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VCE Stuff => VCE Mathematics => VCE Mathematics/Science/Technology => VCE Subjects + Help => VCE General & Further Mathematics => Topic started by: lacoste on February 14, 2009, 12:34:12 pm

Title: Speed in Further
Post by: lacoste on February 14, 2009, 12:34:12 pm
An tennis ball under 'free fall' owing to gravity increases its speed (S) by 10m/s each second. Assuming that at the start the speed of the ball(object) was 0, the formula that relates S and time (t in seconds) is:

A. S=10t    B.S=10/t   C. S=t/10   D. S=5t  E. 20t

Could you also explain how you got the answer, many thanks!!

Title: Re: Speed in Further
Post by: Flaming_Arrow on February 14, 2009, 12:38:43 pm
hint: v = u + at
Title: Re: Speed in Further
Post by: kurrymuncher on February 14, 2009, 12:41:10 pm
V= u + at

V= 0 + 10(t)

V= 10t
Title: Re: Speed in Further
Post by: lacoste on February 14, 2009, 12:41:45 pm
hint: v = u + at


Further doesn't use these Physics formulas.. just Speed=distance/time
Title: Re: Speed in Further
Post by: lacoste on February 14, 2009, 12:43:41 pm
Thanks guys, is there another way without using v=u+at?

because i don't think that formula is in the further course?
Title: Re: Speed in Further
Post by: methodsboy on February 14, 2009, 12:48:43 pm
WTH! there's motion in further ???
Title: Re: Speed in Further
Post by: Flaming_Arrow on February 14, 2009, 12:53:55 pm
distance = speed * time

acceleration = speed / time

speed = acceleration * time

therefore S = at (given initial speed is 0)
Title: Re: Speed in Further
Post by: mypurpleundercracka on February 14, 2009, 01:34:25 pm
what ch this in? were stuck on bloody statistics
Title: Re: Speed in Further
Post by: plato on February 17, 2009, 10:19:00 pm
An tennis ball under 'free fall' owing to gravity increases its speed (S) by 10m/s each second. Assuming that at the start the speed of the ball(object) was 0, the formula that relates S and time (t in seconds) is:

A. S=10t    B.S=10/t   C. S=t/10   D. S=5t  E. 20t

Could you also explain how you got the answer, many thanks!!


The velocity, acceleration etc formulas for motion are not in the Further Maths Study Design.
Still, the question asked here is relevant to the Graphs and Relations module of Further.
Since speed is increasing at a constant rate of 10m/s each second, then a graph of S against time must produce a straight line (throught the origin) with a constant gradient of 10.
Hence S = 10t  (compare this with y = mx)

Just ignore the reference to "gravity".