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VCE Stuff => VCE Science => VCE Mathematics/Science/Technology => VCE Subjects + Help => VCE Chemistry => Topic started by: matt123 on March 08, 2011, 11:10:12 pm

Title: PLEASE HELP WITH MY EASY QUESTIONS ... MATHS AND CHEM
Post by: matt123 on March 08, 2011, 11:10:12 pm: hey guys ... can some 1 please help me on this.
its really basic .... but i dont get it ...

what is "1X10^-8" when expressed in nanometers ( nano = 1X10^-9)

also
...

are these names and formulas correct.

monocarbon tetrachloride = Ccl4

many thanks!
Title: Re: PLEASE HELP WITH MY EASY QUESTIONS ... MATHS AND CHEM
Post by: m@tty on March 08, 2011, 11:16:23 pm: I'm assuming, $1\times10^{-8}$ is in metres?

If so, to convert units divide by $1\times 10^{-9}$ which gives 10nm, or 1*10^1 nm, whichever, they're the same thing.

And yeah, monocarbon tetrachloride is $\text{CCl}_4$
Title: Re: PLEASE HELP WITH MY EASY QUESTIONS ... MATHS AND CHEM
Post by: luken93 on March 08, 2011, 11:17:33 pm: 1 x 10^-8 = 0.000000010
1 x 10^-9 = 0.000000001
Hence, 10 nanometres is equal to 1 x 10^-8
(Think about 1x10^-2m in relation to millimeters)

...

Yep
Title: Re: PLEASE HELP WITH MY EASY QUESTIONS ... MATHS AND CHEM
Post by: matt123 on March 08, 2011, 11:22:49 pm: Quote from: m@tty on March 08, 2011, 11:16:23 pm
I'm assuming, $1\times10^{-8}$ is in metres?

If so, to convert units divide by $1\times 10^{-9}$ which gives 10nm, or 1*10^1 nm, whichever, they're the same thing.

And yeah, monocarbon tetrachloride is $\text{CCl}_4$

No the question is this.
the diameter of a atom is 1X10^-8 CM .... ( ITS CM) lol..... convert to nanometers
what would be the answer??

thanks so much guys
Title: Re: PLEASE HELP WITH MY EASY QUESTIONS ... MATHS AND CHEM
Post by: m@tty on March 08, 2011, 11:36:23 pm: Ok, so it's cm. You can either convert to meters then to nm, or figure out the factor from cm->nm

So, $\underbrace{1\times 10^{-8} cm = 1\times 10^{-10}m}_{\text{Factor of 100}}$

$\underbrace{1\times 10^{-10}m=0.1nm}_{\text{Factor of }1\times 10^{-9}}$

Quote from: luken93 on March 08, 2011, 11:17:33 pm
1 x 10^-8 = 0.000000010
1 x 10^-9 = 0.000000001
Hence, 10 nanometres is equal to 1 x 10^-8
(Think about 1x10^-2m in relation to millimeters)

...

Yep

lol, you mean 1*10^-3?
Title: Re: PLEASE HELP WITH MY EASY QUESTIONS ... MATHS AND CHEM
Post by: matt123 on March 08, 2011, 11:42:40 pm: Quote from: m@tty on March 08, 2011, 11:36:23 pm
Ok, so it's cm. You can either convert to meters then to nm, or figure out the factor from cm->nm

So, $\underbrace{1\times 10^{-8} cm = 1\times 10^{-10}m}_{\text{Factor of 100}}$

$\underbrace{1\times 10^{-10}m=0.1nm}_{\text{Factor of }1\times 10^{-9}}$

Quote from: luken93 on March 08, 2011, 11:17:33 pm
1 x 10^-8 = 0.000000010
1 x 10^-9 = 0.000000001
Hence, 10 nanometres is equal to 1 x 10^-8
(Think about 1x10^-2m in relation to millimeters)

...

Yep

lol, you mean 1*10^-3?

thanks so much budd.

but lol what is the final answer... becuase the options are.

a.1X10^1 Nm
b." " ^ 10
c " " ^ 19
d. " " ^-1
e " " ^-15

i said B off your workings .. but im just double checking.
thanks again
Title: Re: PLEASE HELP WITH MY EASY QUESTIONS ... MATHS AND CHEM
Post by: m@tty on March 08, 2011, 11:46:24 pm: My final answer was 0.1 nm, so that is equivalent to 10 to the power of what?

Your selection, B, is 10^10, which is 10, 000, 000, 000 nm

Think about it, you should be able to tell which one it is.

No problem mate. :)
Title: Re: PLEASE HELP WITH MY EASY QUESTIONS ... MATHS AND CHEM
Post by: matt123 on March 08, 2011, 11:51:27 pm: Quote from: m@tty on March 08, 2011, 11:46:24 pm
My final answer was 0.1 nm, so that is equivalent to 10 to the power of what?

Your selection, B, is 10^10, which is 10, 000, 000, 000 nm

Think about it, you should be able to tell which one it is.

No problem mate. :)

The answer is 1X10-1 :) ..... right? hahaha
Title: Re: PLEASE HELP WITH MY EASY QUESTIONS ... MATHS AND CHEM
Post by: taiga on March 08, 2011, 11:54:53 pm: omg matt123 is back!
Title: Re: PLEASE HELP WITH MY EASY QUESTIONS ... MATHS AND CHEM
Post by: matt123 on March 08, 2011, 11:58:45 pm: Quote from: taiga on March 08, 2011, 11:54:53 pm
omg matt123 is back!

haha yeah brooo
im doing this basic maths stuff which i havnt done since grade 1 and so i cant remember anythinggg farkkkk im so dumb at the moment.

does anyone know the answer 2 this

v205 + 5Ca = 2V + 5ca0
10 mol of v205 is mixed with 10 mol of ca ... which is the limiting reagent
..... i said Ca .... is that right?

thanks in advanced.
Title: Re: PLEASE HELP WITH MY EASY QUESTIONS ... MATHS AND CHEM
Post by: m@tty on March 09, 2011, 12:06:38 am: Yep, you're right. According to the equation there is a 1:5 ratio for V2O5:Ca consumed, so after 10 mol of Ca ha reacted 8 mol of vanadium oxide will remain.

And yes, $1\times 10^{-1}$ is correct for your previous question.
Title: Re: PLEASE HELP WITH MY EASY QUESTIONS ... MATHS AND CHEM
Post by: 59 Fifty on March 15, 2011, 12:53:21 am: U doing pharmacy @ monash? coz im doing pharmacy this yr too, but i dont remember seeing a question like this... and i dont get any of it :(
Title: Re: PLEASE HELP WITH MY EASY QUESTIONS ... MATHS AND CHEM
Post by: matt123 on March 17, 2011, 10:46:40 am: nahh mate.

im studying at CSU