ATAR Notes: Forum
VCE Stuff => VCE Mathematics => VCE Mathematics/Science/Technology => VCE Subjects + Help => VCE General & Further Mathematics => Topic started by: hifer on November 05, 2007, 01:04:56 pm
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My answers..
1. D
2. C
3. E
4. B
5. D
6. E
7. C
8. B
9. A
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Graphs and relations Q9.
Objective function: Z = 2x + ky, maximum occurs only at (100, 0).
Hence
200 = 2x + ky
y = (200 - 2x) / k
Function exists at both (100, 0) and (50, 50), this can only be true when k = B = 2 (not k = 1, A).
Unless I'm horribly wrong :(.
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got 4 or five right which is not a bad result for myself
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Graphs and relations Q9.
Objective function: Z = 2x + ky, maximum occurs only at (100, 0).
Hence
200 = 2x + ky
y = (200 - 2x) / k
Function exists at both (100, 0) and (50, 50), this can only be true when k = B = 2 (not k = 1, A).
Unless I'm horribly wrong :(.
Lol I got B for Qn 9 as well ... worked it out differently though :P
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Graphs and relations Q9.
Objective function: Z = 2x + ky, maximum occurs only at (100, 0).
Hence
200 = 2x + ky
y = (200 - 2x) / k
Function exists at both (100, 0) and (50, 50), this can only be true when k = B = 2 (not k = 1, A).
Unless I'm horribly wrong :(.
umm, if K = 2, at (50,50) Z also = 200
Which means there 2 maximums, which can't be true...
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Haha maybe, I was under the impression the function had to go through (50, 50). Apparently not. Somebody else input plz :p
on second though you are right.
scratch that, i have no idea anymore. thanks :@
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Same except for 7, which I got B.
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Damn, I originally had A for Qn9, why didn't I leave that answer!!! grr
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Same except for 7, which I got B.
how did you get B ... i got E for this question, knowing me I'm probably wrong ;[
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Okay, what I did was...
y = x^3
y = 1, x = 3
hence
1 = 3^3
therefore
y=(1/27)x^3
if we are going to x...
y=cubert(1/27)x^3
y=(1/3)x
sub in (3,1)
1=1
I would of picked E if I assumed (1/27) was a constant.
But it appears that I've done it wrong.
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Same except for 7, which I got B.
how did you get B ... i got E for this question, knowing me I'm probably wrong ;[
I got E too...but it's wrong i think
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Same except for 7, which I got B.
how did you get B ... i got E for this question, knowing me I'm probably wrong ;[
I got E too...but it's wrong i think
I got E aswell.
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Same except for 7, which I got B.
how did you get B ... i got E for this question, knowing me I'm probably wrong ;[
I got E too...but it's wrong i think
I got E aswell.
Got E too
I'm pretty sure its wrong, because the graph represents a x3 transformation already, so to undo this, you would have to square root it and not cube it again.
Meh, I've got no idea.
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Wow the 4 of us got E... hmm
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Can someone explain to me how it can't be E?
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can someone please explain why 7 is C?
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Can someone explain to me how it can't be E?
Oh i know... :shock:...surprisingly I know something :shock:
You need to use the formula y=m * x^3 + c => m= rise/run= 1/3
Therefore you get y= (1/3)x^3, making C the correct answer
Using the points in Option C (1, 1/3), you get the right answer ...
If you want me to explain it further just let me know
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Can someone explain to me how it can't be E?
Oh i know... :shock:...surprisingly I know something :shock:
You need to use the formula y=m * x^3 + c => m= rise/run= 1/3
Therefore you get y= (1/3)x^3, making C the correct answer
Correct and then you test the points from the answers, making (1, (1/3)) correct which is C.
So the correct answers are:
Graphs and Relations
1. D
2. C
3. E
4. B
5. D
6. E
7. C
8. B
9. A
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Can someone explain to me how it can't be E?
Oh i know... :shock:...surprisingly I know something :shock:
You need to use the formula y=m * x^3 + c => m= rise/run= 1/3
Therefore you get y= (1/3)x^3, making C the correct answer
Correct and then you test the points from the answers, making (1, (1/3)) correct which is C.
So the correct answers are:
Graphs and Relations
1. D
2. C
3. E
4. B
5. D
6. E
7. C
8. B
9. A
ohhh, i hope i quoted this thingy right haha
ok, graphs and realtions, q6) E?
why E? wouldn't it be B?
I stuffed up question 7 haha, woopsie, i didn't see that the x axis had already been transformed
did anyone find this years exams so much harder than expected
i cried afterwards
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It's E because he needs to make AT LEAST twice as many bottles of RED wine (x) as white wine (y)
Therefore its x>/= 2y
Ok ok im going now people, adios =]
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I find its sometimes easier to consider them equal before thinking about the inequality, for example:
"This year he plans to make twice as many bottles of red as white"
and then its easier to see that r=2w (or x=2y)
...or you could also do a diagram, and check you've got twice as much red as white.
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Oh i know... :shock:...surprisingly I know something :shock:
You need to use the formula y=m * x^3 + c => m= rise/run= 1/3
Therefore you get y= (1/3)x^3, making C the correct answer
Using the points in Option C (1, 1/3), you get the right answer ...
If you want me to explain it further just let me know
it took me a bit but i get it now. i had the gradient but i sort of lost the plot after that (plot hah - feel free to use that one lads)