ATAR Notes: Forum
Archived Discussion => VCE Exam Discussion 2020 => Exam Discussion => Victoria => Science Exams => Topic started by: 99.95_goal on November 24, 2020, 12:29:51 pm
-
How was it guys?
-
Decent. Some interesting questions.
Just to be clear, the last question was the graph sketch one ye?
-
Decent. Some interesting questions.
Just to be clear, the last question was the graph sketch one ye?
yea it was.
The questions were pretty different from like 90 % of the past exams definitely
-
yea it was.
The questions were pretty different from like 90 % of the past exams definitely
agreed. any idea how hard it'll be to score a 45 ss?
-
yea it was.
The questions were pretty different from like 90 % of the past exams definitely
Yeah like the stretching coil and also the one with the electron moving in that magnetic field with electric plates.
I’m very uncertain as to my score. Anywhere from 95-100%.
Any idea when we will be able to see the answers?
-
definitely did better on this one than any of my other exams. I was shocked that the stuff I actually understood made up most of the paper, woo
I'm so thankful. I love you VCAA let me give you a smooch
-
Do you guys think this exam was harder than previous years or easier? and what do you reckon will be the A+ cutoff?
-
Somewhat Harder, A+ = ~80%
(About 2 percentage points lower).
If 2019 was a 5/10 in difficulty, 2020 exam was about 6.5-7/10. Unconventional questions in the exam
-
anyone got a copy of the exam or solutions? send thru if ya do, thanks g's
-
anyone got a copy of the exam or solutions? send thru if ya do, thanks g's
I second this.
-
anyone got a copy of the exam or solutions? send thru if ya do, thanks g's
I second this.
we're not allowed to have copies of the exam shared using the forums unfortunately since VCAA has the copyright over them :(
suggested solutions are fine tho as long as it doesn't include the actual exam.
-
Somewhat Harder, A+ = ~80%
(About 2 percentage points lower).
If 2019 was a 5/10 in difficulty, 2020 exam was about 6.5-7/10. Unconventional questions in the exam
agree - I mean I thought I did ok but the questions were basically unseen so idk how it'll translate to my ss
-
How did we go on the last question (with the circuit with resistance, and the graph we had to sketch)?
-
How did we go on the last question (with the circuit with resistance, and the graph we had to sketch)?
I did it but lowkey felt like I bludged it, what did you get for the last question?
-
I did it but lowkey felt like I bludged it, what did you get for the last question?
7 Ohms. (negative value of the y intercept)
I have a bad feeling like it is out of range though. Also, I am guessing that is the way to find the value, as -R was the 'c' value of the equation linking r and 1/i.
-
I think this exam was more difficult in past years (not the type of questions but there were lots of sneaky things here and there). I believe the cut off for A+ will be about 105/130 or so....
-
7 Ohms. (negative value of the y intercept)
I have a bad feeling like it is out of range though. Also, I am guessing that is the way to find the value, as -R was the 'c' value of the equation linking r and 1/i.
yea that's what I got too, except I just subbed in the i value when r=0 which was 0.3 and times it by 24
-
7 Ohms. (negative value of the y intercept)
I have a bad feeling like it is out of range though. Also, I am guessing that is the way to find the value, as -R was the 'c' value of the equation linking r and 1/i.
also that 'show that' question for the last one, what were we meant to do? I sorta just did a general equation then subbed in the values for voltage and current but the wording confused me a lot
-
also that 'show that' question for the last one, what were we meant to do? I sorta just did a general equation then subbed in the values for voltage and current but the wording confused me a lot
Show: r = 16/i - R (changing the number to 16 in case copyright is an issue)
The input voltage is 16 V.
Current = i = V/Rt = 16/(r+R), rearranging: r+R=16/i , hence, r = 16/i - R
-
Show: r = 16/i - R (changing the number to 16 in case copyright is an issue)
The input voltage is 16 V.
Current = i = V/Rt = 16/(r+R), rearranging: r+R=16/i , hence, r = 16/i - R
Ok, I did that but wasted so much time trying to sub in values like in methods
-
What about that question where the electron was in a field and could land at points X, Y or Z?
I chose Z, as if v increases, F = qvB increases, as F is downwards, this will outweigh the electric field induced force, hence the electron will move down to z.