ATAR Notes: Forum
VCE Stuff => VCE Science => VCE Mathematics/Science/Technology => VCE Subjects + Help => VCE Chemistry => Topic started by: kenhung123 on September 27, 2010, 02:12:03 pm
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1. So if acid base reactions are exothermic, then wouldn't H2O + H2O => H3O+ + OH- be classified as an exothermic reaction since water is amphiprotic?
2. Why is it that the pH change is low for weak acids when diluted when compared to the dilution of strong acids?
3. For this reaction: Cl2+2OH-<-----> Cl- +ClO- +H2O adding Cl2 would decrease OH-, pH is the measure of [H+] why would the pH decrease when there is no change in [H+]?
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1. No. That reaction is endothermic. Most neutralization reactions are exothermic.
2. Dilution increases %ionisation for weak acids, thus pH drop is smaller
3. [H+]*[OH-] = 10^-14 (at 25 degrees). If OH- is decreased, then H+ must increase, thus pH drop.
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@ 3. Does it have anything to do with the H2O formed?
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No. It's the equilibrium
, if the amount of hydroxide decreases, the system shifts to the left and more H+ must be produced.
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Ah ok. Thanks a lot Mao!
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I came into this interesting question that relates to this. So if a reaction produces OH-, would you say the pH increases as OH- is produced or increases because from the ionisation of pure water, the reaction would consume H+?
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Depends.
If the conditions are already acidic, the latter.
If the conditions are already basic, the prior.
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Hmm how does that work Mao?
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D, H's are being used up.
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D, H's are being used up.
Unfortunately that's not correct.
The fuel cell uses an alkaline electrolyte. At the cathode, even more hydroxides are bring produced. The pH rises due to this accumulation.
B is correct.
I clarify my statement: if you add hydroxides to acid, the pH rises because you are removing acid by a reaction. If you add hydroxides to base, there isn't much H+ yo react with, and the pH rise is due to accumulation of hydroxide
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So pH can be affected by changing [OH-] and not affecting [H+] at all?
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Since its an alkaline electrolyte, does that make the cathode reaction O2 + 2H2O + 4e- => OH- ?
In that case, as hydroxides are being produced wouldn't pH increase, making the answer A?
I'm not really sure. I always get confused in regards to acid/base questions.
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Since its an alkaline electrolyte, does that make the cathode reaction O2 + 2H2O + 4e- => OH- ?
In that case, as hydroxides are being produced wouldn't pH increase, making the answer A?
I'm not really sure. I always get confused in regards to acid/base questions.
That's what I thought.
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But A and C are reactions occuring at the anode (as they indicate oxidation reactions)
The answer must be B or D, but as people above said, H+ indicates an acidic environment, whereas OH- indicates an alkaline environment.
OH- is being produced to maintain the alkaline environment (OH- used up during anode reaction <- A)
hence B
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Yea we're saying B for q 14 but A for q 15
D, H's are being used up.
Unfortunately that's not correct.
The fuel cell uses an alkaline electrolyte. At the cathode, even more hydroxides are bring produced. The pH rises due to this accumulation.
B is correct.
I clarify my statement: if you add hydroxides to acid, the pH rises because you are removing acid by a reaction. If you add hydroxides to base, there isn't much H+ yo react with, and the pH rise is due to accumulation of hydroxide
Mao must've gotten confused between the two questions cause he said "The pH rises due to this accumulation [of OH-]" then said B (pH decreases as OH is used up) is correct.
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Yea we're saying B for q 14 but A for q 15
D, H's are being used up.
Unfortunately that's not correct.
The fuel cell uses an alkaline electrolyte. At the cathode, even more hydroxides are bring produced. The pH rises due to this accumulation.
B is correct.
I clarify my statement: if you add hydroxides to acid, the pH rises because you are removing acid by a reaction. If you add hydroxides to base, there isn't much H+ yo react with, and the pH rise is due to accumulation of hydroxide
Mao must've gotten confused between the two questions cause he said "The pH rises due to this accumulation [of OH-]" then said B (pH decreases as OH is used up) is correct.
yeh agreed
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I was thinking of it in terms of the ionisation of water, as [OH-] increase, the reaction shifts to produce more water H+'s are confused and pH increases!
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Why does diluting strong acid increase pH when the reaction is HCl + H2O => H3O+ + Cl-?
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Why does diluting strong acid increase pH when the reaction is HCl + H2O => H3O+ + Cl-?
Concentration of H30+ will fall when you dilute...
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Why does diluting strong acid increase pH when the reaction is HCl + H2O => H3O+ + Cl-?
Concentration of H30+ will fall when you dilute...
NO UR WRONG. its because CHEMISTRY IS MAGICAL!..
nah hes right
i mean .. think of it.
if you have a strong concentrated acid .. and u put water in it .. guess what happens .. it becomes LESS concentrated
its the same thing here ... add water .. = less concentration of H30+ .. meaning B00M HIGHER PH.
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Diluting increases volume, c=n/v v increases so c decreases.
No magic here ;D
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Lol I was thinking in terms of equilibrium and shifting concentrations. Thanks for the clarification
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Lol I was thinking in terms of equilibrium and shifting concentrations. Thanks for the clarification
No , thank you ;)
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Why does diluting strong acid increase pH when the reaction is HCl + H2O => H3O+ + Cl-?
I think the question he is trying to ask here has to do with physical change vs. chemical change. The point he's making is that adding water leads to a forward reaction as 1 particle vs. 2 particles, it will shift to the side with more dissolved particles to increase the overall concentration, thus increases the conc. of H+, which in turn decreases pH. However, the initial diluting cannot be fully compensated for through the system returning to equilibrium, thus overall conc of H+ decreases, and pH will increases.
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Why does diluting strong acid increase pH when the reaction is HCl + H2O => H3O+ + Cl-?
Remember LCP?
Dilution will decrease concentration of all species. Even though the subsequent change is to produce more H+, this will only be partial, and [H+] invariably drops.
Another point is strong acids do not behave as if they are in equilibrium, because they are so damn strong you get 99.9999999999999999999999999999999999% conversion, the equilibrium lies all the way to the right by about twenty million billion miles. Thus when you dilute, there is no subsequent change, you just get diluted.
Weak acids tend to bounce back a little, but LCP, the pH still rises.
Also, apologies for the previous confusion. You are right in that I was confused, A is the correct answer.
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Great. I understand now. Thanks.
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For a solution that contains involved this reaction:
If I add water, the equilibrium position shifts forward and more OH- produced but still [OH-] is lower. Would you say the pH decrease because [OH-] is lower or because [H+] is higher?
I am not sure if this is considered an alkaline environment or neutral.