ATAR Notes: Forum
VCE Stuff => VCE Science => VCE Mathematics/Science/Technology => VCE Subjects + Help => VCE Chemistry => Topic started by: 8039 on June 06, 2010, 04:01:40 am
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To make propyl methanoate from propane and methane in the shortest reaction pathway, I used this process:
1. propene -(h2o)-> propa-1-ol
2. methane -(cl2)-> chlorometane-(NaOh)-> methanol -(cr207/h+)-> methanoic acid
3. propanol + methanoic acid -(h2so4)->propyl methanoate
Is this a valid method?
And why is it wrong to make butan-1-ol with butene and h2o, why use butane to chlorobutane instead? my guess is unwanted reactions but I'm not sure...
and also, ethanol to ethanoic acid is a oxidation reaction I beleive, why is it dscribed as substitution in my book?
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1. propene -(h2o)-> propa-1-ol
2. methene -(h2o)-> methanol -(cr207/h+)-> methanoic acid
3. propanol + methanoic acid -(h2so4)->propyl methanoate
Is this a valid method?
Cute, But there is no such thing as 'Methene'
And why is it wrong to make butan-1-ol with butene and h2o, why use butane to chlorobutane instead? my guess is unwanted reactions but I'm not sure...
and also, ethanol to ethanoic acid is a oxidation reaction I beleive, why is it dscribed as substitution in my book?
there's Nothing wrong with making Butene with water, but if given in the Question 'Butane' then you can't use water.
Which Text Book do you have? I've always known it to be Oxidn
Souljette
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remember that when you are using water and a chloroalkane, the process has a very low yield.
Chloroalkaneg + H2Ol ->alkanolaq +HClaq
an alkene with water has a two way arrow and H3PO4 catalyst.
I prefer to just remember to do the following
Alkaneg + Cl2g ->(UV light) chloroalkaneg + HClg
Chloroalkaneg + NaOHaq -> alkanolaq + NaClaq
alkanolaq ->(Cr2O7 2-aq /H+aq) -> alkanoic acidaq
also
Alkeneg + H2Og <->(H3PO4/catalyst/300 degrees) alkanolaq
chloroalkaneg + NH3+g ->(alumina/400 degrees) alkanamine(?)g + HClg
BTW, I have never really gotten the amine thing
for example is it supposed to be ethanamine or ethamine?
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You replace the last letter with amine as in the former case.
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with amine it depends on whether you are looking at the hydrocarbon with an amine group atttched or a amine group with a hydrocarbon attached.
i.e having a ethane molecule with an amine group gives you - aminoethane
but having a amine group with an ethyl group attached gives you ethylamine
its the same thing but just different ways of looking at it. either way on an exam would be fine
hope that helps
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cheers martoman and kate
i.e having a ethane molecule with an amine group gives you - aminoethane
but having a amine group with an ethyl group attached gives you ethylamine
not sure what the difference is, with ethane the amine will always be part of the longest chain.
what I have been told is to always use something amine, unless there is a higher ranking group (such as carboxyl)
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there isnt really a difference. just some stupid person realised it can go either way.
and going with something amine will work. just chuck amino out the front if there is a carboxyl, like what you said :)