Post by: paulsterio on October 14, 2011, 08:37:53 pm
By Paulsterio & Luffy
Here's the Spesh Exam 1 everyone! :)
Good luck!
Still working on both Methods & Spesh Exam 2
Solutions to this exam (Exam 1) are here : Coming Soon
Have Fun!!
Post by: tony3272 on October 14, 2011, 08:47:57 pm
Post by: paulsterio on October 14, 2011, 08:49:12 pm
Post by: xZero on October 14, 2011, 09:18:17 pm
Post by: paulsterio on October 14, 2011, 09:20:03 pm
for q1 b), exact value of dy/dx or value of dy/dx in terms of k?
That question is actually based of a VCAA question, and they just said, find the value of dy/dx, without saying anything else, and what you had to do was find it NOT in terms of k, because they said that by giving the point, the value of k is fixed, i think it was the VCAA 2009 (or maybe 2010) Exam 1
Post by: b^3 on October 14, 2011, 09:24:55 pm
VCAA 2009 Exam 1 5c.for q1 b), exact value of dy/dx or value of dy/dx in terms of k?
That question is actually based of a VCAA question, and they just said, find the value of dy/dx, without saying anything else, and what you had to do was find it NOT in terms of k, because they said that by giving the point, the value of k is fixed, i think it was the VCAA 2009 (or maybe 2010) Exam 1
Post by: Natters on October 14, 2011, 10:21:41 pm
A LOGO
edit: ahahahhahahahhahahahh and you didn't write "this page is blank" epic
can i ask how hard this is on a 1-10 scale with the vcaa's being 5?
Post by: pi on October 14, 2011, 10:26:20 pm
can i ask how hard this is on a 1-10 scale with the vcaa's being 5?
Maybe a 6? 7?
Post by: HenryP on October 14, 2011, 10:28:56 pm
oh my god you guys made this? it has a logo peopleI'd give it a 7 to be honest, keep in mind that I'm a bad specialist student though :P
A LOGO
edit: ahahahhahahahhahahahh and you didn't write "this page is blank" epic
can i ask how hard this is on a 1-10 scale with the vcaa's being 5?
Post by: paulsterio on October 14, 2011, 10:45:15 pm
oh my god you guys made this? it has a logo people
A LOGO
edit: ahahahhahahahhahahahh and you didn't write "this page is blank" epic
can i ask how hard this is on a 1-10 scale with the vcaa's being 5?
It was designed to be about a 7, I don't personally think it'll be harder than a Kilbaha, it's probably at the same level as an average Kilbaha or MAV, but it's not too much harder
So guys that have done it, how did you find it? :)
Post by: HarveyD on October 14, 2011, 10:49:03 pm
(sorry for off-topic)
Post by: paulsterio on October 14, 2011, 10:52:14 pm
just out of interest, where would you guys place Heffernan in that range?
(sorry for off-topic)
I'd say Heffernan is around a 5-6
Post by: b^3 on October 14, 2011, 10:57:07 pm
Really? I'd say heffernan would be a 3-4.just out of interest, where would you guys place Heffernan in that range?
(sorry for off-topic)
I'd say Heffernan is around a 5-6
Post by: paulsterio on October 14, 2011, 11:01:51 pm
Really? I'd say heffernan would be a 3-4.
I wouldn't rate heffernan below VCAA, I think they're pretty similar in level, but it would depend though
Post by: b^3 on October 14, 2011, 11:05:03 pm
I'm guessing we would put something like Insight as a 1 or a 2?Really? I'd say heffernan would be a 3-4.
I wouldn't rate heffernan below VCAA, I think they're pretty similar in level, but it would depend though
EDIT: I'm stating to drift off-topic again, sorry guys I'll keep quiet now.
Post by: costa94 on October 14, 2011, 11:11:13 pm
Post by: nacho on October 14, 2011, 11:12:26 pm
0.5 for thisi rate you a 0.5 as a person
Post by: costa94 on October 14, 2011, 11:28:18 pm
0.5 for thisi rate you a 0.5 as a person
but im the trig king
Post by: paulsterio on October 14, 2011, 11:45:11 pm
I'm guessing we would put something like Insight as a 1 or a 2?Really? I'd say heffernan would be a 3-4.
I wouldn't rate heffernan below VCAA, I think they're pretty similar in level, but it would depend though
EDIT: I'm stating to drift off-topic again, sorry guys I'll keep quiet now.
Off topic I know, but last comment, YES I AGREE WITH YOU! Insight would be as easy as you can get! :P
0.5 for thisI personally don't think that your comments are appropriate, although I understand that you may be joking, your comments are "spam-like" and generally not constructive
Post by: taiga on October 15, 2011, 12:00:11 am
if you're trying to be funny, cool man
Post by: thushan on October 15, 2011, 08:11:28 am
On a side note, Kilbaha is awesome, my fav Spesh exam company!
Post by: 99.96 on October 15, 2011, 08:37:22 am
Post by: jane1234 on October 15, 2011, 09:40:02 am
I just did the paper and yeah, have to agree with thushan in that it's fairly straightforward. Probably on par with VCAA, or at least the ones I've done, in that there are no overly complicated questions. Nonetheless, a great practice exam! :)
Post by: 99.96 on October 15, 2011, 09:53:55 am
I did them but i think its wrong.
Post by: paulsterio on October 15, 2011, 09:59:08 am
Had a quick scan of the paper, it's well written, and I think I would actually rate this a 4-6; I say this because VCAA papers are actually relatively difficult - well at least the 2008 paper was. But if you can match VCAA you're doing well.
On a side note, Kilbaha is awesome, my fav Spesh exam company!
hmm yeah that's true, vcaa papers for specialist maths exam 1 are actually far more difficult than vcaa exam 1's for methods, i was actually quite surprised with the jump from methods to spesh! D:
I'll give this a shot, btw this year's exam has 11 questions ;)yeah i know, but I ran out of marks on my exam, I'd already allocated 40 marks by question 10 and it was too hard to try to cut down on marks :P
Good job guys!thanks jane! :D it's nice when people actually do it hahah :) i guess i get a feeling of satisfaction :P LOL!
I just did the paper and yeah, have to agree with thushan in that it's fairly straightforward. Probably on par with VCAA, or at least the ones I've done, in that there are no overly complicated questions. Nonetheless, a great practice exam! :)
Post by: jane1234 on October 15, 2011, 09:59:43 am
^^^ how exactly do you do 8a and b.
I did them but i think its wrong.
You turn z + 1/z = k into a quadratic, then use the quadratic formula to solve for z.
Using the discriminant, we know that if k^2 - 4 >= 0 then z will lie on the real axis.
If not, then sqrt(k^2-4) will be an imaginary number.
Let z = x + yi, and x = k/2, y = sqrt(4-k^2)/2 (you have to times k^2-4 by -1 because you are after the imaginary PART of z).
Square both x and y, add them together and you get x^2 + y^2 = 1, showing that z either lies on the real axis or on the unit circle.
Part b is easy once you have done this. :)
Post by: paulsterio on October 15, 2011, 10:02:38 am
You turn z + 1/z = k into a quadratic, then use the quadratic formula to solve for z.
Using the discriminant, we know that if k^2 - 4 >= 0 then z will lie on the real axis.
If not, then sqrt(k^2-4) will be an imaginary number.
Let z = x + yi, and x = k/2, y = sqrt(4-k^2)/2 (you have to times k^2-4 by -1 because you are after the imaginary PART of z).
Square both x and y, add them together and you get x^2 + y^2 = 1, showing that z either lies on the real axis or on the unit circle.
Part b is easy once you have done this. :)
Thanks Jane, you beat me to it! :P
Post by: zool3 on October 18, 2011, 04:32:33 pm
Post by: paulsterio on October 18, 2011, 05:11:56 pm
solutions for this?
Doing them :)
Post by: zool3 on October 18, 2011, 08:13:13 pm
Post by: ulbasour on October 18, 2011, 11:15:24 pm
Had a quick scan of the paper, it's well written, and I think I would actually rate this a 4-6; I say this because VCAA papers are actually relatively difficult - well at least the 2008 paper was. But if you can match VCAA you're doing well.
On a side note, Kilbaha is awesome, my fav Spesh exam company!
Agreed with the 2008 vcaa one!!! I can rest happier knowing that thushan had trouble with it haha.
I havent done the paper yet but had a quick flick through and it lilkes solid but doable if that makes sense. You could sell these papers to a company or start your own. You'd make a fair deal of dosh from it aswell cos of the high demand. My teachers did some english ones and are getting paid like 50 per paper,they've made about 5-6 grand!
Post by: Dangster on October 22, 2011, 09:26:30 pm
thanks!! =D
Post by: Dangster on October 22, 2011, 09:37:57 pm
Could somebody help me with q.6b instead? ^^
Post by: zool3 on October 22, 2011, 11:02:13 pm
Post by: fbash23 on October 28, 2011, 04:38:48 pm
Post by: Thelimz on November 01, 2011, 11:13:04 pm
Post by: BubbleWrapMan on November 02, 2011, 03:45:44 pm
Post by: HONKHIEM on November 06, 2011, 04:21:15 pm
Post by: Zebra on November 06, 2011, 05:30:53 pm
Post by: butene on January 01, 2012, 06:50:49 pm
Post by: pi on January 01, 2012, 09:26:31 pm
Post by: paulsterio on January 01, 2012, 09:33:33 pm
Post by: Jenny_2108 on June 17, 2012, 08:49:17 pm
Puffy Publications 2011 - Specialist Maths - ATARNotes Trial Examination
By Paulsterio & Luffy
Here's the Spesh Exam 1 everyone! :)
Good luck!
Still working on both Methods & Spesh Exam 2
Solutions to this exam (Exam 1) are here : Coming Soon
Have Fun!!
Thanks for posting :D When will the solution be available?
Post by: Jenny_2108 on July 12, 2012, 10:56:28 pm
Post by: Lasercookie on October 30, 2012, 03:32:46 pm
can we have the solutions :P
Post by: paulsterio on October 30, 2012, 03:35:05 pm
can we have the solutions :P
Ah yes, I'll do the solutions right now :)
Post by: BigAl on October 30, 2012, 07:15:47 pm
Post by: paulsterio on October 30, 2012, 07:17:48 pm
Not bad :) :) I wish the real exam is this much easy :D
This is probably harder than a real VCAA exam :P
Post by: vcestudent94 on November 01, 2012, 07:51:39 pm
Post by: paulsterio on November 01, 2012, 07:55:41 pm
I don't mean to be annoying but when exactly are the answers going to be up?
Tomorrow, because I have an exam tomorrow morning which I need to study for, they'll be up within 24 hours, I don't mean to take long, but my exam tomorrow is pretty important as well and Spesh is a while away :P
Post by: vcestudent94 on November 01, 2012, 08:12:30 pm
All good! :DI don't mean to be annoying but when exactly are the answers going to be up?
Tomorrow, because I have an exam tomorrow morning which I need to study for, they'll be up within 24 hours, I don't mean to take long, but my exam tomorrow is pretty important as well and Spesh is a while away :P
Post by: Moko on November 04, 2012, 10:03:53 pm
I mean, not even VCAA take that long to amend the exam and the solutions lol
Post by: paulsterio on November 04, 2012, 10:13:29 pm
Post by: luke_rulz94 on November 05, 2012, 12:04:31 am
Post by: pi on November 05, 2012, 10:53:19 am
is the 2012 vcaa exam 1 likely to be of the same difficulty as this, easier or harder ?
No-one knows haha
Post by: vcestudent94 on November 08, 2012, 04:17:53 pm
Post by: Crabwhacka on November 08, 2012, 09:01:08 pm
Post by: pi on November 08, 2012, 09:03:39 pm
But here's an idea. Why don't you guys put up what you had (just the answers, no need to waste too much time latexing up all the working) and we'll get a consensus on the correct answers in following discussion? :)
Post by: ZanyCat on November 08, 2012, 10:20:51 pm
So the format of the answers will look horrible, especially with fractions or squared's or cubed's involved.
And I haven't checked these on my calculator or anything, so highly likely there are errors everywhere.
1a) (8 - ky^3) / (3kxy^2 - 6y)
1b) -2/3
2) x = 5pi/6, 11pi/6, pi/2, 3pi/2
3) (sqrt(3) - 1) / 2
4a) two force vectors acting down (hard to show on one diagram I found) with magnitudes 2g and (2v^2) / g respectively
4b) show that question
5a) [1]: 2a + b + 3c = 0, [2]: a - 2b - c = 0
5b) a = b = -g (g is the parameter, gamma)
5c) x = -gi - gj + gk
6a) area = 2pi units^2 (by symmetry)
6b) volume = 3pi^2 units^3
7a) u = ( g - 8 ) / sqrt(3)g
7b) T = 4 newtons
8a/b)
You turn z + 1/z = k into a quadratic, then use the quadratic formula to solve for z.
Using the discriminant, we know that if k^2 - 4 >= 0 then z will lie on the real axis.
If not, then sqrt(k^2-4) will be an imaginary number.
Let z = x + yi, and x = k/2, y = sqrt(4-k^2)/2 (you have to times k^2-4 by -1 because you are after the imaginary PART of z).
Square both x and y, add them together and you get x^2 + y^2 = 1, showing that z either lies on the real axis or on the unit circle.
Part b is easy once you have done this. :)
9a) x= -4, x = 8, y = 0
9b) y = -10 / 3(x-8) + 7 / 3(x+4)
9c) a = 17/3
10a) z = 2 - sqrt(2)i, z = 2 + sqrt(2)i
10b) a = -3, b = 2
10c) z = -1
Post by: Phy124 on November 08, 2012, 11:00:58 pm
Note: I made these before I had studied anything spesh related, so they probably have errors. Looking through it now I'd say the largest chance for error would be 4c and 6bc as those were the first questions I ever did of that type :P
And yeah, sorry for not finding them earlier, it's a bit of a waste now :-[
edit: Disregard the last line in 1 b. (the answer is in the line above)
Post by: silverpixeli on August 18, 2013, 09:34:00 pm
4a) two force vectors acting down (hard to show on one diagram I found) with magnitudes 2g and (2v^2) / g respectively
Do we need to show magnitudes here? I labelled the forces 'air resistance' and 'weight force due to gravity', is that enough? Also, is there a proper way to show both forces? (I drew them kinda next to each other both acting down)
Post by: 09Ti08 on August 21, 2013, 06:44:09 pm
Post by: PB on September 07, 2013, 12:46:01 pm
Just a minor question. In the solutions, the denominator in 1a was factorised in one extra step. Is that a neccessity?
Thanks
Post by: Phy124 on September 07, 2013, 05:07:35 pm
Hey there,
Just a minor question. In the solutions, the denominator in 1a was factorised in one extra step. Is that a neccessity?
Thanks
Post by: PB on September 07, 2013, 05:34:36 pm