ATAR Notes: Forum
VCE Stuff => VCE Science => VCE Mathematics/Science/Technology => VCE Subjects + Help => VCE Chemistry => Topic started by: Hielly on November 15, 2009, 02:12:30 pm
-
a sample of pond water contained 88.00 microgram g-1 of dissolved oxygen gas. calculate the amount in grams of dissolved oxygen in 4.00L of pond water.
thanks
answer says 0.352g
-
As the density of water is equal to 1, the mass of water= volume of water. So, 4 L of water= 4000 g.
m(02)= 88*10^-6 g/g water *4000 (as 1 microgram= 10^-6 g)
=0.352 g
-
As the density of water is equal to 1, the mass of water= volume of water. So, 4 L of water= 4000 g.
m(02)= 88*10^-6 g/g water *4000 (as 1 microgram= 10^-6 g)
=0.352 g
thanks i got the mass of water and solute, which is what you got. Then i subbed it in the c=mass/volume
would you say the concentration is 4000 ? from water. i got confused here
-
how did you get 4000?
-
4L = 4000mL = 4000g
-
yeah i get that part but for the concentration?
would you say the concentration is 4000 ? from water. i got confused here
-
i used the formula C= mass of solute in grams/ volume of solution in litress
so now i find C and volume of solution in litres
volume of solution in litres is 88*10^-6
and C=?
is this the right way to do it?
ignore my question samuch, i made a mistake
-
If you are doing it your way, then the concentration would be 88*10^-3 g/ L (you must change the concentration to g/L, by multiplying the concentration by 10^3, if using litres as the volume) and the volume would be 4.0L.
c=m/v
m=c*v
=88*10^-3*4
=0.352 g
-
Our teacher likes to put what we know first then what we have and what we don't know to find out the quantity of unknown such as:
We have 100g in 1000mL
We want to know xg in 1542mL
Use cross multiplication to solve for xg