ATAR Notes: Forum

VCE Stuff => VCE Mathematics => VCE Mathematics/Science/Technology => VCE Subjects + Help => VCE Specialist Mathematics => Topic started by: DannyN on January 14, 2011, 01:16:34 pm

Title: NEED HELP WITH A SHORT EQUATION! CIRCULAR FUNCTION PROBLEM
Post by: DannyN on January 14, 2011, 01:16:34 pm: i know it must be really easy but i dont know how do i find the asymptote of this equation
F(x)=inverse(cos)(6/x)

help would be really appreciated! thanks!~ :D
Title: Re: NEED HELP WITH A SHORT EQUATION! CIRCULAR FUNCTION PROBLEM
Post by: kamil9876 on January 14, 2011, 01:49:42 pm: So it would be good to firstly sketch/get a feel for the general behaviour of the function. What is the domain? you see immediately that $x\leq -6$ and $x \geq 6$ Hence that means that the only possible asymptote is when $x \to \infty$ or $x \to -\infty$ . As $x \to \infty$ , you see that that $6/x$ approaches $0$ hence the value of the function approaches $\pi/2$ if we use the standard definition of inverse cos. Same story if it approaches $-\infty$ . Hence $y=\pi/2$ is the asympote
Title: Re: NEED HELP WITH A SHORT EQUATION! CIRCULAR FUNCTION PROBLEM
Post by: DannyN on January 14, 2011, 01:52:59 pm: OMG Thanks A lot!