ATAR Notes: Forum
VCE Stuff => VCE Mathematics => VCE Mathematics/Science/Technology => VCE Subjects + Help => VCE Mathematical Methods CAS => Topic started by: spudman on November 06, 2008, 06:08:11 pm
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I know its really basic..
I am unable to come to grips with how dilation rules work.
How do u apply say a dilation parrallel to the x-axis by factor 3 vs dilation parralel to y-axis by factor 3 say to y=x^2 and y=1/x^2
Thanks alot :D
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parallel to x by a factor of 3:
\to f\left( \frac{x}{3}\right))
parallel to y by a factor of 3:
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ok ill do an example.
the graph of y=x^2 is goes through the following transformation:
Dilation factor of 3 in x -axis: ---> y= 3x^2
Dilation factor of 1/3 in y -axis: ---> y= (3x)^2 to become 9x^2
sorry guys...i fixed it just now :)
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ok ill do an example.
the graph of y=x^2 is goes through the following transformation:
Dilation factor of 3 in x -axis: ---> y= 3x^2
Dilation factor of 1/3 in y -axis: ---> y= (3x)^2 to become 6x^2
err is this correct? i'm sort of confused now lol
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in the y-axis=parallel to x-axis?
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Also, For translations, would it be better to write:
Shifted +4 units along the X axis
or like
Shifted 4 units in the positive direction of the X axis.
Is there a big difference. Thanks :)
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^Either is fine.
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Anyone able to help me out with these 2 questions?
State the transformations applied from g(x) to f(x):
(http://img503.imageshack.us/img503/8877/questionsbx3.png)
For both I had a reflection in the y-axis, but the answer says there is no reflection :o
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^4 = (2x-5)^4)

both are evenly symmetrical functions, hence reflecting in this sense doesn't really do anything.
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ugh haha how didn't i pick that up?!
thanks again mao
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Epic reply.