ATAR Notes: Forum

VCE Stuff => VCE Mathematics => VCE Mathematics/Science/Technology => VCE Subjects + Help => VCE Mathematical Methods CAS => Topic started by: fivecent on February 24, 2009, 07:58:11 pm

Title: My methods Q's
Post by: fivecent on February 24, 2009, 07:58:11 pm: x^2 - 3mx + 4 = 0 (no solution)

find the values of m
when you insert in the equation there will be no solution

I'm stuck, never seen a question like this before
Title: Re: My methods Q's
Post by: Flaming_Arrow on February 24, 2009, 08:03:18 pm: a= 1 b= - 3m c = 4

$9m^2-16<0$

$m^2<\frac{16}{9}$

$-\frac{4}{3}<m<\frac{4}{3}$

is that the answer?

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