Post by: TrueTears on November 06, 2009, 11:31:37 am
For those who don't have winrar, PDF version can be downloaded here: http://www.mediafire.com/file/xmdjyrwniwd/TT's Suggested Solutions for Methods!.pdf (Thanks goes to jasrulz63)
Post by: hyperblade01 on November 06, 2009, 11:33:56 am
Post by: TrueTears on November 06, 2009, 11:38:12 am
Post by: chinx_4eva on November 06, 2009, 11:38:55 am
Post by: THem on November 06, 2009, 11:40:39 am
haha
Post by: TrueTears on November 06, 2009, 11:40:50 am
Fucken crazy on 10b thereMan in the exam I wrote wayyy more lol
haha
Post by: almostatrap on November 06, 2009, 11:43:14 am
for q10. I wrote out x=8, h=0.06, f(x)=blah and f'(x)=blah all correctly
then i accidentally subbed in 2 instead of 8 for f'(x), giving a wrong answer. would this be 2 or 3, out of 4marks?
Post by: THem on November 06, 2009, 11:44:10 am
For 7B ( find the variance from
the distribution table given),
x 0 1 2 3 4
0.1 0.2 0.4 0.2 0.1
I wrote E(x^2)-[e(x)]^2
= (0+0.2+1.6+1.8+1.6)-(0.2+0.8+0.6+0.4)
= 5.2 - 2
= 3.2
I didn't square the mean, giving me
3.2 instead of 1.2
It was a 3 mark question and i'm
assuming 2 marks for method, 1
for answer.
Do you think I'll lose 2 or 1?
Post by: m@tty on November 06, 2009, 11:45:12 am
Post by: TrueTears on November 06, 2009, 11:45:41 am
Quick question:Lose 1 for answer mark I reckon.
For 7B ( find the variance from
the distribution table given),
I wrote E(x^2)-[e(x)]^2
= (0+0.2+1.6+1.8+1.6)-(0.2+0.8+0.6+0.4)
= 5.2 - 2
= 3.2
I didn't square the mean, giving me
3.2 instead of 1.2
It was a 3 mark question and i'm
assuming 2 marks for method, 1
for answer.
Do you think I'll lose 2 or 1?
Post by: angelboykevin on November 06, 2009, 11:46:04 am
Post by: m@tty on November 06, 2009, 11:47:52 am
Damn I made an error there :-\
should be
Error from overworking a question...
Post by: TrueTears on November 06, 2009, 11:47:56 am
dont u lose mark for 1b) if u leave the answer like that? thanks for the solution^^Why would you lose a mark...
It never said in expanded form and it's the same thing essentially.
Post by: invalid on November 06, 2009, 11:48:28 am
Didn't find f'(pi), just f'(x), even managed to mess up the ridiculously easy probability question. Hoping examiners will at least see that I had the formulas right.
Post by: Ilovemathsmeth on November 06, 2009, 11:48:39 am
*Fond memories*
Post by: nala on November 06, 2009, 11:49:17 am
Also just a quick question, contrary to what I wrote above (:P) I did simplify my answer for 1b,to 1/2(pi+1)^2. Is this still correct?
Post by: simpak on November 06, 2009, 11:51:06 am
If they do not specify 'in simplest form', you can leave it as it was.
+1
I read the instructions 10 times.
Post by: lynt.br on November 06, 2009, 11:51:17 am
sigh....
Post by: THem on November 06, 2009, 11:52:45 am
Lose 1 for answer mark I reckon.Awesome :)
I think that puts me at 38, highly doubt my explanation for 10B was sufficient :|
Post by: simpak on November 06, 2009, 11:53:29 am
Lose 1 for answer mark I reckon.Awesome :)
I think that puts me at 38, highly doubt my explanation for 10B was sufficient :|
I wrote like, two different things, but I think I was too vague.
Should have done a graph like TrueTears.
Silly.
Post by: avram_grant on November 06, 2009, 11:54:14 am
Post by: nala on November 06, 2009, 11:54:33 am
Post by: TrueTears on November 06, 2009, 11:55:13 am
yo, for the inverse function question, a hyperbola is a fuction anyways and since they didnt ask for a domain, you wouldnt lose marks would you? If you look at the 06 exam, it asks to find the rule and then an alternative part asks to find the domain - so will i lose a mark?Yes you'd definitely lose a mark if you didn't state domain.
A function is defined by the rule AND domain, since the question asked for the FUNCTION, a domain and rule must be given.
Post by: tomygun_123 on November 06, 2009, 11:56:15 am
Post by: simpak on November 06, 2009, 11:56:33 am
It's okay if you just wrote down the domain and the rule separately?
Post by: TrueTears on November 06, 2009, 11:57:06 am
But function notation wasn't specifically required right?Yeah I said that in the solutions, "...Note function notation is not necessary but a rule and domain must be given..." :P
It's okay if you just wrote down the domain and the rule separately?
Post by: avram_grant on November 06, 2009, 11:57:48 am
Post by: simpak on November 06, 2009, 11:57:59 am
But function notation wasn't specifically required right?Yeah I said that in the solutions, "...Note function notation is not necessary but a rule and domain must be given..." :P
It's okay if you just wrote down the domain and the rule separately?
Oops! Sorry, I was skimming >.<
Thanks anyway, your solutions are awesome :)
Post by: naved_s9994 on November 06, 2009, 11:58:46 am
Personally I dropped 2 marks according to TT solutions.
Post by: TrueTears on November 06, 2009, 11:59:03 am
if you look at the 06 exam, the first part says find the rule, and the examiners report doesnt state the domainYeah... the question asked for the rule...
Whereas this one asks for the function.
Post by: hard on November 06, 2009, 11:59:43 am
Post by: naved_s9994 on November 06, 2009, 12:00:05 pm
if you look at the 06 exam, the first part says find the rule, and the examiners report doesnt state the domainYeah... the question asked for the rule...
Whereas this one asks for the function.
I wrote the domain aswell
Post by: TrueTears on November 06, 2009, 12:00:40 pm
you know for q 2 if i didn't simplify cos(pi) and sin(pi) to like 1 or -1 or whatever and left it as a long answer and i got the first and second part right would i get 2/3?yeh lose 1 mark for answer mark I guess.
Post by: avram_grant on November 06, 2009, 12:01:18 pm
if you look at the 06 exam, the first part says find the rule, and the examiners report doesnt state the domainYeah... the question asked for the rule...
Whereas this one asks for the function.
Question 2
For the function f : R → R, f (x) = 3e2x – 1,
a. Þ nd the rule for the inverse function f −1
that is the question from the 06 exam - in the examiners report they do not include the domain....
Post by: chima987 on November 06, 2009, 12:02:02 pm
Post by: bloodboy on November 06, 2009, 12:02:11 pm
Post by: almostatrap on November 06, 2009, 12:03:26 pm
Thanks for the solutions!
for q10. I wrote out x=8, h=0.06, f(x)=blah and f'(x)=blah all correctly
then i accidentally subbed in 2 instead of 8 for f'(x), giving a wrong answer. how many marks would i lose, out of 4marks?
Post by: nala on November 06, 2009, 12:03:48 pm
Post by: hyperblade01 on November 06, 2009, 12:03:53 pm
if you look at the 06 exam, the first part says find the rule, and the examiners report doesnt state the domain
Because they asked for the RULE
This year they said FUNCTION which means rule AND domain
Yeah... the question asked for the rule...
Whereas this one asks for the function.
Question 2
For the function f : R → R, f (x) = 3e2x – 1,
a. Þ nd the rule for the inverse function f −1
that is the question from the 06 exam - in the examiners report they do not include the domain....
They asked for the RULE then
This year they asked for the function which means rule AND domain
Post by: TrueTears on November 06, 2009, 12:04:00 pm
Hey True Tears, what if you left C in there, would that be considered an antiderivative?Technically you should have made c = 0 or some other constant but I don't think examiner are that tight to take a mark off if you left +c...
Post by: TrueTears on November 06, 2009, 12:04:34 pm
Yeah... cause it asks for the RULE not the FUNCTION.if you look at the 06 exam, the first part says find the rule, and the examiners report doesnt state the domainYeah... the question asked for the rule...
Whereas this one asks for the function.
Question 2
For the function f : R → R, f (x) = 3e2x – 1,
a. Þ nd the rule for the inverse function f −1
that is the question from the 06 exam - in the examiners report they do not include the domain....
There's a huge difference b/w "find the rule of the function" and "find the inverse function"
EDIT: hyperblade beat me to it :P
Post by: naved_s9994 on November 06, 2009, 12:07:45 pm
I left C in the antiderivative, but specified that c = any real number.
it said AN, hence no C
Post by: nala on November 06, 2009, 12:09:21 pm
Is that a 1-mark deduction or 2-mark deduction out of 3?
Post by: Chocolate01 on November 06, 2009, 12:10:00 pm
Post by: TrueTears on November 06, 2009, 12:10:03 pm
For the tan(2x) question (I can't remember which one it was), I ended up with the 2 correct answers (pi/6 and 2pi/3), but I also has -pi/6 as an answer (no idea why- i think my brain went slow for that question :P).
Is that a 1-mark deduction or 2-mark deduction out of 3?
1 mark yes. Just for answer :)
Post by: purelemon on November 06, 2009, 12:10:32 pm
Post by: MiCCAS on November 06, 2009, 12:15:02 pm
Post by: TrueTears on November 06, 2009, 12:15:40 pm
Is it worth me uploading a blank copy of the exam?Yeah that would be good, link me I'll upload in the OP if you want :)
Post by: Over9000 on November 06, 2009, 12:17:17 pm
Why shud we state it?
Its already implied, thus I conclude there is no need for it.
Post by: naved_s9994 on November 06, 2009, 12:18:35 pm
If the implied domain of y = 3/(x+4) is R\{-4}LOL !!
Why shud we state it?
Its already implied, thus I conclude there is no need for it.
Yea, I only wrote the domain because I had over 25 mins of "Review" time. Otherwise I wouldn't have aswell.
[BUT, its really DODGY]
Post by: TrueTears on November 06, 2009, 12:19:22 pm
If the implied domain of y = 3/(x+4) is R\{-4}But a function is composed of a rule and a domain. Even if it's implied a domain must be written. Basically state the obvious.
Why shud we state it?
Its already implied, thus I conclude there is no need for it.
Post by: Over9000 on November 06, 2009, 12:20:40 pm
I wrote the domain, its just that if its implied as the book always says then wtf shud we write it even if they ask?If the implied domain of y = 3/(x+4) is R\{-4}LOL !!
Why shud we state it?
Its already implied, thus I conclude there is no need for it.
Yea, I only wrote the domain because I had over 25 mins of "Review" time. Otherwise I wouldn't have aswell.
[BUT, its really DODGY]
Its like 1x = x, its implied 1 is coefficient. So if they then asked what is coefficient of x id say gtfo
Post by: TrueTears on November 06, 2009, 12:21:31 pm
Complain with the history of maths then. Change history :)I wrote the domain, its just that if its implied as the book always says then wtf shud we write it even if they ask?If the implied domain of y = 3/(x+4) is R\{-4}LOL !!
Why shud we state it?
Its already implied, thus I conclude there is no need for it.
Yea, I only wrote the domain because I had over 25 mins of "Review" time. Otherwise I wouldn't have aswell.
[BUT, its really DODGY]
Its like 1x = x, its implied 1 is coefficient. So if they then asked what is coefficient of x id say gtfo
Post by: naved_s9994 on November 06, 2009, 12:22:20 pm
I wrote the domain, its just that if its implied as the book always says then wtf shud we write it even if they ask?If the implied domain of y = 3/(x+4) is R\{-4}LOL !!
Why shud we state it?
Its already implied, thus I conclude there is no need for it.
Yea, I only wrote the domain because I had over 25 mins of "Review" time. Otherwise I wouldn't have aswell.
[BUT, its really DODGY]
Its like 1x = x, its implied 1 is coefficient. So if they then asked what is coefficient of x id say gtfo
Yea, I reckon they'll be a bit lenient
Post by: mankay on November 06, 2009, 12:22:49 pm
Isn't Pr(2nd ball = 1 |_| Sum = 5 ) = 1/4, NOT 1/12
Post by: tl on November 06, 2009, 12:24:04 pm
Post by: TrueTears on November 06, 2009, 12:24:26 pm
For 5(c):I wrote
Isn't Pr(2nd ball = 1 |_| Sum = 5 ) = 1/4, NOT 1/12
Post by: byrons_12 on November 06, 2009, 12:25:16 pm
Post by: TrueTears on November 06, 2009, 12:25:30 pm
Nah a mark will be taken off for sure if you didn't state domain and equation. Study design specifically says when a function is required a rule and domain must be given. No leniency whatsoever.I wrote the domain, its just that if its implied as the book always says then wtf shud we write it even if they ask?If the implied domain of y = 3/(x+4) is R\{-4}LOL !!
Why shud we state it?
Its already implied, thus I conclude there is no need for it.
Yea, I only wrote the domain because I had over 25 mins of "Review" time. Otherwise I wouldn't have aswell.
[BUT, its really DODGY]
Its like 1x = x, its implied 1 is coefficient. So if they then asked what is coefficient of x id say gtfo
Yea, I reckon they'll be a bit lenient
Post by: TrueTears on November 06, 2009, 12:26:05 pm
For 2a) if the part inside the log is not modulus is it considered incorrect?Yeah incorrect since you could end up with a negative value :P
Post by: hard on November 06, 2009, 12:26:16 pm
For 5(c):samee
Isn't Pr(2nd ball = 1 |_| Sum = 5 ) = 1/4, NOT 1/12
Post by: Yoshi on November 06, 2009, 12:30:29 pm
Post by: simplicity123 on November 06, 2009, 12:31:14 pm
Post by: TrueTears on November 06, 2009, 12:32:44 pm
hm just wondering for the integral question with limits 1 to 4, i put 23/3 unit sq, would they penalise me for that?lol nah doesn't really matter, won't lose anything there :)
[It actually is an area anyway haha]
Post by: simplicity123 on November 06, 2009, 12:33:37 pm
Post by: googoo on November 06, 2009, 12:35:15 pm
Post by: NE2000 on November 06, 2009, 12:37:31 pm
Yeah it was pretty easy. TT for the last question I said the gradient function was a decreasing one as x gets larger so the real rate of change is < the approximated rate of change and hence the real value is less than the approximate value. That's cool yeah? I think the graph you did was a good way to show it, but I think stating it was an overestimate without the graph may not be sufficient.
Post by: 10weid on November 06, 2009, 12:37:42 pm
Post by: TrueTears on November 06, 2009, 12:39:39 pm
I'm pretty sure that you need to give the domain lol. There's something I read on a previous assessment report. Not sure which one but I'm quite sure I read something where it asked for the inverse function and you need to give the domain.Yeah in the exam I wrote way more than I did in the solutions haha. I actually said that since the
Yeah it was pretty easy. TT for the last question I said the gradient function was a decreasing one as x gets larger so the real rate of change is < the approximated rate of change and hence the real value is less than the approximate value. That's cool yeah? I think the graph you did was a good way to show it, but I think stating it was an overestimate without the graph may not be sufficient.
And yeah your way is fine. I like the wording xD
Post by: NE2000 on November 06, 2009, 12:40:21 pm
Post by: 10weid on November 06, 2009, 12:43:37 pm
39 is def a+ right?
Post by: moekamo on November 06, 2009, 12:44:24 pm
Nah a mark will be taken off for sure if you didn't state domain and equation. Study design specifically says when a function is required a rule and domain must be given. No leniency whatsoever.I wrote the domain, its just that if its implied as the book always says then wtf shud we write it even if they ask?If the implied domain of y = 3/(x+4) is R\{-4}LOL !!
Why shud we state it?
Its already implied, thus I conclude there is no need for it.
Yea, I only wrote the domain because I had over 25 mins of "Review" time. Otherwise I wouldn't have aswell.
[BUT, its really DODGY]
Its like 1x = x, its implied 1 is coefficient. So if they then asked what is coefficient of x id say gtfo
Yea, I reckon they'll be a bit lenient
where in the study design does it say this?
Post by: dezz on November 06, 2009, 12:45:50 pm
dont know how i managed that. :'(
argh, my blindness.
but yea paper was pretty easy, finished in 25minutes. argh hope i dont loose to many marks for the approximation.
Post by: NE2000 on November 06, 2009, 12:47:20 pm
http://www.vcaa.vic.edu.au/vce/studies/mathematics/methods/assessreports/2007/mm2_assessrep_07.pdf
Q4bi.
The question itself was specifically no more or more less than "find the inverse function h-1"
Post by: charley on November 06, 2009, 12:48:08 pm
Post by: TrueTears on November 06, 2009, 12:48:40 pm
Nah a mark will be taken off for sure if you didn't state domain and equation. Study design specifically says when a function is required a rule and domain must be given. No leniency whatsoever.I wrote the domain, its just that if its implied as the book always says then wtf shud we write it even if they ask?If the implied domain of y = 3/(x+4) is R\{-4}LOL !!
Why shud we state it?
Its already implied, thus I conclude there is no need for it.
Yea, I only wrote the domain because I had over 25 mins of "Review" time. Otherwise I wouldn't have aswell.
[BUT, its really DODGY]
Its like 1x = x, its implied 1 is coefficient. So if they then asked what is coefficient of x id say gtfo
Yea, I reckon they'll be a bit lenient
where in the study design does it say this?
Quote from: Methods (CAS) 3/4 Study Design
the concept of an inverse function, connection between domain and range of the original function
and its inverse and the conditions for existence of an inverse function
Post by: NE2000 on November 06, 2009, 12:49:37 pm
On q6 did the depth mean anything for the related rates or was it just a bit of info that was irrelevent?
It wasn't 'irrelevant' in that the equation for volume that you are given includes it. But it wasn't a piece of info you specifically use. I think it was just to tell people that the puddle won't be rising at all with the extra liquid
Post by: c23 on November 06, 2009, 12:49:59 pm
for 1b)
i had 2(pie)/(2pie+2)^2
and i simplified it to 1/(pie+1)^2
is that still right? :S
Post by: TrueTears on November 06, 2009, 12:50:06 pm
On q6 did the depth mean anything for the related rates or was it just a bit of info that was irrelevent?It's doesn't really contribute to the question heh
It's just... there
Post by: d0minicz on November 06, 2009, 12:50:55 pm
how many marksyou think ill lose for using .6 instead of .06 on the approximation question?did the same bloody thing fks sake mate lols
dont know how i managed that. :'(
argh, my blindness.
but yea paper was pretty easy, finished in 25minutes. argh hope i dont loose to many marks for the approximation.
Post by: krzysiek on November 06, 2009, 12:55:18 pm
Post by: moekamo on November 06, 2009, 12:55:53 pm
Nah a mark will be taken off for sure if you didn't state domain and equation. Study design specifically says when a function is required a rule and domain must be given. No leniency whatsoever.I wrote the domain, its just that if its implied as the book always says then wtf shud we write it even if they ask?If the implied domain of y = 3/(x+4) is R\{-4}LOL !!
Why shud we state it?
Its already implied, thus I conclude there is no need for it.
Yea, I only wrote the domain because I had over 25 mins of "Review" time. Otherwise I wouldn't have aswell.
[BUT, its really DODGY]
Its like 1x = x, its implied 1 is coefficient. So if they then asked what is coefficient of x id say gtfo
Yea, I reckon they'll be a bit lenient
where in the study design does it say this?Quote from: Methods (CAS) 3/4 Study Designthe concept of an inverse function, connection between domain and range of the original function
and its inverse and the conditions for existence of an inverse function
i take that as saying the connection between domain and range is that they swap when you find the inverse, and the conditions for an inverse are that it is one-to-one... nothing about 'you must state domain when stating a function'
Post by: avram_grant on November 06, 2009, 01:00:16 pm
Nah a mark will be taken off for sure if you didn't state domain and equation. Study design specifically says when a function is required a rule and domain must be given. No leniency whatsoever.I wrote the domain, its just that if its implied as the book always says then wtf shud we write it even if they ask?If the implied domain of y = 3/(x+4) is R\{-4}LOL !!
Why shud we state it?
Its already implied, thus I conclude there is no need for it.
Yea, I only wrote the domain because I had over 25 mins of "Review" time. Otherwise I wouldn't have aswell.
[BUT, its really DODGY]
Its like 1x = x, its implied 1 is coefficient. So if they then asked what is coefficient of x id say gtfo
Yea, I reckon they'll be a bit lenient
where in the study design does it say this?Quote from: Methods (CAS) 3/4 Study Designthe concept of an inverse function, connection between domain and range of the original function
and its inverse and the conditions for existence of an inverse function
i take that as saying the connection between domain and range is that they swap when you find the inverse, and the conditions for an inverse are that it is one-to-one... nothing about 'you must state domain when stating a function'
a hyperbola is a function regardless of the domain..... i really dont think you will need to say that x/{-4} to be honest, and im sure a number of schools would complain if they did take a mark off. ..
Post by: sdhains on November 06, 2009, 01:00:36 pm
Post by: TrueTears on November 06, 2009, 01:01:08 pm
Think what you want. I've said countless times, a function is defined by having a rule and a domain. If you don't wanna take that it's your problem.Nah a mark will be taken off for sure if you didn't state domain and equation. Study design specifically says when a function is required a rule and domain must be given. No leniency whatsoever.I wrote the domain, its just that if its implied as the book always says then wtf shud we write it even if they ask?If the implied domain of y = 3/(x+4) is R\{-4}LOL !!
Why shud we state it?
Its already implied, thus I conclude there is no need for it.
Yea, I only wrote the domain because I had over 25 mins of "Review" time. Otherwise I wouldn't have aswell.
[BUT, its really DODGY]
Its like 1x = x, its implied 1 is coefficient. So if they then asked what is coefficient of x id say gtfo
Yea, I reckon they'll be a bit lenient
where in the study design does it say this?Quote from: Methods (CAS) 3/4 Study Designthe concept of an inverse function, connection between domain and range of the original function
and its inverse and the conditions for existence of an inverse function
i take that as saying the connection between domain and range is that they swap when you find the inverse, and the conditions for an inverse are that it is one-to-one... nothing about 'you must state domain when stating a function'
btw notice how the study design says an inverse function which implies a domain must be given if you're asked to find the inverse FUNCTION.
Post by: avram_grant on November 06, 2009, 01:02:05 pm
Post by: mankay on November 06, 2009, 01:03:17 pm
for the last question, if your answer was the following, do you think one would gain the mark?
-the approxmiation f(x+5) ... relies on a small value of h
-as h (0.06) is not small enough, i.e. too large, the approxmiation will be inaccurate.
-therefore, the approxmiated value will be greater than the exact value of 8.06^1/3
Post by: goinggreen91 on November 06, 2009, 01:04:43 pm
Post by: rohanftw on November 06, 2009, 01:05:37 pm
A question for TT,
for the last question, if your answer was the following, do you think one would gain the mark?
-the approxmiation f(x+5) ... relies on a small value of h
-as h (0.06) is not small enough, i.e. too large, the approxmiation will be inaccurate.
-therefore, the approxmiated value will be greater than the exact value of 8.06^1/3
Nah, even if a far smaller h was chosen the same thing would have occurred. I think something along the lines of decreasing gradient, or gradient approaching 0 was needed.
Post by: krzysiek on November 06, 2009, 01:06:14 pm
jokes :( :D
Post by: TrueTears on November 06, 2009, 01:06:26 pm
A question for TT,Yeap that's fine, that's what approximation/integration is all about, making the 'h' infinitely small for integration, thus the larger it gets the more inaccurate. However I think you should have mentioned what NE2000 said because having a large h doesn't always mean overestimate, it could mean underestimate. However given the question was 1 mark, I think that should suffice.
for the last question, if your answer was the following, do you think one would gain the mark?
-the approxmiation f(x+5) ... relies on a small value of h
-as h (0.06) is not small enough, i.e. too large, the approxmiation will be inaccurate.
-therefore, the approxmiated value will be greater than the exact value of 8.06^1/3
Post by: Yoshi on November 06, 2009, 01:07:37 pm
Hey for question 2b I messed up my integral, divided x by 1/2 rather than 3/2. Have I lost all three marks for that stupid error?
Sorry for self quoting but does anyone know? Do I at least get something for showing I know how a definite integral works? :-\
Post by: NE2000 on November 06, 2009, 01:07:50 pm
http://www.vcaa.vic.edu.au/vce/studies/mathematics/methods/assessreports/2007/mm2_assessrep_07.pdf
Q4bi. : you had to find the domain for the final mark
The question itself was specifically no more or more less than "find the inverse function h-1"
----------------
Had to repeat this post lol seeing as the argument rages on
Post by: mankay on November 06, 2009, 01:07:55 pm
Post by: NE2000 on November 06, 2009, 01:08:39 pm
Hey for question 2b I messed up my integral, divided x by 1/2 rather than 3/2. Have I lost all three marks for that stupid error?
Sorry for self quoting but does anyone know? Do I at least get something for showing I know how a definite integral works? :-\
No you would not have lost all three marks. You may have lost 2 as one methods mark would probably be integrating correctly
Post by: mankay on November 06, 2009, 01:08:49 pm
Post by: Yoshi on November 06, 2009, 01:12:21 pm
Post by: nadine on November 06, 2009, 01:15:10 pm
Post by: jrdaniell on November 06, 2009, 01:16:25 pm
Post by: cjays66 on November 06, 2009, 01:17:21 pm
OK stop raging at TT :PMany students did not give the domain. It is important that students realise that a function consists of two parts – the
http://www.vcaa.vic.edu.au/vce/studies/mathematics/methods/assessreports/2007/mm2_assessrep_07.pdf
Q4bi. : you had to find the domain for the final mark
The question itself was specifically no more or more less than "find the inverse function h-1"
----------------
Had to repeat this post lol seeing as the argument rages on
domain and the rule.
Post by: 10weid on November 06, 2009, 01:18:28 pm
if i didnt write the domain in the form R/(-4) ,
rather i wrote the inverse, x ≠ -4 ,
do i get the mark for the domain?
Post by: majo on November 06, 2009, 01:18:39 pm
to get a raw score of 30 in mm, what scores do u need to get?
Post by: dezz on November 06, 2009, 01:19:30 pm
how many marksyou think ill lose for using .6 instead of .06 on the approximation question?
dont know how i managed that. :'(
argh, my blindness.
but yea paper was pretty easy, finished in 25minutes. argh hope i dont loose to many marks for the approximation.
just raising my unanswered question again :)
also, would you lose any marks for not putting a modulus for the log antidiff question? :'(
argh stupid mistakes.
Post by: TrueTears on November 06, 2009, 01:19:41 pm
TT,Should be fine IMO,
if i didnt write the domain in the form R/(-4) ,
rather i wrote the inverse, x ≠ -4 ,
do i get the mark for the domain?
Post by: TrueTears on November 06, 2009, 01:19:59 pm
Yeah you'd lose 1 mark.how many marksyou think ill lose for using .6 instead of .06 on the approximation question?
dont know how i managed that. :'(
argh, my blindness.
but yea paper was pretty easy, finished in 25minutes. argh hope i dont loose to many marks for the approximation.
just raising my unanswered question again :)
also, would you lose any marks for not putting a modulus for the log antidiff question? :'(
argh stupid mistakes.
Post by: jrdaniell on November 06, 2009, 01:21:02 pm
Post by: TrueTears on November 06, 2009, 01:21:41 pm
TT, in the log equation with x, are you certain that x must be greater than zero, for there is a 2 out the front and the question stated no domain, thus -1 should be a perfectly acceptable answer as well as 3/2.Have a read here: http://vcenotes.com/forum/index.php/topic,19334.msg195054.html#msg195054
Post by: dezz on November 06, 2009, 01:22:35 pm
Yeah you'd lose 1 mark.how many marksyou think ill lose for using .6 instead of .06 on the approximation question?
dont know how i managed that. :'(
argh, my blindness.
but yea paper was pretty easy, finished in 25minutes. argh hope i dont loose to many marks for the approximation.
just raising my unanswered question again :)
also, would you lose any marks for not putting a modulus for the log antidiff question? :'(
argh stupid mistakes.
1mark for the .6 thing? or 1 for the log part.?
or both :|
i was expecting to lose 2marks for the .6 one. hopefully only one :|
Post by: nadine on November 06, 2009, 01:23:31 pm
Post by: TrueTears on November 06, 2009, 01:23:48 pm
1 for log. I'm not too sure myself on the 0.6 one.Yeah you'd lose 1 mark.how many marksyou think ill lose for using .6 instead of .06 on the approximation question?
dont know how i managed that. :'(
argh, my blindness.
but yea paper was pretty easy, finished in 25minutes. argh hope i dont loose to many marks for the approximation.
just raising my unanswered question again :)
also, would you lose any marks for not putting a modulus for the log antidiff question? :'(
argh stupid mistakes.
1mark for the .6 thing? or 1 for the log part.?
or both :|
i was expecting to lose 2marks for the .6 one. hopefully only one :|
Post by: cjays66 on November 06, 2009, 01:24:32 pm
Post by: dezz on November 06, 2009, 01:25:00 pm
alright thanks, you would think it would be no more than 2 marks yea?1 for log. I'm not too sure myself on the 0.6 one.Yeah you'd lose 1 mark.how many marksyou think ill lose for using .6 instead of .06 on the approximation question?
dont know how i managed that. :'(
argh, my blindness.
but yea paper was pretty easy, finished in 25minutes. argh hope i dont loose to many marks for the approximation.
just raising my unanswered question again :)
also, would you lose any marks for not putting a modulus for the log antidiff question? :'(
argh stupid mistakes.
1mark for the .6 thing? or 1 for the log part.?
or both :|
i was expecting to lose 2marks for the .6 one. hopefully only one :|
1mark for answer, and 1 for screwing up a number in the working?
the rest would be fine imo.
Post by: THem on November 06, 2009, 01:25:21 pm
Post by: TrueTears on November 06, 2009, 01:25:33 pm
Yeah probs 2.alright thanks, you would think it would be no more than 2 marks yea?1 for log. I'm not too sure myself on the 0.6 one.Yeah you'd lose 1 mark.how many marksyou think ill lose for using .6 instead of .06 on the approximation question?
dont know how i managed that. :'(
argh, my blindness.
but yea paper was pretty easy, finished in 25minutes. argh hope i dont loose to many marks for the approximation.
just raising my unanswered question again :)
also, would you lose any marks for not putting a modulus for the log antidiff question? :'(
argh stupid mistakes.
1mark for the .6 thing? or 1 for the log part.?
or both :|
i was expecting to lose 2marks for the .6 one. hopefully only one :|
1mark for answer, and 1 for screwing up a number in the working?
the rest would be fine imo.
Post by: nadine on November 06, 2009, 01:25:47 pm
Post by: dezz on November 06, 2009, 01:31:31 pm
so many stupid little mistakes...
using .6 instead of .06
not including domain in inverse function question
not including modulus in log question.
dont think my answer for the very last question was enough..
and also just realised i didnt simply 6/9 to 2/3 in the probabilty question
wtf was i doing... :|
ARGH
roughly how many marks can i afford to lose in exam 2 for a RAW 40?
thanks.
Post by: matthew_potato on November 06, 2009, 01:32:26 pm
it's not what the answers say, but do you think i'll get the mark? or is what i wrote even true?
Post by: mystikal on November 06, 2009, 01:33:58 pm
im guessing 40 RAW isnt really possible with a mid - low A on exam 1 ?:|
so many stupid little mistakes...
using .6 instead of .06
not including domain in inverse function question
not including modulus in log question.
dont think my answer for the very last question was enough..
and also just realised i didnt simply 6/9 to 2/3 in the probabilty question
wtf was i doing... :|
ARGH
roughly how many marks can i afford to lose in exam 2 for a RAW 40?
thanks.
it depends on how hard the exam 2 is and how you went on sac's its still very possible to get 40+ RAW methods with an A on exam 1, if you have like high A's for SAC's and A+ (mid - high (so you can afford to lose like 7-8 marks)) then you can still get 40+ RAW
Post by: cjays66 on November 06, 2009, 01:34:55 pm
Did that also, i don't think we would lose marks though...
and also just realised i didnt simply 6/9 to 2/3 in the probabilty question
wtf was i doing... :|
ARGH
Post by: VeryCrazyEdu. on November 06, 2009, 01:37:10 pm
ggaahhh i was going to but decided against it
i lost a mark for question s- forgot the -1/2 out the front
the domain and range for the inverse function
i included -1 in my answer for the log question and there is no way i got a mark for my explanation at the end :(
heres hoping the a+ cut off is 36/40 haha :D
Post by: TrueTears on November 06, 2009, 01:38:22 pm
will we definately lose a mark for NOT stating domain and range?? for the inverse function :(You didn't have to state range for the inverse function. But yes you'd definitely lose a mark for not stating domain.
ggaahhh i was going to but decided against it
i lost a mark for question s- forgot the -1/2 out the front
the domain and range for the inverse function
i included -1 in my answer for the log question and there is no way i got a mark for my explanation at the end :(
heres hoping the a+ cut off is 36/40 haha :D
Post by: dejan91 on November 06, 2009, 01:39:11 pm
Post by: dejan91 on November 06, 2009, 01:39:51 pm
Post by: chinx_4eva on November 06, 2009, 01:53:03 pm
i realised that it was 'an anti-derivitive'
but i did not state c AT ALL .. totally left it out, was not mentioned.
would i lose a mark for that ? :(
Post by: Gloamglozer on November 06, 2009, 01:55:37 pm
for the anti-derivative question (question 2 )
i realised that it was 'an anti-derivitive'
but i did not state c AT ALL .. totally left it out, was not mentioned.
would i lose a mark for that ? :(
No. It said, "an anti-derivative".
Post by: rohanftw on November 06, 2009, 01:57:00 pm
A question for TT,Yeap that's fine, that's what approximation/integration is all about, making the 'h' infinitely small for integration, thus the larger it gets the more inaccurate. However I think you should have mentioned what NE2000 said because having a large h doesn't always mean overestimate, it could mean underestimate. However given the question was 1 mark, I think that should suffice.
for the last question, if your answer was the following, do you think one would gain the mark?
-the approxmiation f(x+5) ... relies on a small value of h
-as h (0.06) is not small enough, i.e. too large, the approxmiation will be inaccurate.
-therefore, the approxmiated value will be greater than the exact value of 8.06^1/3
Umm are you sure? Saying the h value was too large only explains why it isn't a perfect exact answer... They explicitly requested why "this approximate value is greater than the exact value for...". I would have thought some reference to decreasing gradient was necessary.
Post by: tomygun_123 on November 06, 2009, 01:59:17 pm
Post by: Blitz on November 06, 2009, 01:59:51 pm
Post by: GerrySly on November 06, 2009, 02:01:41 pm
1. No modulus in Q2a, -1 mark?
2. Forgetting to divide
2. Not squaring the mean Q7b, -1 mark?
3. Not discarding the negative Q9, -1 mark?
And my explanation on 10b was probably silly (as h is a large value than the exact value then our estimation will be larger)
Overall the exam was nice, too bad I didn't pick up on all those silly mistakes haha, nice work on these solutions TT :)
Post by: Ghost on November 06, 2009, 02:03:35 pm
38/40
Post by: TrueTears on November 06, 2009, 02:05:09 pm
That's why I said "...However I think you should have mentioned what NE2000 said because having a large h doesn't always mean overestimate, it could mean underestimate."A question for TT,Yeap that's fine, that's what approximation/integration is all about, making the 'h' infinitely small for integration, thus the larger it gets the more inaccurate. However I think you should have mentioned what NE2000 said because having a large h doesn't always mean overestimate, it could mean underestimate. However given the question was 1 mark, I think that should suffice.
for the last question, if your answer was the following, do you think one would gain the mark?
-the approxmiation f(x+5) ... relies on a small value of h
-as h (0.06) is not small enough, i.e. too large, the approxmiation will be inaccurate.
-therefore, the approxmiated value will be greater than the exact value of 8.06^1/3
Umm are you sure? Saying the h value was too large only explains why it isn't a perfect exact answer... They explicitly requested why "this approximate value is greater than the exact value for...". I would have thought some reference to decreasing gradient was necessary.
Post by: kdgamz on November 06, 2009, 02:09:27 pm
Alright just a few clarifications...
1. No modulus in Q2a, -1 mark?
we cudnt possibly lose a mark? i mean its not spesh, i know it makes sense for us to lose a mark...but that wud be ruthless, surely VCAA cant do that... :(
Post by: iwakura on November 06, 2009, 02:12:25 pm
would that get a mark? i cant open your solutions since im on the mac :(
Post by: TrueTears on November 06, 2009, 02:23:00 pm
hey i think i wrote for q10 something like "the limit of h as h->0, f(x+h)-> f(x) so the higher the 'h-value' the margin of error too increases"I had a diagram for mine ^.^ and some words explaining etc.
would that get a mark? i cant open your solutions since im on the mac :(
You got the general jist of it but you need to also mention why it's greater since the higher the h-value could also mean underestimate :P
NE2000 has an awesome response and without a diagram I think you need to state what he said.
Post by: rohanftw on November 06, 2009, 02:26:20 pm
That's why I said "...However I think you should have mentioned what NE2000 said because having a large h doesn't always mean overestimate, it could mean underestimate."
Yeah I saw that bit and I agree haha; just debating whether an answer solely referring to a large h value would be worth the one mark, as it doesn't really address specifically what the question is asking.
Post by: Gloamglozer on November 06, 2009, 02:36:20 pm
Post by: YT_17 on November 06, 2009, 02:40:35 pm
Post by: steph_r on November 06, 2009, 02:47:07 pm
High A+ sacs
High B+ exam1
B+ exam 2
Post by: squance on November 06, 2009, 02:51:51 pm
Post by: matthew_potato on November 06, 2009, 03:14:36 pm
for the last question i said that the approx formula was an existing val (2) + the area (rectangle) under the differential curve that is (f'(8) x h). where h is the width, i then drew a differential graph (no tangents) with the area shown and stated that because the approx area is bigger, the approx value was bigger then original
it's not what the answers say, but do you think i'll get the mark? or is what i wrote even true?
Post by: NE2000 on November 06, 2009, 03:16:43 pm
Post by: matthew_potato on November 06, 2009, 03:19:56 pm
yeah I don't think what you say is actually true. It doesn't actually use the area, it uses tangents :S
hmm, true,, didn't really have any idea how to answer that so i just made up something that sounded "right" lol, oh well, 37/40's not bad yeah?
Post by: nala on November 06, 2009, 03:21:41 pm
Post by: matthew_potato on November 06, 2009, 03:30:32 pm
37/40 is good! That's either really high A or low A+ depending on the grade distributions. :)
yeah,,, just as long as its not like the physics midyear :P
Post by: makemytime on November 06, 2009, 03:37:17 pm
37/40 is good! That's either really high A or low A+ depending on the grade distributions. :)
yeah,,, just as long as its not like the physics midyear :P
yeah.... 95% was minimum for A+... :( i had 90% and it was only an A
just wondering, for question 2a) if i did not place modulus signs, would i lose a mark?
Post by: TrueTears on November 06, 2009, 03:41:42 pm
Post by: simpak on November 06, 2009, 04:00:13 pm
If they give it to you that way, then that's the way they'd want it when you apply the formula.
Post by: dcc on November 06, 2009, 04:13:06 pm
Post by: nels on November 06, 2009, 04:13:27 pm
Post by: nala on November 06, 2009, 04:22:22 pm
Post by: simpak on November 06, 2009, 04:38:51 pm
To do that question, if I'm not mistaken, the probability acquired in b was required in c.
If you worked out c correctly using the answer you obtained in b, then I thought you get consequential marks and method marks.
Your answer is consequential.
Post by: jasrulz63 on November 06, 2009, 04:50:28 pm
Post by: TrueTears on November 06, 2009, 04:50:46 pm
Want it into a PDF again TT?That would be greatly appreciated! Thanks xD
I'll post link up in OP.
Post by: jasrulz63 on November 06, 2009, 04:55:19 pm
msg195356 date=1257486628]
That would be greatly appreciated! Thanks xD
I'll post link up in OP.
Haha same to you for doing the solutions;
http://www.mediafire.com/file/xmdjyrwniwd/TT's Suggested Solutions for Methods!.pdf
Post by: TrueTears on November 06, 2009, 04:55:51 pm
Awesome, thanks again.msg195356 date=1257486628]
That would be greatly appreciated! Thanks xD
I'll post link up in OP.
Haha same to you for doing the solutions;
http://www.mediafire.com/file/xmdjyrwniwd/TT's Suggested Solutions for Methods!.pdf
Post by: jasrulz63 on November 06, 2009, 04:56:20 pm
Post by: kamil9876 on November 06, 2009, 05:15:31 pm
I see a 'clearly' in one of the proofs - how amusing. I'm sure VCAA won't mind though. Perhaps it is clear?hah, is the use of this taboo in mathematics?
Post by: TheJosh on November 06, 2009, 05:18:27 pm
should be
Is this the right answer???
Post by: tomygun_123 on November 06, 2009, 06:28:32 pm
should be
Is this the right answer???
yeah it is
Post by: kayf on November 06, 2009, 06:58:38 pm
Lost seven marks, it looks like - not brilliant but it was always destined to be in my bottom two. I only wasted two or so hours revising, anyway.
Post by: homghomg1 on November 06, 2009, 08:45:21 pm
I'm not too sure about the h value being too big though, it's appropriate to account for inaccuracy of the approximation, but doesn't tell us why the approximation is greater, which is what the question asked. You may or may not get the mark.
Also, for the inverse function question:
"Many students did not give the domain. It is important that students realise that a function consists of two parts – the
domain and the rule."
This is a quote from VCAA 07 paper 2, where the question asked for the inverse function
You often get questions which just ask for the rule, which is why in that case you don't have to put the domain. A rule is different than a function. As VCAA said, a function consists of a rule AND a domain, so forgetting to put the domain will definitely cost a mark
Post by: TrueTears on November 06, 2009, 08:51:34 pm
I think the main point for the last question was for you to recognise that the derivative function is a decreasing one for x > 0, and the linear approximation assumes that the gradient is constant (hence the reason it's called linear approximation, straights lines have a constant gradient), and does not account for the fact that the gradient of f(x) is always decreasing for x > 0.Very well said.
I'm not too sure about the h value being too big though, it's appropriate to account for inaccuracy of the approximation, but doesn't tell us why the approximation is greater, which is what the question asked. You may or may not get the mark.
Also, for the inverse function question:
"Many students did not give the domain. It is important that students realise that a function consists of two parts – the
domain and the rule."
This is a quote from VCAA 07 paper 2, where the question asked for the inverse function
You often get questions which just ask for the rule, which is why in that case you don't have to put the domain. A rule is different than a function. As VCAA said, a function consists of a rule AND a domain, so forgetting to put the domain will definitely cost a mark