ATAR Notes: Forum
VCE Stuff => VCE Mathematics => VCE Mathematics/Science/Technology => VCE Subjects + Help => VCE Mathematical Methods CAS => Topic started by: lacoste on January 09, 2009, 12:42:38 pm
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Qst A).
A coin is tossed 3 times and you note that the coin lands heads exactly twice. What is the probability that the first toss was the tail?
Help please, any help appreciated
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whats the answer?
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whats the answer?
Qst. A)
1/3
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These questions are from Conditional and Multiplication Rule Probability.. Including Qst. A)
Im not sure how they got the answers.
Qst B) A pair of fair dice are rolled. Find the probability that both numbers are odd given that the first die shows a number less than 4?
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A) I won't use maths, because the question is not too complicated:
exactly two H, meaning the possible combinations are: THH, HTH, HHT
hence the chance of T first is 1/3
B)
both odd = first odd * second odd
=Pr(odd|<4)=\frac{2}{3})
second odd is 1/2
hence both odd given that first is less than 4 would be 1/3
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1.

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1.

Why is it 3C2?
Does that mean 3 Combination? / a coin is tossed 3 times.
Shouldn't it be 3(0.5 * 0.5), because its 2 heads(50/50 chance) and three tosses?
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1.

Why is it 3C2?
Does that mean 3 Combination? / a coin is tossed 3 times.
Shouldn't it be 3(0.5 * 0.5), because its 2 heads(50/50 chance) and three tosses?
3C2 as in 2 heads in 3 tosses
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what does that equate to?
so 3C2 is equal to just 3?
why havnt i heard of"3C2" notation is that part of permuations or sumthin
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its nCr