ATAR Notes: Forum
Archived Discussion => 2010 => End-of-year exams => Exam Discussion => Victoria => Physics => Topic started by: Whatlol on November 10, 2010, 02:51:56 pm
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Here are solutions for electric power and light
Edit: Question 1 a should be a south pole at the RIGHT hand side of the coil , not the left (sorry)
Added solutions to sound.
Any complaints just post below (=
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Someone sticky please?
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The energy diagram was from n=4 to n=2 IIRC
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The energy diagram was from n=4 to n=2 IIRC
yes thats correct, sorry was a typo
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"An Error Has Occurred!
You are not allowed to access this section "
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"An Error Has Occurred!
You are not allowed to access this section "
cant download it?
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Lots of typos. Also I think you got question 1 backwards.
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"An Error Has Occurred!
You are not allowed to access this section "
cant download it?
Wait just managed to. Nice work :)
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Lots of typos. Also I think you got question 1 backwards.
sorry i was trying to get these up quickly.
I see what you mean with q1 , ill change it now
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thanks man you raised my confidence. i went out of the exam thinking i lost like 15 marks over those 2 sections. now i've lost 5 tops if my explanations sucked
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thanks man you raised my confidence. i went out of the exam thinking i lost like 15 marks over those 2 sections. now i've lost 5 tops if my explanations sucked
no problems, i got sound solutions coming soon
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was Q to P from left to right or the other way round?
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thanks man you raised my confidence. i went out of the exam thinking i lost like 15 marks over those 2 sections. now i've lost 5 tops if my explanations sucked
no problems, i got sound solutions coming soon
awesome lol i did sound. looks like we might have an answer for the question 10 squabble
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thanks man you raised my confidence. i went out of the exam thinking i lost like 15 marks over those 2 sections. now i've lost 5 tops if my explanations sucked
no problems, i got sound solutions coming soon
awesome lol i did sound. looks like we might have an answer for the question 10 squabble
sound apart from q10 was a freakin breeze. did it in 5 mins. lol
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was Q to P from left to right or the other way round?
from left to right? do you mean the flux?
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Are you sure about sound q9?
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I meant the current bro.
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Are you sure about sound q9?
yes im fairly sure, although im no sound expert i just went along with a the linear reigon being associated with best reproduction of sound.
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I meant the current bro.
The current flows from Q to P
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yeah i know that, but was Q to P from left to right?
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yeah i know that, but was Q to P from left to right?
oh sorry, no Q to P is from right to left, i was refering to the flux cutting the loop from left to right
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thanks
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Guys was it Faraday's Law or Lenz's Law...?
I wrote Lenz's law ><
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I think I got 87-88/90 depending on what they take for that "which physical law applies" question as right.
Looks good! :D
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Guys was it Faraday's Law or Lenz's Law...?
I wrote Lenz's law ><
im unsure, i was retarded and wrote conservation of energy. dont ask why
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I didn't see the energy state question until last 30 seconds
GG
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I can't download this :S
What should I be viewing them under? thanks
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I can't download this :S
What should I be viewing them under? thanks
what happens when you click on it ?
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for question 10.
didnt you have to divide the time by 4 first? because it was an average emf?
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for question 10.
didnt you have to divide the time by 4 first? because it was an average emf?
The time given was the time it took to go from a maximum to a minimum flux though. So you didn't need to change it.
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hmm i said lenz's law seeing as a negative voltage was important
if i drew the circuit as having the line from each resister, so connecting them directly, is that ok? i actually stated next to it that the resisters must be in series.
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for question 10.
didnt you have to divide the time by 4 first? because it was an average emf?
no because they told you the field was decreasing over a period. it didn't say the coil was rotated with a period of x seconds.
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for question 10.
didnt you have to divide the time by 4 first? because it was an average emf?
Why 4?
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hmm i said lenz's law seeing as a negative voltage was important
if i drew the circuit as having the line from each resister, so connecting them directly, is that ok? i actually stated next to it that the resisters must be in series.
Dont take my answers as the actual answers. I didnt even write Faraday's law on my exam.
And im not quite sure what you mean with the circuit?
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for question 10.
didnt you have to divide the time by 4 first? because it was an average emf?
The time given was the time it took to go from a maximum to a minimum flux though. So you didn't need to change it.
i thought it said the period was .012?
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for question 10.
didnt you have to divide the time by 4 first? because it was an average emf?
The time given was the time it took to go from a maximum to a minimum flux though. So you didn't need to change it.
i thought it said the period was .012?
To quote the question " The magnetic field is now reduced to zero over a period of 0.012s"
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It said the coil rotated from maximum to 0 in a period 0.012 seconds. Confusing wording, yes.
So you didn't have to divide by 4.
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I can't download this :S
What should I be viewing them under? thanks
what happens when you click on it ?
A pop up appears with open with or save.
What should i be opening this with?
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I can't download this :S
What should I be viewing them under? thanks
what happens when you click on it ?
A pop up appears with open with or save.
What should i be opening this with?
its a microsoft word document, save it to your computer then try open it if you have word.
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for q10, would i get 1 mark for statng that the wavelengths are equal?
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for q10, would i get 1 mark for statng that the wavelengths are equal?
not sure to be honest, possibly
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thanks mate for this, much appreciated
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thanks mate for this, much appreciated
no problems.
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thanks :)
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I'm bending over for you now "whatlol" you are messiah.. note, please don't take this bending as sexual.
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I'm bending over for you now "whatlol" you are messiah.. note, please don't take this bending as sexual.
...
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for the n=4 to n=2 isnt there 2 arrows
cause they said something abbout 2... so n=4 to n=3 then n=3 to n=2 ?
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for the n=4 to n=2 isnt there 2 arrows
cause they said something abbout 2... so n=4 to n=3 then n=3 to n=2 ?
Nah they said a transition between two energy levels so from one energy level to another I'm pretty sure.
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" A photon of wavelength 478nm is emitted from an excited hydrogen atom, The emerging photon is caused by a trasnition between two energy states. Draw an arrow on Figure 6 that shows this transition from the initial to the final energy state"
so what blackhitman said.
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omg so i dont get a mark or 2 :( T___________T WAHHHHHHHHHHHHHHHHHHHHHHHHH
so far 2+2+2+2+2=10 OMO SO MANY MARKS GONE
damn my shit english understanding
that makes me feel like crap...do i get 1 mark atleast =D???
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omg so i dont get a mark or 2 :( T___________T WAHHHHHHHHHHHHHHHHHHHHHHHHH
so far 2+2+2+2+2=10 OMO SO MANY MARKS GONE
damn my shit english understanding
that makes me feel like crap...do i get 1 mark atleast =D???
hmm not sure to be honest i dont really know what they will do, unfortunately i dont think so
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THANKS TO WHATLOL'S UBER GOOD SOLUTIONS I HAVE FOUND OUT THAT I LOST A MINIMUM 14 marks...do i still get an A ? maybe? ..no chance? :(
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THANKS TO WHATLOL'S UBER GOOD SOLUTIONS I HAVE FOUND OUT THAT I LOST A MINIMUM 14 marks...do i still get an A ? maybe? ..no chance? :(
its possible, say A+ cut off is about 83 - 84 you may get an A
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The circuit question?? does it matter how we drew it :o i drew it in series but not a digonal :|
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The circuit question?? does it matter how we drew it :o i drew it in series but not a digonal :|
i honestly dont know i got it wrong. i assume if you did it in series it should be ok
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The circuit question?? does it matter how we drew it :o i drew it in series but not a digonal :|
How did you draw it then?
Because you can't just leave the end of the second element unattached (assuming you just drew a vertical line connecting the two). The circuit would not be complete.
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what lol did u draw a vertical line down the left side? cause i did bloody rushing costs ya
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what lol did u draw a vertical line down the left side? cause i did bloody rushing costs ya
no, id rather not discuss what i did because it lost me 2 marks )=
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I KNOW OK :P i dint think of diagonal line thattime but its still series??
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thats parallel
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What those r the two elements..Hows tht parallel?? its just a wire twister rather going straight to the thing :P
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i couldnt think of how to make it series )=
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no thats series, should be right i think :)
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IF i lose a mark for that :P !!! vCAA BETTER NOt ;P
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I KNOW OK :P i dint think of diagonal line thattime but its still series??
That's fine. You'll get the marks :P
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i disagree with your answer to question 10 of sound! i believe its A =[
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i disagree with your answer to question 10 of sound! i believe its A =[
It may well be, but i would think it is B since the 3000Hz produces a larger response than the 1000Hz
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i disagree with your answer to question 10 of sound! i believe its A =[
It may well be, but i would think it is B since the 3000Hz produces a larger response than the 1000Hz
Hey, Whatlol, could you check the graph in option B for Sound Q10 and report if the 3000Hz sound had 1/3 the period of the 1000Hz sound?
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i disagree with your answer to question 10 of sound! i believe its A =[
It may well be, but i would think it is B since the 3000Hz produces a larger response than the 1000Hz
Hey, Whatlol, could you check the graph in option B for Sound Q10 and report if the 3000Hz sound had 1/3 the period of the 1000Hz sound?
The period of the sounds for graphs A and B are identical i just checked it then.
The 1000Hz sound on graphs A and B both take up 4 squares(for one period) The 3000Hz sounds on graphs A and B both take up 1 square for one period
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i disagree with your answer to question 10 of sound! i believe its A =[
It may well be, but i would think it is B since the 3000Hz produces a larger response than the 1000Hz
Hey, Whatlol, could you check the graph in option B for Sound Q10 and report if the 3000Hz sound had 1/3 the period of the 1000Hz sound?
The period of the sounds for graphs A and B are identical i just checked it then.
The 1000Hz sound on graphs A and B both take up 4 squares(for one period) The 3000Hz sounds on graphs A and B both take up 1 square for one period
Sucks to be me then because I chose A :buck2:
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i disagree with your answer to question 10 of sound! i believe its A =[
It may well be, but i would think it is B since the 3000Hz produces a larger response than the 1000Hz
Hey, Whatlol, could you check the graph in option B for Sound Q10 and report if the 3000Hz sound had 1/3 the period of the 1000Hz sound?
The period of the sounds for graphs A and B are identical i just checked it then.
The 1000Hz sound on graphs A and B both take up 4 squares(for one period) The 3000Hz sounds on graphs A and B both take up 1 square for one period
Sucks to be me then because I chose A :buck2:
it really depends on just what they implied by the sound intensities being the same at the microphone ,i personally feel this means that they are made the same that way their responses can be compared equally , for example if the 1000Hz sample was three times louder than the 3000hz sound when it enters the microphone, you may actually interpret that as them both producing the same response , since the microphone responds louder to the 3000hz than the 1000hz. So if they are both the same intensities when they enter the mic, then you will observe the differences.
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Does it say that the frequency-response graph had to be used for the next question?
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what did the Q6 graph actually look like? (in electricity)
i cant remember which one i put
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Does it say that the frequency-response graph had to be used for the next question?
Not directly, but i will write out the question for everyone.
"To test the frequency response of the microphone, a variable frequency sound source is used. The sound emits a pure tone of 1000Hz, followed by a pure tone of 3000Hz. The sound source is adjusted so that the two tones have the same sound intensity at the microphone. In the diagrams below, first a 1000Hz and then a 3000Hz signal are displayed on an oscilloscope.
Which display best shows what will be observed on the oscilloscope?"
Also at the top of the frequency response curve it states "The following information relates to Questions 9 and 10"
I personally feel that you must take into account the frequency response curve since what is displayed on the oscilloscope depends on the frequency response of the microphone itself.
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what did the Q6 graph actually look like? (in electricity)
i cant remember which one i put
Question six , i assume you mean for electric power.
Each graph shows you a the graph of flux versus time and over that it has the corresponding voltage. the answer (A) displays voltage as the negative rate of change of flux so it was basically a cosine curve (as the graph of flux was a sine curve)
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Does it say that the frequency-response graph had to be used for the next question?
Not directly, but i will write out the question for everyone.
"To test the frequency response of the microphone, a variable frequency sound source is used. The sound emits a pure tone of 1000Hz, followed by a pure tone of 3000Hz. The sound source is adjusted so that the two tones have the same sound intensity at the microphone. In the diagrams below, first a 1000Hz and then a 3000Hz signal are displayed on an oscilloscope.
Which display best shows what will be observed on the oscilloscope?"
Also at the top of the frequency response curve it states "The following information relates to Questions 9 and 10"
I personally feel that you must take into account the frequency response curve since what is displayed on the oscilloscope depends on the frequency response of the microphone itself.
Yeah, then it has to be B.
Damn... I thought it was a separate question.
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Did anyone get Lenz's law for Q9 in the first section? I actually wrote negative gradient, which is wrong >.<
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Did anyone get Lenz's law for Q9 in the first section? I actually wrote negative gradient, which is wrong >.<
It is being debated whether it is Lenz's or faraday's law so we will find out once VCAA releases solutions (if anyone even cares then)
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Did anyone get Lenz's law for Q9 in the first section? I actually wrote negative gradient, which is wrong >.<
It is being debated whether it is Lenz's or faraday's law so we will find out once VCAA releases solutions (if anyone even cares then)
Haha, wouldn't care less by then.
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There's this thing called pdf. It doesn't stand for 'portable' for no reason.
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There's this thing called pdf. It doesn't stand for 'portable' for no reason.
well im so sorry i couldn't get a pdf for you, im not good with using that software.