ATAR Notes: Forum
VCE Stuff => VCE Mathematics => VCE Mathematics/Science/Technology => VCE Subjects + Help => VCE Mathematical Methods CAS => Topic started by: Andiio on September 04, 2010, 02:16:32 pm
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For this question;
1. Evaluate
a. cot 2.4
Would the working out just be as follows?
cot 2.4
= 1/tan 2.4
= 23.859
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umm yea.
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Okay sweet. So you don't have to take into account any radians or anything?
How would you do this question?
2. If cos(theta) = 0.92, sin (theta) = 0.39 and tan(theta) = 0.42 find the value of:
a) cot (pi+theta)
Teacher has been away for ages sigh.
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pi + theta in 3rd quadrant so ur tan is positive. so cot(pi+theta) is equal to 1/(0.42)
edit: fixed, thanks for pointing it out :)
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^^^^ theta is not 0.42, tan(theta)=0.42
cot(pi+theta)=1/tan(pi+theta)
As tan(pi+theta)=tan(theta) (quadrants)
cot(pi+theta)=1/tan(theta)
=1/0.42
=___
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Thanks!
What about something like:
Write down the exact value of each:
d) cot 240 degrees
Are you supposed to put 1/tan(180+60) or something? I'm not sure what angle youre supposed to put in :/
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yep.
tan(180+60) is equivalent to tan(60) as tan(180)=0.
cot(240)=1/tan(60)=
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Oh, but I thought you had to relate the angles you take to the quadrants?
As in, 180 - theta = 2pi - theta, pi + theta etc?