Post by: user_5 on August 08, 2010, 08:47:55 pm
Pr(2) = Pr(3) = Pr(4) = Pr(5) = 0.2
Pr(1) = Pr(6) = 0.1
The die is rolled twice, and the smaller of the numbers showing is noted. Let Y represent this value.
Find Pr(Y = 1)
Post by: the.watchman on August 08, 2010, 09:00:21 pm
So
On second thoughts, the probability is the same as getting a 1 on either roll:
Post by: pooshwaltzer on August 08, 2010, 09:06:24 pm
Post by: the.watchman on August 08, 2010, 09:21:13 pm
Pr(Y = 1) = 0.2 ... watchman, need to double your answer because 1 can be either on 1st roll or 2nd roll.
Oops, fixed :P
Post by: user_5 on August 08, 2010, 09:33:34 pm
I eventually figured out the answer, similar to your first approach before checking back here.
The book has the answer 0.19, so I'm assuming in this case, the first approach is required?
Post by: the.watchman on August 08, 2010, 09:37:32 pm
Oh okay, thanks the.watchman.
I eventually figured out the answer, similar to your first approach before checking back here.
The book has the answer 0.19, so I'm assuming in this case, the first approach is required?
Damnit, I had to change my above answer AGAIN because I forgot something
It should be 0.19, not 0.2 :P
Post by: pooshwaltzer on August 08, 2010, 09:46:25 pm