ATAR Notes: Forum

VCE Stuff => VCE Science => VCE Mathematics/Science/Technology => VCE Subjects + Help => VCE Chemistry => Topic started by: SDPHD on August 16, 2011, 06:01:22 pm

Title: Acid - Base Question.
Post by: SDPHD on August 16, 2011, 06:01:22 pm: I'm wondering how to do this question.

The answer seems pretty straight forward, but I don't know how or why you do what you're meant to do.

(http://i25.lulzimg.com/dc0194.png)

Any help is much appreciated, thanks.
Title: Re: Acid - Base Question.
Post by: Vincezor on August 16, 2011, 06:53:52 pm: As it is a neutral solution, $[D^+] = [OD^-]$

$K_d= 1.82*10^{-16} = (D+)^2$

$[D^+]=\sqrt{1.82*10^{-16}}=1.35*10^{-8}M$

=B?
Title: Re: Acid - Base Question.
Post by: BoredSatan on August 16, 2011, 08:15:56 pm: Looks correct Vincezor ;)
Title: Re: Acid - Base Question.
Post by: SDPHD on August 16, 2011, 08:49:16 pm: Quote from: Vincezor on August 16, 2011, 06:53:52 pm
As it is a neutral solution, $[D^+] = [OD^-]$

$K_d= 1.82*10^{-16} = (D+)^2$

$[D^+]=\sqrt{1.82*10^{-16}}=1.35*10^{-8}M$

=B?

Makes sense now, thanks.