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VCE Stuff => VCE Mathematics => VCE Mathematics/Science/Technology => VCE Subjects + Help => VCE General & Further Mathematics => Topic started by: onur369 on November 03, 2011, 10:37:04 pm

Title: NUMBER PATTERNS 2010 EXAM 1 QUESTION 8
Post by: onur369 on November 03, 2011, 10:37:04 pm

WHY IS THE ANSWER A ? ???? PLEASE NEED HELP

Title: Re: NUMBER PATTERNS 2010 EXAM 1 QUESTION 8
Post by: Keo on November 03, 2011, 10:42:17 pm

Flip the graph around its an increasing trend, this also shows that r > 1, it can't be c because it curves again. It increases negatively instead of positively. Good luck tomorrow! :)

Title: Re: NUMBER PATTERNS 2010 EXAM 1 QUESTION 8
Post by: FromBaghdadWithLove on November 03, 2011, 10:44:52 pm

hey onur bro just do trial and error stuff on ur calculator, dont panic most questions are straight forward...

Title: Re: NUMBER PATTERNS 2010 EXAM 1 QUESTION 8
Post by: DannyN on November 03, 2011, 10:47:12 pm

remember the question doesnt state whether your initial value is postive or negatiuve, hopefully im explaining the right question doing this from memory, i remember every question in 08 onwards >.>

Title: Re: NUMBER PATTERNS 2010 EXAM 1 QUESTION 8
Post by: geoff_821 on November 03, 2011, 10:51:34 pm

r>1 however "a" may be negative

Let's suppose a = -2 and r =2

t1 = ar^(n-1)
t1 = -2
t2 = -4
t3 = -8

Hope this helps