ATAR Notes: Forum
Uni Stuff => Science => Faculties => Mathematics => Topic started by: squance on January 09, 2009, 03:09:13 pm
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Im really stuck on this question (well, a series of questions that are all related to finding existence of solutions and just want to know how to do one so I can do the rest).
Determine the values of k for which the system of linear equations has i). no solution vector, ii). a unique solution vector, iii). more than one solution vector (x,y, z).
kx + y + z = 1
x + ky + z = 1
x + y + kz = 1
I've made up a matrix with all these coeffiecients in it but after performing row operations on it, for the last row in the matrix, I get:
2-k^2 - k = 1-k
Which after you rearrange it its k^2 = 1
But the solution says (for the no solution vector one): k =-2 no solution and I have no idea how they got it.
for the unique solutions, it says k is all real numbers except for -2 and 1 (with some values in a matrix).
And for the multiple solutions, it says k = 1 (with some values in a matrix).
I really really really really need help. This question is driving me insane :(
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here it is, excuse the messy handwriting
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Wow. Thanks Mao :D
I actually finally worked out the question as well though I did my working a bit differently.
But thanks for showing me your way :D
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fark MAOanator!
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nice!
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here it is, excuse the messy handwriting
Nice, but sifn't LaTeX