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VCE Stuff => VCE Science => VCE Mathematics/Science/Technology => VCE Subjects + Help => VCE Chemistry => Topic started by: tarek on December 02, 2010, 06:51:03 pm

Title: Who can answer this please (+) : Cl- ions in 13.4 g of nickel chloride (NiCl2)
Post by: tarek on December 02, 2010, 06:51:03 pm

with working out! I already know the answer.

Title: Re: Who can answer this please (+) : Cl- ions in 13.4 g of nickel chloride (NiCl2)
Post by: kenhung123 on December 02, 2010, 07:01:56 pm

n(Cl-)=2n(NiCl2)=13.4/M(NiCl2)

Title: Re: Who can answer this please (+) : Cl- ions in 13.4 g of nickel chloride (NiCl2)
Post by: kakar0t on December 02, 2010, 07:04:15 pm

n(NiCl2)= 13.4g/129.71gmol-1
n(NiCl2)=0.103mol
n(Cl-) = 2 x n(NiCl2) =0.207 mol
N(Cl-) = n(Cl-) * avagadros constant
N(Cl-)= 0.207 mol * 6.023 * 10^23
N(Cl-)=1.24*10^23 Cl- ions

Title: Re: Who can answer this please (+) : Cl- ions in 13.4 g of nickel chloride (NiCl2)
Post by: tarek on December 02, 2010, 09:12:07 pm

thank you! how do you reward some one?

Title: Re: Who can answer this please (+) : Cl- ions in 13.4 g of nickel chloride (NiCl2)
Post by: iNerd on December 02, 2010, 09:18:53 pm

Quote from: tarek on December 02, 2010, 09:12:07 pm

thank you! how do you reward some one?

Karma requires 50 posts.

Title: Re: Who can answer this please (+) : Cl- ions in 13.4 g of nickel chloride (NiCl
Post by: sanam on December 11, 2010, 09:08:08 pm

yeah i was wondering how this karma stuff works, cos im a newbie would someone like to explain! thanks! :angel: