ATAR Notes: Forum

VCE Stuff => VCE Mathematics => VCE Mathematics/Science/Technology => VCE Subjects + Help => VCE Mathematical Methods CAS => Topic started by: destain on March 14, 2012, 08:25:15 pm

Title: Inverse Help
Post by: destain on March 14, 2012, 08:25:15 pm

The question is to find the inverse of that function

y=x/x-2

Title: Re: Inverse Help
Post by: yawho on March 14, 2012, 08:56:41 pm

x=y/(y-2) is the inv of y=x/(x-2)

Title: Re: Inverse Help
Post by: destain on March 14, 2012, 08:59:27 pm

and you have to solve for y.....

Title: Re: Inverse Help
Post by: DazMan on March 14, 2012, 09:18:31 pm

x=y/(y-2)
x(y-2)=y
xy-2x=y
xy-y=2x
y(x-1)=2x
y=2x/(x-1)

that's what i got :)

Title: Re: Inverse Help
Post by: destain on March 14, 2012, 09:22:49 pm

thanks :)
this type of question always knew you ahd to take the y out like that but just couldnt get it 8)