ATAR Notes: Forum
VCE Stuff => VCE Science => VCE Mathematics/Science/Technology => VCE Subjects + Help => VCE Chemistry => Topic started by: kenhung123 on May 09, 2010, 08:28:03 pm
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Does the oxygen in water have to be from the hydroxyl or caroxyl group? Or is it a totally random process?
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I don't think it really matters, but if you want to get technical, then I believe it is from the carboxyl group.
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i dont think this really matters but id say the OH comes from the hydroxyl and the H from the carboxyl. leaving u with the ester linkage (COO).
>.>
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haha, we both said a different thing. :P
I'm just saying what my teacher told me...
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OH comes from the carboxyl. But this mechanism is beyond VCE, so don't worry about it.
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lol yea i had no idea anyway :P
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http://en.wikipedia.org/wiki/Fischer_esterification
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Just remember that carboxyl has 2 oxygens, and hydoxyl only has 1.
It is only fair that in the end they have 1 each. :P
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OH from hyrdoxyl and the H from carboxyl
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OH from hyrdoxyl and the H from carboxyl
mao just corrected that ahah
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Could you just imagine a question on this. It would be like:
In a condensation reaction between a carboxylic acid and an alkanol, water is formed. The oxygen in the water has come from:
a) the carboxylic acid
b) the alkanol
c) either the carboxylic acid or the alkanol as the reaction is random
d) the molecule with the lowest molecular weight
haha!
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OH from hyrdoxyl and the H from carboxyl
mao just corrected that ahah
serious? teacher told us it had to be like this XD
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The O comes from the carboxy thats what I thought. WHen you form an amide group in proteins, it becomes NH-C=O and the OH is gone from the carboxy...
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Coz in different textbooks they tend to highlight the O from different functional groups (jumping between hydroxy and carboxy)
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Coz in different textbooks they tend to highlight the O from different functional groups (jumping between hydroxy and carboxy)
yea it really doesnt matter.
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Just wanted to clarify..
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In acid catalysed esterification, the condensate is released from the carboxyl group.