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VCE Stuff => VCE Science => VCE Mathematics/Science/Technology => VCE Subjects + Help => VCE Physics => Topic started by: crappy on March 19, 2010, 02:46:12 pm

Title: The question the whole universe could not answer!!!!!!!
Post by: crappy on March 19, 2010, 02:46:12 pm

Did I get your attention?? haha

[IMG]http://img6.imageshack.us/img6/8480/78125848.jpg[/img]


anyone know how to do this using Kirchhoff's Voltage law?
Title: Re: The question the whole universe could not answer!!!!!!!
Post by: /0 on March 19, 2010, 06:14:51 pm
Haha well i won't answer but I'll start u off:

First order of business is to arbitrarily choose current directions. Just point the currents any way you like in each section.
Now, we have 5 unknown currents. So you need to travel around 5 loops to get 5 equations. (See Pic)
(Note, there is also another loop you could take - going around the outisde of the whole circuit)

The rules are:
If you travel with current, you will DROP voltage over resistors and GAIN over batteries.
If you travel against current, you will GAIN voltage over resistors and DROP over battiers.


Let's give it a go with 1:



Do the same thing with the 4 more loops and solve simultaneously!
(It might be efficient to use a matrix)

After you solve, if you get a negative current then you just reverse the current arrow!
Title: Re: The question the whole universe could not answer!!!!!!!
Post by: crappy on March 19, 2010, 06:51:55 pm
Haha well i won't answer but I'll start u off:

First order of business is to arbitrarily choose current directions. Just point the currents any way you like in each section.
Now, we have 5 unknown currents. So you need to travel around 5 loops to get 5 equations. (See Pic)
(Note, there is also another loop you could take - going around the outisde of the whole circuit)

The rules are:
If you travel with current, you will DROP voltage over resistors and GAIN over batteries.
If you travel against current, you will GAIN voltage over resistors and DROP over battiers.


Let's give it a go with 1:



Do the same thing with the 4 more loops and solve simultaneously!
(It might be efficient to use a matrix)

After you solve, if you get a negative current then you just reverse the current arrow!

thanks /0, I just got it lol

thanks man