ATAR Notes: Forum
VCE Stuff => VCE Mathematics => VCE Mathematics/Science/Technology => VCE Subjects + Help => VCE Mathematical Methods CAS => Topic started by: PringlePop on November 06, 2010, 11:52:22 pm
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Why won't my calculator solve for a(or x) in terms of p?
And this question is A LOT of work for just one mark!
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u dont need a calc for that question..
f(1) so sub in x=1, u've got q in terms of p from the previous question so sub that in. the calc can clean up the rest or it can be done by hand.
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Soz - I'm looking at the Checkpoints and there is sooo much working out. The guy/girl used a calculator, and I didn't get anything resembling their answer...
Question answered :D
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This is a question you must do by hand.
It is an incredible amount of working for 1 mark.
f'(x)=3px^2+2qx+4.25=0
4f'(x)=12px^2+8qx+17=0
FACTORISE:
12px^2-12px +17 -17x
12px(x-1)-17(x-1)
therefore:
(12px-17)(x-1)=0
therfore:
x=17/12p or x=1
I cannot believe all that was one mark!
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Soz - I'm looking at the Checkpoints and there is sooo much working out. The guy/girl used a calculator, and I didn't get anything resembling their answer...
Question answered :D
LOL beat me to it.
I hope I'm right, haven't checked solutions.
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Soz - I'm looking at the Checkpoints and there is sooo much working out. The guy/girl used a calculator, and I didn't get anything resembling their answer...
Question answered :D
LOL beat me to it.
I hope I'm right, haven't checked solutions.
Yeah that's what i got.
your cas wont do that, i tried it with the cas at first
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would you guys automatically think to times f(x) by 4?
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Cas did it for me :) But instead of 17/12p , it gives 1.41667/p which is the approximation. I had to do further work to get that it was 17/12p :/