ATAR Notes: Forum
VCE Stuff => VCE Mathematics => VCE Mathematics/Science/Technology => VCE Subjects + Help => VCE Mathematical Methods CAS => Topic started by: mkhan on November 08, 2010, 08:31:55 pm
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Got this off itute forum.
SECTION 1
1D 2E 3A 4D 5B 6C 7D 8E 9A 10C 11C 12B 13B 14A 15C 16D 17B 18D 19D 20D 21C 22E
Note: For Q16, assumed 'and' meant to be 'or'.
SECTION 2
q1ai inverse of g = e^(x-1)/2 - 4, dom is R
q1aii x-intercept: x = 2loge4 + 1, y-intercept: y = e^(-1/2) - 4
q1aiii x = 5.503, -3.914
q1aiv area = 52.63 unit squares
q1bi a = 1
q1bii c = 1
q1biii show
q1biv show
q1bv p = e^0.9 - 1
q2a Pr = 0.12 (amended)
q2b Pr = 0.729
q2c steady state pr 0.875
q2di first state matrix
[1]
second state matrix
[p]
[1-p]
third state matrix
[p p-0.2][p]=[0.7]
[1-p 1.2-p][1-p]=[0.3]
p = 0.75
q2dii expectation = 1.21
q2e min. n = 18
q3ai AB=20cosx
q3aii WZ=10sinx
q3b area of 4triangles and a square
q3c WY=10sqrt(1-2cos^2 x)
q3d show
q3e T=4000/9 m3, x=arccos(1/sqrt(3))
q3f x=0.86, 1.08
q4a x=1/2 inf, x=13/8 max
q4b x=1/a inf, x=(3ab+1)/10a
q4c a=0
q4d a=3/b
q4e 2
q4f p=1-3^(2/3)
QUESTION 3 E AND 3 F IS WRONG.
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how did people go?? my aim to get over fourty is crushed...
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4f on there is wrong, p was = 1 or 4 but it said p =/= 1 therefore p = 4
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mm true
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all the rest are the same as i got
cant be sure with multichoice coz i cant remember all the correct answers but yeah..
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x=(3ab+1)/10a
i think this part is wrong,
and q3e T=4000/9 m3, x=arccos(1/sqrt(3))
this part is wrong
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haha missed those two^
should be (ab+1)/4a (if i remember right)
and T= 4000rt3/27, or - as it also says - cos^-1(rt3/3)
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Updated:
q3e T=4000/3^(2.5) m3 (amended), x=arccos(1/sqrt(3))
q3f x=0.81, 1.23 (amended)
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q4b x=1/a inf, x=(ab+1)/4a (amended)
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q4f p=4 (amended)
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itute has got the updated version
http://www.itute.com/board/viewtopic.php?f=2&t=1913
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will 39.5/40 for exam1, 80/80 for exam 2 and 90% average SAC mark get a raw score of 50?
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will 39.5/40 for exam1, 80/80 for exam 2 and 90% average SAC mark get a raw score of 50?
Yeah, I'd say so. Dunno how you managed to get a half mark on exam 1 though..
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will 39.5/40 for exam1, 80/80 for exam 2 and 90% average SAC mark get a raw score of 50?
Yeah, I'd say so. Dunno how you managed to get a half mark on exam 1 though..
You wouldn't.
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get c for sacs get25/40 get 40/80 would i get 25?
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will 39.5/40 for exam1, 80/80 for exam 2 and 90% average SAC mark get a raw score of 50?
Yeah, I'd say so. Dunno how you managed to get a half mark on exam 1 though..
for the probability part where p=1/2, I wrote in the bracket (0 <equal p<eqal 1)
where should be (0<equal to pr(X=x)<equal to 1)
too nurvous that day, I assume a 0.5 mark off, or one...
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yeah you might lose a mark if the assesor is actually correcting propererly,
you really didn't need to said that, you just needen't to say that p couldn't be less than zero, to get rid of the extraneous solution
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Hi ALL,
Worked solution to the Exam 2 - Question(4) is attached.
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ooo