ATAR Notes: Forum

VCE Stuff => VCE Mathematics => VCE Mathematics/Science/Technology => VCE Subjects + Help => VCE Mathematical Methods CAS => Topic started by: Damo17 on December 15, 2008, 04:55:18 pm

Title: Logarithm help::
Post by: Damo17 on December 15, 2008, 04:55:18 pm: How do I work out the value of $-2loge5$ ?
Title: Re: Logarithm help::
Post by: vcestar on December 15, 2008, 04:56:25 pm: Just enter it in ur calc -2 ln 5
Title: Re: Logarithm help::
Post by: dekoyl on December 15, 2008, 04:58:25 pm: Yeah I'm just working it out; Is this meant to be calculator-free?

$log_e(5)^{-2}$

$log_e(\frac{1}{25})$

$log_e(1) - log_e(25)$

$-log_e(25)$

I don't know what else to do =\
Title: Re: Logarithm help::
Post by: Damo17 on December 15, 2008, 05:00:09 pm: Quote from: dekoyl on December 15, 2008, 04:58:25 pm
Yeah I'm just working it out; Is this meant to be calculator-free?

I'm not sure, the exercise says nothing about how to use the calculator to work anything out.
Title: Re: Logarithm help::
Post by: Damo17 on December 15, 2008, 05:01:52 pm: I guess you must have to use the calculator. It gets the right answer, thanks dekoyl and vcestar.
Title: Re: Logarithm help::
Post by: dekoyl on December 15, 2008, 08:14:03 pm: It's okay. Please post anymore questions you may have. I just got to keep the brain familiar with methods in case I decide to change my mind and repeat it :P Good luck.