Post by: Albeno69 on April 10, 2010, 06:36:54 pm
how do i do a 3 median line method.
i comprehend that if you have,
11 points are divided into 4/3/4.
10 points are divide into 3/4/3.
12 points are divided into 4/4/4.
but after this step i am completely lost.
could someone explain how to do this?
Post by: Gloamglozer on April 10, 2010, 10:27:57 pm
1. You've done the first step correctly. Basically the rule is that if you can't divide it evenly and there is one extra point, put it in the middle region. if there are two spare points, put one in each of the outer regions.
2. Now that you have divided up the points into groups, we are going to find the median point in each group. You need to do this in two steps:
- Firstly, find the median of the x values.
- Just say for the first group, we have 3 points of the coordinates (1,1), (2,2) & (3,1.5).
- Put all the x coordinates in order. So 1,2,3.
- The median is 2.
- Secondly, we find the median of the y values.
- Put all the y coordinates in order. So 1, 1.5, 2.
- The median is 1.5.
3. Now, we know the median point in the first region is (2, 1.5).
4. Mark this point on the graph with a cross (or whatever tickles your fancy).
5. Repeat steps 2-4 for the remaining groups.
6. Place your ruler so that the ruler passes through the first and last median points.
7. Now slide the ruler one third towards the middle cross/marker.
8. Rule the line.
9. There you have it, your three median line.
Another and faster way if doing it would be to do step 2 visually but in a SAC, I'm pretty sure they'll ask you to calculate the gradient and possibly y-intercept of the line and if you do it visually, then you might end up with a gradient that could be very inaccurate from the "range" that your teachers would accept as the correct answer.
Post by: Albeno69 on April 10, 2010, 10:54:48 pm
I know the book is a little ambiguous about the explanation so I'll try my best into giving you my own explanation. So please yell out if you still have any further enquiries.thanks i have a dud of a teacher who compares maths to religion.lol
1. You've done the first step correctly. Basically the rule is that if you can't divide it evenly and there is one extra point, put it in the middle region. if there are two spare points, put one in each of the outer regions.
2. Now that you have divided up the points into groups, we are going to find the median point in each group. You need to do this in two steps:
- Firstly, find the median of the x values.
- Just say for the first group, we have 3 points of the coordinates (1,1), (2,2) & (3,1.5).
- Put all the x coordinates in order. So 1,2,3.
- The median is 2.
- Secondly, we find the median of the y values.
- Put all the y coordinates in order. So 1, 1.5, 2.
- The median is 1.5.
3. Now, we know the median point in the first region is (2, 1.5).
4. Mark this point on the graph with a cross (or whatever tickles your fancy).
5. Repeat steps 2-4 for the remaining groups.
6. Place your ruler so that the ruler passes through the first and last median points.
7. Now slide the ruler one third towards the middle cross/marker.
8. Rule the line.
9. There you have it, your three median line.
Another and faster way if doing it would be to do step 2 visually but in a SAC, I'm pretty sure they'll ask you to calculate the gradient and possibly y-intercept of the line and if you do it visually, then you might end up with a gradient that could be very inaccurate from the "range" that your teachers would accept as the correct answer.
just wondering say you are given 4 points what would you do?
Post by: Gloamglozer on April 10, 2010, 10:59:46 pm
thanks i have a dud of a teacher who compares maths to religion.lol
just wondering say you are given 4 points what would you do?
Your welcome. Are you saying 4 points to plot a three median line for? If that is the case, I'm pretty sure you can't do one because you wouldn't be able to divide the points, let alone be able to draw a median line accurately since you'll end up with one point in the first and last group. But unfortunately, I'm not too pro enough you answer that question so perhaps someone with more knowledge might be more certain.
Post by: Albeno69 on April 10, 2010, 11:01:27 pm
na like 4/3/4. sorry for the confusion.thanks i have a dud of a teacher who compares maths to religion.lol
just wondering say you are given 4 points what would you do?
Your welcome. Are you saying 4 points to plot a three median line for? If that is the case, I'm pretty sure you can't do one because you wouldn't be able to divide the points, let alone be able to draw a median line accurately since you'll end up with one point in the first and last group. But unfortunately, I'm not too pro enough you answer that question so perhaps someone with more knowledge might be more certain.
Post by: Gloamglozer on April 10, 2010, 11:09:11 pm
na like 4/3/4. sorry for the confusion.thanks i have a dud of a teacher who compares maths to religion.lol
just wondering say you are given 4 points what would you do?
Your welcome. Are you saying 4 points to plot a three median line for? If that is the case, I'm pretty sure you can't do one because you wouldn't be able to divide the points, let alone be able to draw a median line accurately since you'll end up with one point in the first and last group. But unfortunately, I'm not too pro enough you answer that question so perhaps someone with more knowledge might be more certain.
Not a problem. You would do the same thing. If you have four points in the first and last group, then you would follow step 2 of my explanation. Just say you had these four points:
(1,3), (3,5), (2,6) & (5,4).
1. Put all the x-coordinates in order - 1,2,3,5.
2. Take the median. In this case, it would fall between 2 & 3.
3. To find the median, you would do
4. Put all the y-coordinates in order - 3,4,5,6.
5. Take the median. In this case, it would fall between 4 & 5.
6. To find the median, you would do
7. Therefore, the median point for that group would be (2.5,4.5).
Post by: Albeno69 on April 10, 2010, 11:11:00 pm
you are the best thanks youna like 4/3/4. sorry for the confusion.thanks i have a dud of a teacher who compares maths to religion.lol
just wondering say you are given 4 points what would you do?
Your welcome. Are you saying 4 points to plot a three median line for? If that is the case, I'm pretty sure you can't do one because you wouldn't be able to divide the points, let alone be able to draw a median line accurately since you'll end up with one point in the first and last group. But unfortunately, I'm not too pro enough you answer that question so perhaps someone with more knowledge might be more certain.
Not a problem. You would do the same thing. If you have four points in the first and last group, then you would follow step 2 of my explanation. Just say you had these four points:
(1,3), (3,5), (2,6) & (5,4).
1. Put all the x-coordinates in order - 1,2,3,5.
2. Take the median. In this case, it would fall between 2 & 3.
3. To find the median, you would do. That equals to 2.5.
4. Put all the y-coordinates in order - 3,4,5,6.
5. Take the median. In this case, it would fall between 4 & 5.
6. To find the median, you would do. That equals to 4.5.
7. Therefore, the median point for that group would be (2.5,4.5).
Post by: Gloamglozer on April 10, 2010, 11:14:11 pm
Post by: Albeno69 on April 12, 2010, 02:13:21 pm
thanks.
Post by: stonecold on April 14, 2010, 12:23:24 am
a rule which you can follow is the independent variable is always plotted on the horizontal axis (known as the x-axis), whilst the dependent variable is on the vertical axis. (known as the y-axis)
on last years exam 1, they gave us a two columns of data. normally you would plot the left column as x variable, and the right column as y variable. the question said to use the right column as the independent variable, so you had to switch the columns in your calc to get the right equation.
to make it more complicated the the columns were named age and sleep time or something like that.
normally you would use age (left column) as independent, and sleep time(right column) as dependent
however this question said to use sleep time as the independent variable, so in your calc, you have to put the sleep time list on the left and the age list on the right, basically the opposite to how it appeared on the paper....
then just do your normal stat calc function and get the equation of the line, r value or whatever it's asking for...
Post by: nex on April 17, 2010, 10:54:49 am
Post by: Albeno69 on April 18, 2010, 08:58:36 am
Post by: Visionz on April 21, 2010, 10:00:57 pm
I've found a great way to distinguish between the dependant and independant variable is to construct a sentence from it, and see which option makes more logical sense. For example, Height and Time. The two sentences would be either 1) Height is dependant on time or 2) Time is dependant on height. The 2nd sentence doesn't make sense at all, while the first one is completely logical, so therefore, height is the dependant variable, and time is the independant variable.
This is how I did it. My sentence is simply "______ depends on _________" Height depends on weight - no. weight depends on height - yes. Whichever makes more sense. :)
I used to label independent variables, dependent, 100% of the time. I found that my issue was completely retarded. I thought in my head that dependent meant independent. I think it was because the in- prefix has a negative connotation.. sort of.. like inconsiderate and incomprehensible. Comprehensible is the same as independent but dependent is the same as incomprehensible. It was adjective is 'weaker' or something. I dunno. I dont expect anyone to understand, especially when I dont.
Post by: Martoman on April 23, 2010, 05:16:41 pm
I've found a great way to distinguish between the dependant and independant variable is to construct a sentence from it, and see which option makes more logical sense. For example, Height and Time. The two sentences would be either 1) Height is dependant on time or 2) Time is dependant on height. The 2nd sentence doesn't make sense at all, while the first one is completely logical, so therefore, height is the dependant variable, and time is the independant variable.
This is how I did it. My sentence is simply "______ depends on _________" Height depends on weight - no. weight depends on height - yes. Whichever makes more sense. :)
I used to label independent variables, dependent, 100% of the time. I found that my issue was completely retarded. I thought in my head that dependent meant independent. I think it was because the in- prefix has a negative connotation.. sort of.. like inconsiderate and incomprehensible. Comprehensible is the same as independent but dependent is the same as incomprehensible. It was adjective is 'weaker' or something. I dunno. I dont expect anyone to understand, especially when I dont.
This is the EXACT method I use.
Post by: Albeno69 on April 24, 2010, 12:59:06 am
yea now that what im using to and i actually understand what im doing now. it is so much easier when u understand something.lolI've found a great way to distinguish between the dependant and independant variable is to construct a sentence from it, and see which option makes more logical sense. For example, Height and Time. The two sentences would be either 1) Height is dependant on time or 2) Time is dependant on height. The 2nd sentence doesn't make sense at all, while the first one is completely logical, so therefore, height is the dependant variable, and time is the independant variable.
This is how I did it. My sentence is simply "______ depends on _________" Height depends on weight - no. weight depends on height - yes. Whichever makes more sense. :)
I used to label independent variables, dependent, 100% of the time. I found that my issue was completely retarded. I thought in my head that dependent meant independent. I think it was because the in- prefix has a negative connotation.. sort of.. like inconsiderate and incomprehensible. Comprehensible is the same as independent but dependent is the same as incomprehensible. It was adjective is 'weaker' or something. I dunno. I dont expect anyone to understand, especially when I dont.
This is the EXACT method I use.
Post by: naved_s9994 on April 24, 2010, 01:33:56 am
I've found a great way to distinguish between the dependant and independant variable is to construct a sentence from it, and see which option makes more logical sense. For example, Height and Time. The two sentences would be either 1) Height is dependant on time or 2) Time is dependant on height. The 2nd sentence doesn't make sense at all, while the first one is completely logical, so therefore, height is the dependant variable, and time is the independant variable.
Exactly, how I do it..
If youve enough Methods questiones, you should pick this up preety easily, by reading it..
Its always in the wording...very easy. just read and interpret - just practice, youll get better
Post by: Albeno69 on April 24, 2010, 12:46:05 pm
yea that what i have been doing sac in 2 weeksI've found a great way to distinguish between the dependant and independant variable is to construct a sentence from it, and see which option makes more logical sense. For example, Height and Time. The two sentences would be either 1) Height is dependant on time or 2) Time is dependant on height. The 2nd sentence doesn't make sense at all, while the first one is completely logical, so therefore, height is the dependant variable, and time is the independant variable.
Exactly, how I do it..
If youve enough Methods questiones, you should pick this up preety easily, by reading it..
Its always in the wording...very easy. just read and interpret - just practice, youll get better
Post by: Albeno69 on May 14, 2010, 04:24:44 pm
how do i work out question 2 AND 6.
we did this last yr and i didn't have to much trouble but i lost all the notes i made for it and ones in text book are not realy good/helpful. It on page 21 of the pdf.
Post by: Gloamglozer on May 14, 2010, 08:31:20 pm
Another question
how do i work out question 2 AND 6.
we did this last yr and i didn't have to much trouble but i lost all the notes i made for it and ones in text book are not realy good/helpful. It on page 21 of the pdf.
I can't seem to open to attachment. It says the file "...is damaged and cannot be repaired."
Post by: Albeno69 on May 14, 2010, 08:45:36 pm
sorry bout that dont know what happened this one works.Another question
how do i work out question 2 AND 6.
we did this last yr and i didn't have to much trouble but i lost all the notes i made for it and ones in text book are not realy good/helpful. It on page 21 of the pdf.
I can't seem to open to attachment. It says the file "...is damaged and cannot be repaired."
Post by: Albeno69 on May 15, 2010, 07:02:32 pm
Another questionanyone know how to work these quetions out need some help.
how do i work out question 2 AND 6.
we did this last yr and i didn't have to much trouble but i lost all the notes i made for it and ones in text book are not realy good/helpful. It on page 21 of the pdf.
Post by: Gloamglozer on May 15, 2010, 07:49:41 pm
Now, let's find the surface area. If you look at the picture, there are 3 rectangles and two triangles. We can now work out the surface area by splitting up each surface up, calculate the area of each side and add them all up. That makes the formula:
6. With this question, you are asked to calculate the volume of a right pyramid. If you look on page 379, it will have the formula for a square pyramid, which is:
where x is the length of the base and h is the height.
In this question, as it is not a square pyramid, the logic still applies. Instead of squaring the base, you just multiple the two sides of the base (ie. find the area of the base). In fact, if you think about it, with a square pyramid, we are still multiplying the two sides of the base. But because a square has sides of equal length, it will just be
As this question is just a matter of plugging in numbers, I'll leave this one up to you and if you have any problems, just yell out. :)
Post by: Albeno69 on May 15, 2010, 08:23:52 pm
2. Firstly, let's find the volume because that's the easiest. As it is a triangular prism, we know the formula for volume is:ok for question 2 how did u know the height was 4?
Now, let's find the surface area. If you look at the picture, there are 3 rectangles and two triangles. We can now work out the surface area by splitting up each surface up, calculate the area of each side and add them all up. That makes the formula:
6. With this question, you are asked to calculate the volume of a right pyramid. If you look on page 379, it will have the formula for a square pyramid, which is:
where x is the length of the base and h is the height.
In this question, as it is not a square pyramid, the logic still applies. Instead of squaring the base, you just multiple the two sides of the base (ie. find the area of the base). In fact, if you think about it, with a square pyramid, we are still multiplying the two sides of the base. But because a square has sides of equal length, it will just be, which is of course,
.
As this question is just a matter of plugging in numbers, I'll leave this one up to you and if you have any problems, just yell out. :)
and thanks
Post by: Gloamglozer on May 16, 2010, 12:48:14 am
ok for question 2 how did u know the height was 4?
and thanks
In the question, we are told that the cross-section is a "right-angled isosceles triangle". This means we can look at it like this:
(http://img686.imageshack.us/img686/8118/triangleh.jpg)
Post by: Albeno69 on May 16, 2010, 07:52:32 am
thanks i was thinking that but realy wanst sure thanks very much.ok for question 2 how did u know the height was 4?
and thanks
In the question, we are told that the cross-section is a "right-angled isosceles triangle". This means we can look at it like this:
(http://img686.imageshack.us/img686/8118/triangleh.jpg)
Post by: Albeno69 on May 19, 2010, 03:57:02 pm
7= 35.6 m
thanks
Post by: stonecold on May 19, 2010, 06:57:00 pm
Post by: Albeno69 on May 19, 2010, 09:12:35 pm
solution is attached. :)thanks
Post by: Albeno69 on June 14, 2010, 06:18:32 pm
when do u apply the ambiguous case i know it means there are two angle but not sure how to know when to apply the ambiguous case.
Post by: Albeno69 on September 20, 2010, 04:12:14 pm
Also business maths question,
How do you work out a question were either the interest rate has increase or decreased using the financial solver.
Post by: Martoman on September 20, 2010, 04:23:41 pm
Post by: Albeno69 on September 20, 2010, 05:16:13 pm
Interest rate decreasing or increasing? I'd need to see the question but usually you find the final value of the investment for the original percentage then you place this as the intial value and change the percentage to what it is.yea there is no such question but i dont know how to approach such as question and want to be fully prepared for the exam.
do u know the annuities formula cos the quest and essential have a different formula
Post by: Martoman on September 20, 2010, 06:01:57 pm
For Interest rate changing refer to page 602 of quest.
Post by: Albeno69 on September 20, 2010, 06:47:25 pm
With the annuities you are probs getting confused with the + and - in between the terms? If so, the essentials shows the annuities for a loan. In Quest it shows annuities for superannuation (as well as a loan on page584). The difference arises after you think about it for a bit; the -ve in the equation will mean you are making regular repayments to pay off a loan (money you are losing to the greedy bank) wheras the +ve in super means you are adding regular amounts to a bank account (and thus gaining money thats what superannuation is).aw thanks very much for clearing it up
For Interest rate changing refer to page 602 of quest.
Post by: Albeno69 on September 26, 2010, 04:55:48 pm
Post by: jasoN- on September 26, 2010, 04:57:59 pm
Variance: you mean coefficient of determination (r^2)? If so its usually a LinearReg line between two variables. (Statistics -> Calc -> LinearReg)
Post by: Albeno69 on September 26, 2010, 05:06:42 pm
Standard deviation: Statistics -> One or Two Variable (Calc)yea i see this was with standard deviation but im pretty sure there is something in the book or something on the calc. and variance isnt the coefficient of determination its something different.
Variance: you mean coefficient of determination (r^2)? If so its usually a LinearReg line between two variables. (Statistics -> Calc -> LinearReg)
thanks for the help anyway
Post by: ChairmanMao on September 26, 2010, 06:35:55 pm
Post by: Albeno69 on September 26, 2010, 06:48:00 pm
TI-84 ftwwhat?
Post by: aznanthony on September 26, 2010, 07:18:00 pm
Post by: Albeno69 on September 26, 2010, 09:24:52 pm
What calculator do you use?cas,
i remember soothing with the book button on the calc
Post by: Albeno69 on October 24, 2010, 10:10:47 am
Post by: Albeno69 on October 24, 2010, 04:58:04 pm
Post by: Martoman on October 25, 2010, 12:15:02 am
N = 96
I% = 6.5
PV = -500
PMT = 200
FV=?
P/Y=12
C/y= 12
Press FV then you get 25935.30411
Post by: Blakhitman on October 25, 2010, 12:17:50 am
Apparently working out is drawing the financial solver box...f that...matrices rock!! ;D
Post by: Martoman on October 25, 2010, 12:20:44 am
Fuck that, that turned me off bad. Now I do business maths. its lovely.
Post by: Blakhitman on October 25, 2010, 12:24:37 am
but man, business maths is annoying sometimes, especially the wording they have.
Post by: kenhung123 on October 25, 2010, 12:27:45 am
have you tried doing some NEAP matricies exam 2?Yes its ridiculous. However some say its not assessable
Fuck that, that turned me off bad. Now I do business maths. its lovely.
Post by: Martoman on October 25, 2010, 12:31:54 am
and its further maths.
I just went. No. halfway through the module I just gave up. Did buisness on the same paper. Its a joke. Business is ALWAYS a joke. Matricies is variable amoung the exams. VCAA though? pfft, matricies aren't hard at all.
Post by: Blakhitman on October 25, 2010, 12:34:56 am
Post by: Albeno69 on October 25, 2010, 07:54:40 am
Answer is 25935.the PMT is supposed to be a negative because the money is flowing from you to the bank???
N = 96
I% = 6.5
PV = -500
PMT = 200
FV=?
P/Y=12
C/y= 12
Press FV then you get 25935.30411
also vcaa got a different answer in the solutions that has also got me stunned on this question.
Post by: milkcarton on October 25, 2010, 10:56:29 am
Answer is 25935.the PMT is supposed to be a negative because the money is flowing from you to the bank???
N = 96
I% = 6.5
PV = -500
PMT = 200
FV=?
P/Y=12
C/y= 12
Press FV then you get 25935.30411
also vcaa got a different answer in the solutions that has also got me stunned on this question.
Hi Albeno69, I assume the question you're referring to is this one.
3c. $500 is deposited into an account with an interest rate of 6.5% per annum compounding monthly.
Deposits of $200 are made to this account on the last day of each month after interest has been paid.
Determine the total value of this investment at the end of eight years.
Write your answer correct to the nearest dollar.
And also
Martoman's answer of 25935.30411 is correct, you mustn't been looking at the correct examiner's report.
Edit: Sorry, failed to mention that Martoman had the values incorrect, as the above would give an answer of 24255.63.
Albeno69, both values should be negative (PV & PMT) as it's money out of your pocket into the bank. You then should get a correct value of 25935.30411 :)
$25 935 is VCAA's answer. :) Hope that clears any doubts.
Post by: Albeno69 on October 25, 2010, 11:05:13 am
yea thanks verry helpful.Answer is 25935.the PMT is supposed to be a negative because the money is flowing from you to the bank???
N = 96
I% = 6.5
PV = -500
PMT = 200
FV=?
P/Y=12
C/y= 12
Press FV then you get 25935.30411
also vcaa got a different answer in the solutions that has also got me stunned on this question.
Hi Albeno69, I assume the question you're referring to is this one.
3c. $500 is deposited into an account with an interest rate of 6.5% per annum compounding monthly.
Deposits of $200 are made to this account on the last day of each month after interest has been paid.
Determine the total value of this investment at the end of eight years.
Write your answer correct to the nearest dollar.
And also
Martoman's answer of 25935.30411 is correct, you mustn't been looking at the correct examiner's report.
Edit: Sorry, failed to mention that Martoman had the values incorrect, as the above would give an answer of 24255.63.
Albeno69, both values should be negative (PV & PMT) as it's money out of your pocket into the bank. You then should get a correct value of 25935.30411 :)
$25 935 is VCAA's answer. :) Hope that clears any doubts.
2006 vcaa exam 1 business maths module and i struggled on question 9 do u know how to figure this one put thanks.
Post by: milkcarton on October 25, 2010, 11:16:38 am
Jenny borrowed $18 000. She will fully repay the loan in five years with equal monthly payments.
Interest is charged at the rate of 9.2% per annum, calculated monthly, on the reducing balance.
The amount Jenny has paid off the principal immediately following the tenth repayment is
A. $1876.77
B. $2457.60
C. $3276.00
D. $3600.44
E. $3754.00
Okay, firstly you want to find how much is the monthly repayment. So using the information above, through the TVM Solver
N: 60 (5 x 12(monthly repayments for 5 years)
I: 9.2
PV= 18000 (she borrowed it, so it's in her pocket. Positive value)
PMT = -375.40
FV = 0
P/Y = 12
C/Y = 12
Okay, now that we have that, we want to find out how much of the principal has been paid at the 10th repayment.
N= 10 (1 payment per month; 10 repayments =10 months)
I=9.2
PV=18000
PMT=-375.40
FV= -15542.39
P/Y=12
C/Y=12
Although negative value, use logic to assume it's a positive number
Then simply, principal - future value = 18000 - 15542.39(I preferably don't round up and just look for the one closest) = $2457.61
So the answer is B. :)
Post by: sam.utute on October 25, 2010, 12:25:00 pm
Although negative value, use logic to assume it's a positive number
So the answer is B. :)
I like that. USE LOGIC damn you! :D
Post by: Albeno69 on October 25, 2010, 02:15:44 pm
Post by: Martoman on October 25, 2010, 03:51:22 pm
Will you compare the two on the exam day or will you decide before-hand which you will definitely do?
on exam day
Post by: Albeno69 on October 27, 2010, 06:09:49 pm
Post by: milkcarton on October 27, 2010, 06:17:07 pm
im doing the 2008 vcaa exam one can someone provide explanation of question 5 my calc doesnt seem to be ever getting the right answers.
What module?
Post by: Albeno69 on October 27, 2010, 07:10:30 pm
sorry coreim doing the 2008 vcaa exam one can someone provide explanation of question 5 my calc doesnt seem to be ever getting the right answers.
What module?
Post by: milkcarton on October 27, 2010, 07:33:08 pm
Look at the dot plot and record the frequency of hours watching TV in your calculator in list 1. 0, 0,0,1,1,2,2,2,2,3,3,4,4,5. Then calculate 1-variable statistics. You should see the mean as x = 2.1 and standard deviation as Sx = 1.6.
(Done on a TI-84 calculator, I don't know what to do for Nspire)
Post by: Albeno69 on October 27, 2010, 09:04:17 pm
Hi Albeno69,ok thanks i was doing it totally wrong.
Look at the dot plot and record the frequency of hours watching TV in your calculator in list 1. 0, 0,0,1,1,2,2,2,2,3,3,4,4,5. Then calculate 1-variable statistics. You should see the mean as x = 2.1 and standard deviation as Sx = 1.6.
(Done on a TI-84 calculator, I don't know what to do for Nspire)
Post by: Albeno69 on October 28, 2010, 01:41:31 pm
how do they get the answer for question 6 business maths for 2008 vcaa multi choice?
Post by: LFTM on October 28, 2010, 01:57:46 pm
Sam will earn 0.075x5000=375 375x3=1125
Charlie will earn 0.075x5000=375
(375+5000)x0.075=403.125
5778.125x0.075=433.36
375+403.125+433.36=1211.49
1211.49-1125=86.48
So, it's A.
Post by: Albeno69 on October 30, 2010, 01:01:26 pm
im doing networks and cant seem to get my head around crashing.
can someone give me a quick explanation?
is it to do with making another critical path?
Post by: Albeno69 on October 31, 2010, 09:06:46 pm
ok i dont know why this is confusing me but it is.Bump
im doing networks and cant seem to get my head around crashing.
can someone give me a quick explanation?
is it to do with making another critical path?
Post by: mmmmm on October 31, 2010, 09:10:52 pm
Hi Albeno69,
Look at the dot plot and record the frequency of hours watching TV in your calculator in list 1. 0, 0,0,1,1,2,2,2,2,3,3,4,4,5. Then calculate 1-variable statistics. You should see the mean as x = 2.1 and standard deviation as Sx = 1.6.
(Done on a TI-84 calculator, I don't know what to do for Nspire)
Sorry i've got a CAS calculator. But i think it's basically the same time. Is there another way of doing this rather than typing each number repetitively? Because what if the frequency is 40 etc :/
Post by: shokstar on October 31, 2010, 09:15:03 pm
Post by: mmmmm on October 31, 2010, 09:22:22 pm
Yeh, just put the data in one column, then put the frequencies of each in the next column, then do one-variable statistics>and when your choosing your x list, theres a category called 'frequency list', make that the column you put your frequencies in, and thats it!
OMG. THANK YOU SO MUCH! I've been trying to do this for ages!