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VCE Stuff => VCE Science => VCE Mathematics/Science/Technology => VCE Subjects + Help => VCE Chemistry => Topic started by: Cappuccinos on January 13, 2011, 07:48:01 pm

Title: Steph243's Chem Questions
Post by: Cappuccinos on January 13, 2011, 07:48:01 pm
Calculate the amount of substance in (in mol), in the following samples (simple yes?)

d) 157.3g of Sodium Hyrdoxide
(Values from Data Booket)
(Values from Textbook)





But the book tells me I'm wrong :tickedoff:  (says 3.983?!)     Why?


AND Does anyone have the worked answers for StudyOn Chemistry 2? (I can only find ones for heinamann >.<) If so, could you please upload it or something? Because the answers at the back of the book don't seem to reliable   :-\  Thanks a million! :angel:
Title: Re: Question! + StudyOn Chemistry 2?
Post by: Cappuccinos on January 13, 2011, 08:14:32 pm
Studyon is quite a good book, but the solutions can be wrong at times. If I recall correctly, they are mainly the minor calculation errors. No need to fuss too much over them.

With regard to your request for worked solutions, its attached with this post~  :)

Thank you so so so so so so much for the worked solutions!!  :D  I'd Karma, but i don't know how  :-[

And yep, I just checked the answer for this question in the worked solutions, and it's right! (well I just gotta round my answer) .
I thought it was wrong due to sig figs or something, but yeah.   

Thank you again!!   :)
Title: Re: Steph243's Chem Questions
Post by: Cappuccinos on March 08, 2011, 07:04:09 pm
Okay, so normally I just copy the answer out of the book for these types of questions, but the teacher is making me show working out and I have no idea where to start...

A bottle of ‘Wunda White’ bleach lists the following as its active ingredients: sodium hypochlorite, NaOCl,
40 g/L; sodium hydroxide, NaOH, 9 g/L. A chemist wishes to check both these claims using volumetric analysis.


9. NaOCl reacts as an oxidant. To check the sodium hypochlorite claim, the bleach should be reacted with:
A solution
B solution
C   solution
D NaOH solution.

The answer is B....