ATAR Notes: Forum
VCE Stuff => VCE Science => VCE Mathematics/Science/Technology => VCE Subjects + Help => VCE Chemistry => Topic started by: VivaTequila on April 14, 2011, 09:31:14 pm
-
Not sure if there are any other VCE Texts, but we use Heinemann Chemistry 2 (I don't know any schools that don't).
As of the end of term one, Mentone Grammar has covered everything up to Chapter 13, which we are expected to look at over the holidays. Most schools seem to be midway through carbon chemistry, at around chapters 9-10, so I feel we are going a tad too fast, especially considering that we briefly skimmed over all of chromatography and only did a little of NMR/Mass Spec.
Where are you guys up to?
-
just started organic chem argh
-
We're at around chp 10 i think
-
chapter 9 :S
-
NMR, but we've done a fair bit of organic chem already
-
NMR, but we've done a fair bit of organic chem already
Same. NMR and we've done a bit of year 11-standard organic. We did 3 SACs on aspirin... so I don't think we will need to revisit that!!
Moderator action: removed real name, sorry for the inconvenience
-
Chemistry class up to Chapter 9 - Compounds of Carbon but since it's holidays might as well get up to Chapter 14 - From organic molecules to medicines. ;D
Holiday homework to do one practice exam.
-
My chemistry class is up to ch 7, we've finished chapter 9 though.
Personally, im up to chapter 10, and hopefully will finish rest of unit 3 these holidays :)
-
My class in particular had its last lesson on Infrared .. chapter 7, with nothing done beyond that.
Although personally I'm starting carbon chemistry with a bit of luck and motivation over the holidays.
Suffice to say, we are screwed.
-
we finished the whole unit three when term one ended
on heinemann too
-
we finished the whole unit three when term one ended
on heinemann too
we finished unit 3 chem in year 10 before the year ended
-
Finished everything except NMR and IR. We don't go by the textbook though.
-
@ Nacho: wow in year 10 :D
Lol Which school is this ?
-
I bet you it's McRob :P I know they finish Jap 3/4 in year 11 and then just do practice exams in year 12.
-
we finished the whole unit three when term one ended
on heinemann too
we finished unit 3 chem in year 10 before the year ended
I finished before I started :o
I bet you it's McRob :P I know they finish Jap 3/4 in year 11 and then just do practice exams in year 12.
have you got that question yet thushan? I'm not looking at it anymore, I killed about 5 trees I reckon with the amount of drawings I did..
-
Not yet. Actually I'll just quickly read the NMR notes and actually try this qn properly.
-
I might have the answer...but there's an issue with it.
I worked out that a R-CH2-CH2-OH is needed. I have a feeling that there are more than 4 proton environments, but that the 7.25 one (which is the aromatic one I think) is really 3 environments 'fused' into one...
I propose that it could be Ph-CH2-CH2-OH.
I just need to do a little reading - I don't get NMR. Properly.
-
tush you have you guys done all the bio-molecules stuff in chem? peters is still up to organic, just starte
-
I might have the answer...but there's an issue with it.
I worked out that a R-CH2-CH2-OH is needed. I have a feeling that there are more than 4 proton environments, but that the 7.25 one (which is the aromatic one I think) is really 3 environments 'fused' into one...
I propose that it could be Ph-CH2-CH2-OH.
I just need to do a little reading - I don't get NMR. Properly.
post spectrum.
-
I might have the answer...but there's an issue with it.
I worked out that a R-CH2-CH2-OH is needed. I have a feeling that there are more than 4 proton environments, but that the 7.25 one (which is the aromatic one I think) is really 3 environments 'fused' into one...
I propose that it could be Ph-CH2-CH2-OH.
I just need to do a little reading - I don't get NMR. Properly.
post spectrum.
It's alright, we are quite sure we have it now!!!
But anyway, confirmation from you would be nice :P
BTW, it's CHM1011
"(b) An unknown organic compound has a molecular formula of C8H10O and the
following spectral data;
IR: 3340 cm-1, 13C NMR: δ140, 128, 127, 124, 62, and 39, 1H NMR: δ 2.01 (1H,
broad singlet, exchanges with D2O), 2.87 (2H, triplet), 4.85 (2H, triplet), 7.25 (5H,
multiplet). [chemical shift (integration, splitting)]."
Attached was the preliminary and now final structure that we think it could be...
-
Yeah, you've nailed it.
-
Yeah, you've nailed it.
Yay!
The thing we were unsure of, is that the difference between the H environments of the ring is negligible/small enough that it wouldn't produce separate peaks? Or is it that they do, hence the multiplicity?
-
Yeah, you've nailed it.
Yay!
The thing we were unsure of, is that the difference between the H environments of the ring is negligible/small enough that it wouldn't produce separate peaks? Or is it that they do, hence the multiplicity?
They would produce different peaks, but of course there are complications. In an aromatic ring, spin-spin coupling occurs for neighbouring nuclei at 3 bonds away as well as 4 bonds away. These peaks however are all at very similar chemical shifts. What you end up with is quite a few 'doubly' coupled peaks right on top of each other. The resulting peaks are quite complex, and often our machines are not good enough to clearly see the shape of the peaks to allow us to assign them (due to limited resolution of the instruments). So we just note this complex peak pattern as a 'multiplet' (I prefer to call it 'cluster-fuck', most lecturers don't appreciate it though).
-
Hahaha fair enough, just wondering how you derived that name? :P
And yeah, it seemed too complex to have 5 equivalent 1H environments when it wasn't a ring, hence why I kept going back to that structure...
Cheers
-
What's everyone up to now in chem? ive done chaps..1-9 excluding 8..(maybe some motivation to cover 1 or 2 more chapters tomorrow :P)
-
AOS 2 is the best part of chem
AOS 1 is just quite wacky and harder
-
I might have the answer...but there's an issue with it.
I worked out that a R-CH2-CH2-OH is needed. I have a feeling that there are more than 4 proton environments, but that the 7.25 one (which is the aromatic one I think) is really 3 environments 'fused' into one...
I propose that it could be Ph-CH2-CH2-OH.
I just need to do a little reading - I don't get NMR. Properly.
post spectrum.
It's alright, we are quite sure we have it now!!!
But anyway, confirmation from you would be nice :P
BTW, it's CHM1011
"(b) An unknown organic compound has a molecular formula of C8H10O and the
following spectral data;
IR: 3340 cm-1, 13C NMR: δ140, 128, 127, 124, 62, and 39, 1H NMR: δ 2.01 (1H,
broad singlet, exchanges with D2O), 2.87 (2H, triplet), 4.85 (2H, triplet), 7.25 (5H,
multiplet). [chemical shift (integration, splitting)]."
Attached was the preliminary and now final structure that we think it could be...
That is Uni Chem, right? :P
-
Yerp, don't worry about it haha
-
You know how worried I was getting when you guys were talking about NMR .. I didn't understand what was going on :o
-
half way through IR spectroscopy :(
-
Currently on Ch14.
We spent a long time on chapter 12, going through lots of more complex questions that are in the book.
Then all of a sudden, we spent two lessons on DNA and are looking at Aspirin now for a non-SAC prac that we are doing next week.
Doing all of our Biofuelds/Food Chem/Reaction Pathways/DNA SAC on Monday, with exactly one month to the chem exam
-
Started chapter 9 .. functional groups lol.
And apparently the class spent 20 min in total going over MS.
Honestly have no idea how this class is going to finish before the semester.
-
Chapter 12 this week... I feel my teacher is skimming too much too quickly - yes revision is important alas its pointless if we haven't learnt the work first :/
-
Chapter 12 this week... I feel my teacher is skimming too much too quickly - yes revision is important alas its pointless if we haven't learnt the work first :/
That's exactly the same as our class. We're skimming through each topic really briefly so we can finish sooner.