Post by: hard on November 08, 2009, 10:41:52 pm
and
how do we intergrate fractions.
and
what is an anti derivative and how do we solve it. cheers
Post by: TrueTears on November 08, 2009, 10:45:57 pm
Post by: hard on November 08, 2009, 10:48:37 pm
how did yo lose the x in the first equation. Also why is is there a modula's sign in front of the loge |x| ? is it cause you cannot log a number less than 0? so the integral of 1/x is loge|x| + c
Post by: TrueTears on November 08, 2009, 10:52:14 pm
By definitionhow did yo lose the x in the first equation. Also why is is there a modula's sign in front of the loge |x| ? is it cause you cannot log a number less than 0? so the integral of 1/x is loge|x| + c
There is a mod sign because x can not be smaller than or equal to 0.
Post by: hard on November 08, 2009, 11:35:49 pm
thankss TTBy definitionhow did yo lose the x in the first equation. Also why is is there a modula's sign in front of the loge |x| ? is it cause you cannot log a number less than 0? so the integral of 1/x is loge|x| + c
There is a mod sign because x can not be smaller than or equal to 0.
Post by: Over9000 on November 08, 2009, 11:54:15 pm
Its on the cheat sheet with the mod sign so you dont needa try and remember it, just read off the cheat sheet.how did yo lose the x in the first equation. Also why is is there a modula's sign in front of the loge |x| ? is it cause you cannot log a number less than 0? so the integral of 1/x is loge|x| + c
Post by: hard on November 09, 2009, 12:04:31 am
ahkai cheersIts on the cheat sheet with the mod sign so you dont needa try and remember it, just read off the cheat sheet.how did yo lose the x in the first equation. Also why is is there a modula's sign in front of the loge |x| ? is it cause you cannot log a number less than 0? so the integral of 1/x is loge|x| + c