ATAR Notes: Forum

Archived Discussion => 2009 => End-of-year exams => Exam Discussion => Victoria => Physics => Topic started by: Flaming_Arrow on November 11, 2009, 07:54:11 pm

Title: PHYSICS EXAM 2 SUGGESTED SOLUTIONS
Post by: Flaming_Arrow on November 11, 2009, 07:54:11 pm
Electric power:
1. alternator
2. 8.0X10^(-3)T
3. 3.6X10^(-4)V
4. diagram
5. up
6. 0.0045N
7. 0 N
8.
9.1.00X10^4W
10. 4000W
11. 300V
12. 5000VRMS
13. 480 turns
14. 40.0W
15 498VRMS
16. T=0.040s, Vpeak=50V

Light and matter:
1. interference - wave property
2.
3. Thelma, same distance, constructive, bright
4. 496nm
5.
6. h=5.0X10^(-15)eVs, Work function=1.5V (no minus)
7. i) max k. e. not affected, ii) double
8. 8.9X10^3eV
9. 4.7X10^(-24)kgms-1
10.
11. first to second, first to third
12.Whole number of standing waves around nucleus.

Synchrotron
CBCBCDDBCBACB

Photonics
CCADBCBBBCBCA

Sound
BBCBCDCCBCAAA


got it from itute
Title: Re: PHYSICS EXAM 2 SUGGESTED SOLUTIONS
Post by: ngRISING on November 11, 2009, 07:56:11 pm
LOOOOOOOOOL. I GOT 2 MC WRONG. HAHA. AWESOME (Y). your the best flaming arrows + itute.
Title: Re: PHYSICS EXAM 2 SUGGESTED SOLUTIONS
Post by: THem on November 11, 2009, 07:57:12 pm
What's question 8? - Electric power

Whats question 2,5 and 10 of light?
edit: 2 - photoelectric effect?
5 - describing ekmax, w and f?
10 - bright band explanation?
Title: Re: PHYSICS EXAM 2 SUGGESTED SOLUTIONS
Post by: poppa on November 11, 2009, 09:35:30 pm
for sound question 4, anyone 100 % sure the answer is B, not C?
Title: Re: PHYSICS EXAM 2 SUGGESTED SOLUTIONS
Post by: appianway on November 11, 2009, 09:38:40 pm
The sound answer for question 4 is definitely B. Think about what the waveform behind the displacement of 0 (presuming it's a distance from the speaker when the displacement starts being measured anyway). Most people I know put down B, and my teacher said that the answer's B.
Title: Re: PHYSICS EXAM 2 SUGGESTED SOLUTIONS
Post by: poppa on November 11, 2009, 09:42:18 pm
The sound answer for question 4 is definitely B. Think about what the waveform behind the displacement of 0 (presuming it's a distance from the speaker when the displacement starts being measured anyway). Most people I know put down B, and my teacher said that the answer's B.
thanks for the fast ans
i lost 2 marks there :(
Title: Re: PHYSICS EXAM 2 SUGGESTED SOLUTIONS
Post by: KeyMan on November 11, 2009, 10:03:15 pm
Can someone explain why question 15 is 498RMS?

I got 480V for question 15.

P = VI
10000 = 5000I
I = 2.0A

V_drop = IR
= 2.0 * 10
= 20V

500 - 20 = 480V
Title: Re: PHYSICS EXAM 2 SUGGESTED SOLUTIONS
Post by: crappy on November 11, 2009, 10:04:56 pm
Can someone explain why question 15 is 498RMS?

I got 480V for question 15.

P = VI
10000 = 5000I
I = 2.0A

V_drop = IR
= 2.0 * 10
= 20V

500 - 20 = 480V

You got 480V without the transformers Im guessing. The second part had transformers in it, so there is a massive difference in working D:
Title: Re: PHYSICS EXAM 2 SUGGESTED SOLUTIONS
Post by: /0 on November 11, 2009, 10:05:33 pm
You apply to the stepped-up voltage, since the voltage loss occurs where the voltage has been stepped up.
So the voltage delivered to the second transformer is

Then you step this down by 10x to get 498V
Title: Re: PHYSICS EXAM 2 SUGGESTED SOLUTIONS
Post by: KeyMan on November 11, 2009, 10:07:11 pm
Ah damn it! Subtracted 20 from the wrong voltage :(

Thanks for explanation.

I should get 2 out of the 3 marks though yeh? :P
Title: Re: PHYSICS EXAM 2 SUGGESTED SOLUTIONS
Post by: nem0 on November 11, 2009, 10:36:55 pm
i dont see itute answers? are they even up?
Title: Re: PHYSICS EXAM 2 SUGGESTED SOLUTIONS
Post by: majo on November 12, 2009, 02:45:25 am
i think i only lost 5 marks. I did the loop for the solenoid the wrong way, feel like such a doosh bag :(

what do you guys think will be the a+ cutoff?

i think i lost between 5 and 8. depending on how good my explanation for question 2 of light and matter!