ATAR Notes: Forum
VCE Stuff => VCE Science => VCE Mathematics/Science/Technology => VCE Subjects + Help => VCE Chemistry => Topic started by: zibb3r on February 12, 2011, 09:24:16 pm
-
Hi guys,
I just had my SAC yesterday, and I need to do 1 question. The SAC is on pg. 50 of the heinemann workbook titled "gravimetric determination of sulfur as sulfate in fertiliser". Anyway the question I have trouble with is: Use the molar masses of barium and sulfate to calculate the mass of sulfate ions in the solution". Any idea how to do this???
:smitten: :smitten: :smitten: :smitten: :smitten: :smitten: :smitten: :smitten: :smitten: :smitten: :smitten: :smitten: :smitten:
Thanks :smitten:
-
Haha chill out with the emoticons. xD
You can use the number of moles of barium sulfate to calculate the mass of sulfate ions in the solution since:
BaSO4---->Ba2+ + SO4 2-
Basically, the mole ratio for barium sulfate and sulfate ions is 1:1 and from there you can just use stoich to calculate the mass of sulfate ions.
-
lol, will do :uglystupid2:
So lets say that n(BaSO4)=0.0327 mol, how would i go from here???
Thanks
-
BaSO4---->Ba2+ + SO4 2-
So the mole ratio for BaSO4 and SO4 2- is 1:1.
n(SO4 2-)=n(BaSO4)=0.0327mol
m(SO4 2-)= no. of mole X molar mass
=0.0327 X (32.07+64.00)
=3.141g (4 significant figures)
Is this correct?
-
looks great!!!! can any1 clarify the procedure just to be sure?????
-
looks great!!!! can any1 clarify the procedure just to be sure?????
Yes it is indeed correct