ATAR Notes: Forum
VCE Stuff => VCE Science => VCE Mathematics/Science/Technology => VCE Subjects + Help => VCE Chemistry => Topic started by: happyhappyland on May 30, 2010, 10:02:30 am
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The final one is here. If you see any mistakes please correct me, Im not perfect. Its basically questions Ive compiled that you probably wont see from normal past papers you are doing. Hopefully it will help you with your studies :) :)
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Delete Q3 in MC
Question 5c in short answer should read:
c. A solution of bromine of unknown concentration is placed in a sample cell with a path length of 2 cm. Absorbance is at 0.48
[Br2] = ________________ M
[Edit]
Ill be kind and upload the first all the multiple choice. DOWNLOAD THE FILE "MULTIPLE CHOICE".
[Original post]
Ive compiled a few questions to make a practise paper. Here are the first 10 multiple choice. Ill be finished by tomorrow on it and release on this site. I dont have answers to it yet cos I havnt dont the questions myself! The questions are from various sources like neap and stuff. Ive just chosen the hard ones and edited some of the numbers.
If you think its crap then tell me so, then I wont make anymore
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Thanks for putting in the effort but won't everyone here pretty much have the practice exams already?
And if you expose them to questions now they'll just see them again while using practice and know the answer already
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1.A
2.D
3. I don't know what 4-amino phenol's molar mass is or paracetamol.
4. B
5. C
6. D
7. A
8. Fairly sure the mg should read grams per litre. This is because at 25 degrees 8g per litre.Then in 10L there will be 80g or 80mL. C
9. I don't think most of these were are meant to know at VCE level?
10. B
11. D
12. B
13. A
14. You don't actually ask a question here! It could be A if you want the diluted or D if you want the original.
15. B
16.A
17. C
18. Cannot read the coefficients off in word 2010.
19. A not D as A would have lots more water in it, which accounts for the discrepancy in weight.
20. C
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Thanks for putting in the effort but won't everyone here pretty much have the practice exams already?
And if you expose them to questions now they'll just see them again while using practice and know the answer already
No because some of these questions are from my school sacs and some are from the HSC chemistry course. Unless you have bothered to go through the HSC course and find every relevant question or go to my school, I doubt you would have been exposed to the questions.
Q3 ill delete that question...
Q8 the question is right. you have to think a bit more beyond the question. its not as simplistic as it seems. try using the normal atmospheric pressure (101.3kpa)
Q9. its meant to be a challenge, no point in past papers like lisachem.
Q14 thanks edited
Q18. edited
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Martoman, aminophenol is just an amine group replacing a hydrogen on a phenol ring. :)
So C6H7NO, molar mass 109 g/mol.
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lol whats a phenol ring...
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Benzene ring with one hydrogen replaced with a hydroxy group. I am fairly sure we aren't required to know that though.
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So has anyone done it yet? I can't print till Monday, printer sucks.
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Scrap Q3 on Multiple choice I cant work it out lol
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Thanx, do you happen to have the answers?
Souljette
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Thanx, do you happen to have the answers?
Souljette
Nup. Ill post my answers up when Im done with it :) You can do that aswell. Some of the questions I changed a few numbers so the actual answer would be different from the question I got it from originally.
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Thanks happy, post the solutions up when you can please.
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MC
1A 2D 3/ 4B 5C 6D 7A 8A 9D 10B 11D 12B 13A 14D 15D 16A 17C 18A 19A 20C
Q15 the fact that it is CHLOROpropane the large molecular weight will cause it to have a higher boiling point than 1-butanol
SA: im trying to scan my answers except my printer is being a ****.
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mmm but its not the same bonding... just because it has a bigger molar mass by 4.5 g/mol and the fact that the butanol will be able to form hydrogen bonds makes me inclined to defend my answer?
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Are we required to be able to compare different length members of different homologous series in that way?
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mmm but its not the same bonding... just because it has a bigger molar mass by 4.5 g/mol and the fact that the butanol will be able to form hydrogen bonds makes me inclined to defend my answer?
But isnt the chlorine more electronegative that the oxygen?... wait im not sure what im saying.
This question was on my sac, and I got it right with that answer. Im not sure if they accepted butanol aswell cos it was a very poor sac and many MC Qs had two answers.
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I think butan-1-ol also. Both are polar I believe, but chlorowhatever can only make dipole-dipole bonds, whereas the alcohol can make hydrogen bonds which are stronger and require more energy to break...
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Just came across a mistake Question 5 c) SHOULD read
c. A solution of bromine of unknown concentration is placed in a sample cell with a path length of 2 cm. Absorbance is at 0.48.
[Br2] = ________________ M
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Not bad happyhappyland, but I think a lot of your questions are irrelevant for vce.
I have only looked at multi choice for now, but here is some of my feedback.
E.g. Question 3 - we arent expected to know about phenols, or paracetamol. If they were in the exam, there should be enough information.
I like question 6 - although if I wrote it, I wouldnt specify it as being a condenstaion polymer - but because people are drilled into the thought of polymers being addition polymers, this would be a great question.
7 - I dont like the "wrong" choices, I would have done something like 2,3,-Dicholoro-1-fluoro-1,4-dimethylbutane. Or even 3,5-dichloro-2-fluoro-5-methylpentane
Yeah you can probably see why I would put these as a choice.
8 - probably pointed out before that it can't be mls. BUT if you made the concentration ppm and then asked people to work out how many mls, then this would be a real trick. But I would have 80ml as one choice, 0.08ml (the real answer) as another choice.
9 - VCE students aren't required to know about aldehydes and Ketones, however if we are given an NMR or an IR of one, we should be able to draw the molecule without realizing its an aldehyde or a ketone. And if you were going to use pentone,why not make it trickier and say acetone?
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9 - VCE students aren't required to know about aldehydes and Ketones, however if we are given an NMR or an IR of one, we should be able to draw the molecule without realizing its an aldehyde or a ketone. And if you were going to use pentone,why not make it trickier and say acetone?
Because acetone is propanone, and a ketone with 5 carbons is pentanone. :)