do agree that the question is very ambiguous.
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Firstly if you use the method High Exposure intersect below avg, the answer would be 29. C=28
Secondly, you dont know how many animals are in each group. Only percentages. So low exposure may have 10 animals while High has 100. So you cant assume that each group is equal making 29% incorrect.
E.G. 100 in high
10 in low
10 in medium
86 in high are below avg.
so 86/(100+10+10) *100 = 72 %
Any number of combinations depending on the numbers in each group.
So answer must be E