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VCE Stuff => VCE Mathematics => VCE Mathematics/Science/Technology => VCE Subjects + Help => VCE General & Further Mathematics => Topic started by: KyngPynn on July 25, 2011, 11:38:24 am

Title: (Linear)How would you graph this equation?
Post by: KyngPynn on July 25, 2011, 11:38:24 am

2x - 6y < 3

and

x-2y > 3?

Title: Re: (Linear)How would you graph this equation?
Post by: KyngPynn on July 25, 2011, 11:51:36 am

like how would i graph 3/2 on the x axis

and 3/2 on the y axis?

Title: Re: (Linear)How would you graph this equation?
Post by: taiga on July 25, 2011, 01:40:34 pm

Take it as an equal sign first, and draw a dotted line rather than a full one.

Then if it is > then you shade everything above the dotted line, and if it is < then you shade everything below the dotten line.

Not sure what you mean by "how would i graph 3/2 on the x axis", but it is exactly between 1 and 2.

Title: Re: (Linear)How would you graph this equation?
Post by: TrueTears on July 25, 2011, 02:21:47 pm

Quote from: KyngPynn on July 25, 2011, 11:51:36 am

like how would i graph 3/2 on the x axis

and 3/2 on the y axis?

maybe you mean x = 3/2 and y = 3/2? The former is the vertical line passing through x = 3/2 and the latter is a horizontal line passing through y = 3/2